a) 9 . 9 . 9 . 9 . 9 = 9⁵

b) 10 . 10 . 10 . 10 = \(10^4\)

c) 5.5.5.25=5.5.5.5.5=\(5^5\)      

d) a.a.a.a.a.a=\(a^6\)

a) 9.9.9.9.9=9⁵                   b) 10. 10. 10. 10=10⁴

c) 5.5.5.25=5.5.5.5.5=5⁵                      d) a.a.a.a.a.a=a⁶

a: \(8=2^3\)

\(125=5^3\)

\(27=3^3\)

\(64=8^2\)

\(81=9^2\)

\(1000=10^3\)

\(10000000=10^7\)

1000..000=10^k

b: \(7\cdot7\cdot7=7^3\)

\(7\cdot8\cdot7\cdot25=7^2\cdot200=70^2\cdot2^2\)

a) \(2^3;5^3;3^3;4^3;3^4;5^4;10^3;10^7;10^k3^4\)

\(a,=5^{40}\cdot5^{12}=5^{52}\\ b,=x^{7+4+3}=x^{14}\\ c,=\left(3\cdot4\right)^6=12^6\)

a) \(25^{20}.125^4=\left(5^2\right)^{20}.\left(5^3\right)^4=5^{40}.5^{12}=5^{40+12}=5^{52}\)

b) \(x^7.x^4.x^3=x^{7+4+3}=x^{14}\)

c) \(3^6.4^6=\left(3.4\right)^6=12^6\)

viết các tích sau dưới dạng 1 luỹ thừa:

a(    25^20 . 125^4 = (5²)²⁰ . (5³)⁴ = 5⁴⁰ . 5¹² = 5⁵²

b(     x^7 . x^4 . x^3 = x⁷⁺⁴⁺³ = x¹⁴

c(     3^6 . 4^6 = (3.4)⁶=12^6
??

a) 2.2.2.3.3 = 2³ . 3²

b) x4.x = x² . 4

a) 2.2.2.3.3 = 2³ . 3²

b) x4.x = x² . 4

a) 2.2.2.3.3 = 2³ . 3²

b) x4.x = x² . 4

a) 2³.3²

b) x²4¹

a) 7⁶:7⁴ = 7⁶⁻⁴ = 7²

b) 1091¹⁰⁰: 1091¹⁰⁰ = 1091^100−100  = 1091⁰

a) 7⁶ : 7⁴=7²                          b) 1 091¹⁰⁰ : 1 091¹⁰⁰=1

a) 5³.5⁷ = 5³⁺⁷ = 5¹⁰

b) 2⁴.2⁵.2⁹=2⁴⁺⁵⁺⁹  = 2¹⁸

c) 10².10⁴.10⁶.10⁸ = 10^2+4+6+8 = 10²⁰.

a) 5³.5⁷=5¹⁰               b) 2⁴ . 2⁸. 2⁹=2¹⁸         c) 10². 10⁴. 10⁶. 10⁸=10²⁰

\(\dfrac{-5}{6}=\dfrac{-5\times4}{6\times4}=\dfrac{-20}{24}\)

\(\dfrac{3}{-8}=\dfrac{3\times\left(-3\right)}{-8\times\left(-3\right)}=\dfrac{-9}{24}\)

\(2=\dfrac{48}{24}\)

\(\dfrac{-25}{100}=\dfrac{-1}{4}=\dfrac{-1\times6}{4\times6}=\dfrac{-6}{24}\)

\(\dfrac{72}{108}=\dfrac{2}{3}=\dfrac{2\times8}{3\times8}=\dfrac{16}{24}\)