\(x+0,25=\dfrac{18}{5}+\dfrac{43}{4}\)
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Câu 1: Tìm x, biết:a)x^2-dfrac{16}{25}0 b)dfrac{2}{5}-left|dfrac{1}{2}-xright|6C2.Tính giá của biểu thức: a)A1dfrac{5}{13}-0,25-left(2dfrac{5}{9}+dfrac{18}{13}-dfrac{1}{4}right)b)dfrac{dfrac{3}{5}.7^2-3.5^6+dfrac{3}{5}.3^9}{dfrac{3}{4}.7^2-dfrac{3}{4}.5^7+dfrac{3}{4}.3^9}
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Câu 1: Tìm x, biết:
a)\(x^2-\dfrac{16}{25}=0\) b)\(\dfrac{2}{5}-\left|\dfrac{1}{2}-x\right|=6\)
C2.Tính giá của biểu thức:
a)\(A=1\dfrac{5}{13}-0,25-\left(2\dfrac{5}{9}+\dfrac{18}{13}-\dfrac{1}{4}\right)\)
b)\(\dfrac{\dfrac{3}{5}.7^2-3.5^6+\dfrac{3}{5}.3^9}{\dfrac{3}{4}.7^2-\dfrac{3}{4}.5^7+\dfrac{3}{4}.3^9}\)
a)
x^2-16/25=0
x^2-4^2/5^2=0
=>x-4/5=0
x=0+4/5
x=0/5
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1. Giá trị của x trong : x : \(\dfrac{2}{9}\) = 18 là:
a) 2 b) \(\dfrac{162}{2}\) c) 4 d) \(\dfrac{18}{9}\)
2. \(\dfrac{3}{5}\) của 4 tấn là:
a) 2400kg b) 240kg c) 24kg d) 24 000kg
3. 25ha = ........km2
a) 0,0025 b) 0,025 c) 0,25 d) 2,5
1.
x : \(\dfrac{2}{9}=18\)
x = 18 x \(\dfrac{2}{9}\)
x = 4
\(\Rightarrow\) Chọn C
2.
\(\dfrac{3}{5}\) của 4 tấn:
Đổi: 4 tấn = 4000 kg.
\(\dfrac{3}{5}\) của 4000 kg là:
4000 x \(\dfrac{3}{5}\) = 2400 kg
\(\Rightarrow\) Chọn A
3. 25ha = ... km2
Ta có: 1ha = 0,01 km2
\(\Rightarrow\) 25ha = 0,01 x 25 = 0,25 km2
\(\Rightarrow\) Chọn C
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a) dfrac{15}{11} - (dfrac{5}{7} - dfrac{18}{11}) + dfrac{27}{7}
b) dfrac{39}{5}+ (dfrac{9}{4} - dfrac{9}{5}) - (dfrac{5}{4} + 1,2)
c) -1,2 - 0,8 + 0,25 + 5,75 - 2022
d) 0,1 + dfrac{16}{9} + 5,1 + dfrac{-20}{9}
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a) \(\dfrac{15}{11}\) - (\(\dfrac{5}{7}\) - \(\dfrac{18}{11}\)) + \(\dfrac{27}{7}\)
b) \(\dfrac{39}{5}\)+ (\(\dfrac{9}{4}\) - \(\dfrac{9}{5}\)) - (\(\dfrac{5}{4}\) + 1,2)
c) -1,2 - 0,8 + 0,25 + 5,75 - 2022
d) 0,1 + \(\dfrac{16}{9}\) + 5,1 + \(\dfrac{-20}{9}\)
a) 15/11 - (5/7 - 18/11) + 27/7
= 15/11 - 5/7 + 18/11 + 27/7
= (15/11 + 18/11) + (-5/7 + 27/7)
= 3 + 22/7
= 43/7
b) 39/5 + (9/4 - 9/5) - (5/4 + 1,2)
= 39/5 + 9/4 - 9/5 - 5/4 - 6/5
= (39/5 - 9/5 - 6/5) + (9/4 - 5/4)
= 24/5 + 1
= 29/5
c) -1,2 - 0,8 + 0,25 + 5,75 - 2022
= (-1,2 - 0,8) + (0,25 + 5,76) - 2022
= -2 + 6 - 2022
= 4 - 2022
= -2018
d) 0,1 + 16/9 + 5,1 + (-20/9)
= (0,1 + 5,1) + (16/9 - 20/9)
= 5,2 - 4/9
= 419/90
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a) \(\dfrac{15}{11}-\left(\dfrac{5}{7}-\dfrac{18}{11}\right)+\dfrac{27}{7}=\dfrac{22}{7}+3=\dfrac{43}{77}\)
b) \(\dfrac{39}{5}+\left(\dfrac{9}{4}-\dfrac{9}{5}\right)-\left(\dfrac{5}{4}+\dfrac{6}{5}\right)=\dfrac{24}{5}+1=\dfrac{29}{5}\)
c) \(-1,2-0,8+0,25+5,75-2022=-2+6-2022=-2018\)
d) \(0,1+\dfrac{16}{9}+5,1+\dfrac{-20}{9}=\dfrac{26}{5}-\dfrac{4}{9}=\dfrac{214}{45}\)
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BT2: Tính nhanh:
5) \(\dfrac{15}{7}\left(\dfrac{1}{5}-\dfrac{46}{45}\right)+\dfrac{46}{45}\left(\dfrac{15}{7}-\dfrac{45}{46}\right)\)
6) \(\dfrac{43}{47}\left(\dfrac{18}{37}+\dfrac{47}{43}\right)-\dfrac{18}{37}\left(\dfrac{43}{47}+\dfrac{37}{36}\right)\)
1/Ta co :
\(\dfrac{15}{7}.\left(\dfrac{1}{5}-\dfrac{46}{45}\right)+\dfrac{46}{45}.\left(\dfrac{15}{7}-\dfrac{45}{46}\right)\)
=\(\dfrac{15}{7}.\dfrac{1}{5}-\dfrac{15}{7}.\dfrac{46}{45}+\dfrac{46}{45}.\dfrac{15}{7}-\dfrac{46}{45}.\dfrac{45}{46}\)
=\(\dfrac{15}{7}.\left(\dfrac{1}{5}-\dfrac{46}{45}+\dfrac{46}{45}\right)-1\)
=\(\dfrac{15}{7}.\dfrac{1}{5}-1\)
=\(\dfrac{3}{7}-1=\dfrac{-4}{7}\)
2/Ta co
\(\dfrac{43}{47}.\left(\dfrac{18}{37}+\dfrac{47}{43}\right)-\dfrac{18}{3}.\left(\dfrac{43}{47}+\dfrac{37}{36}\right)\)
=\(\dfrac{43}{47}.\dfrac{18}{37}+\dfrac{43}{47}.\dfrac{47}{43}-\dfrac{18}{37}.\dfrac{43}{47}+\dfrac{18}{37}.\dfrac{37}{36}\)
=\(\dfrac{18}{37}.\left(\dfrac{43}{37}-\dfrac{43}{37}+\dfrac{37}{36}\right)+1\)
=\(\dfrac{18}{37}.\dfrac{37}{36}+1\)
=\(\dfrac{1}{2}+1=\dfrac{3}{2}\)
tick cho mk nha
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28 tháng 1 2022 lúc 21:48
Tính giá trị biểu thức:e,dfrac{18}{37}+dfrac{8}{24}+dfrac{19}{37}-1dfrac{23}{24}+dfrac{2}{3}f,left(-2right)^3.left(dfrac{3}{4}-0,25right):left(2dfrac{1}{4}-1dfrac{1}{6}right)g,left(dfrac{2}{5}right)^2+5dfrac{1}{2}.left(4,5-2right)+dfrac{2^3}{left(-4right)}h,dfrac{4}{9}.19dfrac{1}{3}-dfrac{4}{9}.39dfrac{1}{3}i,left(-dfrac{1}{2}right)^2:dfrac{1}{4}-2left(-dfrac{1}{2}right)^2j,125%.left(dfrac{-1}{2}right)^2:left(1dfrac{5}{16}-1,5right)+2008^0k,left(-2right)^3.dfrac{-1}{24}+left(dfrac{4}{3}-1dfrac{5...
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Tính giá trị biểu thức:
\(e,\dfrac{18}{37}+\dfrac{8}{24}+\dfrac{19}{37}-1\dfrac{23}{24}+\dfrac{2}{3}\)
\(f,\left(-2\right)^3.\left(\dfrac{3}{4}-0,25\right):\left(2\dfrac{1}{4}-1\dfrac{1}{6}\right)\)
\(g,\left(\dfrac{2}{5}\right)^2+5\dfrac{1}{2}.\left(4,5-2\right)+\dfrac{2^3}{\left(-4\right)}\)
\(h,\dfrac{4}{9}.19\dfrac{1}{3}-\dfrac{4}{9}.39\dfrac{1}{3}\)
\(i,\left(-\dfrac{1}{2}\right)^2:\dfrac{1}{4}-2\left(-\dfrac{1}{2}\right)^2\)
\(j,125\%.\left(\dfrac{-1}{2}\right)^2:\left(1\dfrac{5}{16}-1,5\right)+2008^0\)
\(k,\left(-2\right)^3.\dfrac{-1}{24}+\left(\dfrac{4}{3}-1\dfrac{5}{6}\right):\dfrac{5}{12}\)
e: \(=\left(\dfrac{18}{37}+\dfrac{19}{37}\right)+\left(\dfrac{8}{24}+\dfrac{2}{3}\right)-\dfrac{47}{24}=2-\dfrac{47}{24}=\dfrac{1}{24}\)
f: \(=-8\cdot\dfrac{1}{2}:\left(\dfrac{9}{4}-\dfrac{7}{6}\right)\)
\(=-4:\dfrac{13}{12}=\dfrac{-48}{13}\)
g: \(=\dfrac{4}{25}+\dfrac{11}{2}\cdot\dfrac{5}{2}-\dfrac{8}{4}=\dfrac{4}{25}+\dfrac{55}{4}-2=\dfrac{1191}{100}\)
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x + 0,25 = 18/5 + 43/4
x+0,25=3,6+10,75
x+0,25=14,35
x+0,25=14,35-0,25
x+0,25=14,1
x =14,1-0,25
x=13,85
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ta có
x + 0,25 = 43/4 - 18/5
=> x + 1/4 = 143/20
=> x = 143/20 - 1/4
=> x = 25/4
vậy x = 25/4
15 tháng 5 2023 lúc 18:33
4 x 0,25 x 5 x \(\dfrac{1}{5}\) x 2 x \(\dfrac{1}{2}\)
`4 xx 0,25 xx 5 xx 1/5 xx 2 xx 1/2`
`=(4xx0,25) xx(5xx1/5) xx (2xx1/2)`
`= 1 xx 5/5 xx 2/2`
`= 1 xx 1 xx 1`
`=1`
`@ M``i``n`
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Tìm x
\(\dfrac{3}{4}x+\dfrac{-1}{2}=\dfrac{-13}{8}\)
\(\left|x\right|+0,25=1,75.3\)
\(\dfrac{2x-1}{3}=\dfrac{-5}{0,6}\)
a, \(\dfrac{3}{4}x=-\dfrac{9}{8}\)
x= \(-\dfrac{3}{2}\)
b, |x| + 0,25= 5,25
|x | = 5
=> x\(\in\){ +- 5}
Ko chắc đúng, kiểm tra trc khi làm
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\(\dfrac{2x-1}{3}=\dfrac{-5}{0.6}\)
\(\Leftrightarrow2x-1=-25\)
hay x=-12
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9 x (\(\dfrac{-1}{3}\))3+\(\dfrac{1}{3}\): 0,25 - \(5\dfrac{3}{4}\)
\(9\times\left(\dfrac{-1}{3}\right)^3+\dfrac{1}{3}:0,25-5\dfrac{3}{4}=\dfrac{9}{1}\times\left(\dfrac{-1}{27}\right)+\dfrac{1}{3}:\dfrac{1}{4}-\dfrac{23}{4}\)
\(=\left(\dfrac{-9}{27}\right)+\dfrac{4}{3}-\dfrac{23}{4}=\left(\dfrac{-1}{3}\right)+\dfrac{4}{3}-\dfrac{23}{4}=\dfrac{3}{3}-\dfrac{23}{4}=1-\dfrac{23}{4}=\dfrac{4}{4}-\dfrac{23}{4}=\dfrac{-19}{4}\)
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