\(\left(-3\right)^2.\left(-5\right)-\left[\left(-95\right)+\left(13+7\right)^2\right]\)

\(=9.\left(-5\right)-\left(-95+20^2\right)\)

\(=-45+95-400\)

\(=50-400\)

\(=-350\)

          \(\frac{5}{9}.\frac{-4}{17}+\frac{-13}{17}.\frac{5}{9}+2\frac{4}{9}\)

\(=\)\(\frac{5}{9}.\left(\frac{-4}{17}+\frac{-13}{17}\right)+2\frac{4}{9}\)

\(=\frac{5}{9}.\left(-1\right)+\frac{22}{9}\)

\(=\frac{5}{9}+\frac{22}{9}\)

\(=3\)

a,714+382+286+318

\(=\left(714+286\right)+\left(382+318\right)\)

\(=1000+700\)

= \(1700\)

b,18.73+15.18+12.18

\(=18.\left(73+15+12\right)\)

\(=18.100\)

\(=1800\)

c,(37+63) : {250:[450-(4.5^3-2^2.25)]}

\(=100:\left\{250:\left[450-\left(2^2.125-2^2.25\right)\right]\right\}\)

\(=100:\left\{250:\left[450-\left(2^2.\left(125-25\right)\right)\right]\right\}\)

\(=100:\left\{250:\left[450-400\right]\right\}\)

\(=100:\left\{250:50\right\}\)

\(=100:5\\ =20\)

CHÚC BANJ HỌC TỐT!!

a) 714+382+286+318

=(714+286)+(382+318)

=1000+700

=1700

b) 18.73+15.18+12.18

=18.(73+15+12)

=18.100

=1800

c) (37+63):{250:[450-(4.5^3-2^2.25)]}

=100:{250:[450-(4.125-4.25)]}

=100:{250:[450-4.(125-25)]}

=100:{250:[450-4.100]}

=100:{250:[450-400]}

=100:{250:50}

=100:5

=20

-Chúc bạn học tốt-

19.64 + 76.34

= 19.64 + 19.4.34

= 19.64 + 19.136

= 19.(64+136)

= 19.200

= 3800

Đáp án A

cos 119 0 + i sin 119 0 = sin − 29 0 + i cos − 29 0 ;

1 2 cos 119 0 + i sin 119 0 8 cos 59 0 + i sin 59 0 = 2 cos − 29 0 + i sin − 29 0 cos 59 0 + i sin 59 0 = 2 cos 30 0 + i sin 30 0 = 3 + i .

hộ mik vs

Đáp số là 26461,26922 em nhé

bạn có thể vt rõ câu hỏi ra đc ko

 (x²y-2xy+2y)(x-2y)  = x³y-2x²y²-2x²y+4xy²+2xy-4y²

Lời giải:

\(17x^2-2x^3-3x^4-4x-5=-3x^4-2x^3+17x^2-4x-5\)

\(=-3x^2(x^2+x-5)+x^3+2x^2-4x-5\)

\(=-3x^2(x^2+x-5)+x(x^2+x-5)+(x^2+x-5)\)

\(=(x^2+x-5)(-3x^2+x+1)\)

Do đó: $(17x^2-2x^3-3x^4-4x-5):(x^2+x-5)=(-3x^2+x+1)$

\(\frac{2^5.6^3}{8^2.9^2}\) = \(\frac{2^5.2^3.3^3}{2^6.3^4}\) = \(\frac{2^8.3^3}{2^6.3^4}\) = \(\frac{2^2}{3}\) = \(\frac{4}{3}\)

bâm máy tính đi

\(=\frac{6912}{5184}=\frac{4}{3}\)