2⁴ - 2 . (15 - x) = 10

16 - 2 . (15 - x) = 10

2 . (15 - x) = 16 - 10

2 . (15 - x) = 6

15 - x = 6 : 2

15 - x = 3

x = 15 - 3

x = 12

Chúc bạn học tốt!! ^^

Ta có: \(2^4-2\left(15-x\right)=10\)

\(\Leftrightarrow2\left(15-x\right)=6\)

\(\Leftrightarrow15-x=3\)

hay x=12

4(x - 5) - 2³ = 2⁴ . 3

4(x - 5) - 8   = 48

4(x - 5)        = 48 + 8 

4(x - 5)         = 56

   x - 5          = 56 : 4

   x - 5          = 14

   x                = 14 + 5

   x                 = 19

Vậy x = 19

4( x - 5 ) - 2^3 = 2^4 . 3

4( x - 5 ) - 8 = 16 . 3

4( x - 5 ) - 8 = 48

4( x - 5 ) = 48 + 8

4( x - 5 ) = 56

x - 5 = 56 : 4

x - 5 = 14

x = 14 + 5

x = 19

Ta có: \(4\left(x-5\right)-2^3=2^4\cdot3\)

\(\Leftrightarrow4\left(x-5\right)=56\)

\(\Leftrightarrow x-5=14\)

hay x=19

`4(x-5)-2^3=2^{4}.3`

`=>4(x-5)-8=16.3=48`

`=>4(x-5)=48+8=56`

`=>x-5=56:4=14`

`=>x=19`

Vậy `x=19`

4.(x-5)-2³=2⁴.3

4.(x-5)-8=16.3

4.(x-5)-8=48

4.(x-5)=48+8

4.(x-5)=56

x-5=56:4

x-5=14

x=14+5

x=19

     4 (x - 5) - 2³ = 2⁴*3

=> 4 (x - 5) - 2³ = 16*3 = 48

=> 4 (x - 5) = 48 + 2³ = 48 + 8 = 56

=> x - 5 = 56/4 = 14

=> x = 14 + 5 = 19

 Vậy x = 19

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vi 1 nhan voi so nao cung = chinh no

de: x^15=x^2

nen x=1

1hoặc 0

1hoặc 0

Điều kiện: \(x\ge74\)

\(GT\Rightarrow\left\{{}\begin{matrix}x+15=m^2\left(m\in N\right)\\x-74=n^2\left(n\in N\right)\end{matrix}\right.\)

\(\Rightarrow m^2-15=n^2+74\)

\(\Leftrightarrow m^2-n^2=89\Leftrightarrow\left(m+n\right)\left(m-n\right)=89\)

Do \(m,n\in N\) và \(89=1\cdot89\) nên ta có:

Trường hợp 1: \(\left\{{}\begin{matrix}m+n=1\\m-n=89\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}m=45\\n=-44\end{matrix}\right.\) (loại).

Trường hợp 2: \(\left\{{}\begin{matrix}m+n=89\\m-n=1\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}m=45\\n=44\end{matrix}\right.\) (nhận).

\(\Rightarrow x=m^2-15=45^2-15=2010\left(TM\right)\)

Vậy: \(x=2010\).

=>7/15<x<20/15=4/3

=>x=1

Ta có : 4/15 : 4/7< x > 2/5 x 10/3                                                                                           

Nên:  7/15   < x >     4/3                                                                                                       

Vậy số tự nhiên x là 1

\(\dfrac{4}{15}:\dfrac{4}{7}< x< \dfrac{2}{5}\times\dfrac{10}{3}\\ \dfrac{7}{15}< x< \dfrac{4}{3}\\ x=1\)

a -10

b-6

c27

a) = -10

b) = -6

c) = 27

đó