HOC24
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Bài học
Phân tích đa thức thành nhân tử x⁴ +x³ +2x² +x +1 Tìm x biết 4x² -3x -1 =0
a. (-2x+3)² – (3y)²
b. (-2x)² – (y–x)²
P = x² - 2x + 5 = x² - 2x + 1 + 4
= ( x - 2 )² + 1 ≥ 1 ( vì ( x - 2 )² ≥ 0 )
Dấu " = " xảy ra khi x - 2 = 0 => x = 2
Vậy GTNN của P là 1 khi x = 2
4.A
5.D
(5x - 2)² - (2x - 1)²
= (5x - 2 + 2x - 1) (5x - 2 - 2x + 1)
= (7x - 3) (3x - 1)
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D
b) ( x - √7y )² = x² - 2x.7y + ( √7y )²
= x² - 14xy + 7y
4 (x - 5) - 2³ = 2⁴*3
=> 4 (x - 5) - 2³ = 16*3 = 48
=> 4 (x - 5) = 48 + 2³ = 48 + 8 = 56
=> x - 5 = 56/4 = 14
=> x = 14 + 5 = 19
Vậy x = 19