\(\frac{1212}{3030}=\frac{2}{5}\)

\(\frac{32032}{48048}=\frac{2}{3}\)

\(\frac{456456}{234234}=\frac{76}{39}\)

\(\frac{1339}{1442}=\frac{13}{14}\)

#Châu's ngốc

1) Ta có :  \(\frac{49}{28}=\frac{49:7}{28:7}=\frac{7}{4}\)

             \(\frac{85}{51}=\frac{85:17}{51:17}=\frac{5}{3}\)

             \(\frac{64}{96}=\frac{64:32}{96:32}=\frac{2}{3}\)

             \(\frac{1212}{3030}=\frac{1212:606}{3030:606}=\frac{2}{5}\)

             \(\frac{32032}{48048}=\frac{32032:16016}{48048:16016}=\frac{2}{3}\)

             \(\frac{1339}{1442}=\frac{1339:103}{1442:103}=\frac{13}{14}\)    

Bài 1 :

49/28 =7/4    85/51=5/3   64/96=2/3     1212/3030=2/5     32032/48048=2/3   1339/1442=13/14

49/28=7/4

85/51=5/3

64/96=2/3

1212/3030=2/5

32032/48048=2/3

1339/1442=13/14

mk chắc chắn đúng 100% nên bạn k cho mk nha

chúc bạn học tốt

\(\frac{1339}{1442}=\frac{13}{14}\)

\(\frac{1212}{3030}=\frac{2}{5}\)

\(\frac{1339}{1442}=\frac{1300+39}{1400+42}=\frac{13\times100+13\times3}{14\times100+14\times3}=\frac{13\times\left(100+3\right)}{14\times\left(100+3\right)}=\frac{13}{14}\)\(\frac{13}{14}\)

\(\frac{1212}{3030}=\frac{1200+12}{3000+30}=\frac{12\times100+12}{30\times100+30}=\frac{12\times\left(100+1\right)}{30\times\left(100+1\right)}=\frac{12}{30}=\frac{2}{5}\)

\(\frac{1339}{1442}=\frac{13}{14}\)

\(\frac{1212}{3030}=\frac{2}{5}\)K.quả như vậy nha bn .

Nhớ tk mk nha

a: Các phân số tối giản là \(\dfrac{1}{3};\dfrac{4}{7};\dfrac{72}{73}\) vì ƯCLN(1;3)=1; ƯCLN(4;7)=1; ƯCLN(72;73)=1

b:

Các phân số rút gọn được là

 \(\dfrac{8}{12}=\dfrac{8:4}{12:4}=\dfrac{2}{3}\)

\(\dfrac{30}{36}=\dfrac{30:6}{36:6}=\dfrac{5}{6}\)

Ta có : A = \(\dfrac{7}{4}.\left(\dfrac{333}{1212}+\dfrac{3333}{2020}+\dfrac{3333}{3030}+\dfrac{3333}{4242}\right)\)

\(\Rightarrow A=\dfrac{7}{4}.\left(\dfrac{11}{4}+\dfrac{33}{20}+\dfrac{11}{10}+\dfrac{11}{14}\right)\)

\(\Rightarrow A=\dfrac{7}{4}.\dfrac{44}{7}\)

\(\Rightarrow A=11\)

Vậy A = 11

A=7/4(33/12+33/20+33/30+33/42)

=7/4.33.(1/12+1/20+1/30+1/42)

=7/4.33.4/21

=11

1: B là số nguyên

=>n-3 thuộc {1;-1;5;-5}

=>n thuộc {4;2;8;-2}

3:

a: -72/90=-4/5
b: 25*11/22*35

\(=\dfrac{25}{35}\cdot\dfrac{11}{22}=\dfrac{5}{7}\cdot\dfrac{1}{2}=\dfrac{5}{14}\)

c: \(\dfrac{6\cdot9-2\cdot17}{63\cdot3-119}=\dfrac{54-34}{189-119}=\dfrac{20}{70}=\dfrac{2}{7}\)

\(\dfrac{60}{72}=\dfrac{60:12}{72:12}=\dfrac{5}{6}\\ \dfrac{70}{95}=\dfrac{70:5}{95:5}=\dfrac{14}{19}\\ \dfrac{150}{360}=\dfrac{150:30}{360:30}=\dfrac{5}{12}\)

\(\dfrac{60}{72}=\dfrac{5}{6}\)

\(\dfrac{70}{95}=\dfrac{14}{19}\)

\(\dfrac{150}{360}=\dfrac{5}{12}\)

\(3;\dfrac{-1}{5};\dfrac{-1}{3}\)

\(\dfrac{-12}{-4}=\dfrac{-3}{-1}\)

\(\dfrac{7}{-35}=\dfrac{1}{-5}\)

\(\dfrac{-9}{27}=\dfrac{-1}{3}\)