a) Ư(36) = {1; 2; 3; 4; 6; 9; 12; 18; 36}

Ư(45) = {1; 3; 5; 9; 15; 45}

=> ƯC(36; 45) = {1; 3; 9}.

b) Ư(18) = {1; 2; 3; 6; 9; 18}

Ư(36) = {1; 2; 3; 4; 6; 9; 12; 18; 36}

Ư(45) = {1; 3; 5; 9; 15; 45}

=> ƯC(18, 36, 45) = {1; 3; 9}.

Ư(36) = {1; 2; 3; 4; 6; 9; 12; 18; 36}

Ư(45) = {1; 3; 5; 9; 15; 45}

=> ƯC(36; 45) = {1; 3; 9}.

b) Ư(18) = {1; 2; 3; 6; 9; 18}

Ư(36) = {1; 2; 3; 4; 6; 9; 12; 18; 36}

Ư(45) = {1; 3; 5; 9; 15; 45}

=> ƯC(18, 36, 45) = {1; 3; 9}.

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a) Ư(30) = {1; 2; 3; 5; 6; 10; 15; 30}

    Ư(45) = {1; 3; 5; 9; 15; 45}

Vậy ƯC(30, 45) = {1; 3; 5; 15}

b) Ư(42) = {1; 2; 3; 6; 7; 14; 21; 42}

    Ư(70) = {1; 2; 5; 7; 10; 14; 35; 70}

Vậy ƯC(42, 70) = {1; 2; 7; 14}.

a) ƯC(36;48)={1;2;3;4;6;12}

b) ƯC(45;75;105)={1;3;5;15}

c) ƯC(14;33)=1

a. ƯC(36;48) = {1;2;3;4;6;12}

b. ƯC(45;75;105) = {1;3;5;15}

c. ƯC(14;33) = 1

a: \(ƯC\left(36;48\right)=\left\{1;2;3;4;6;12\right\}\)

b: \(ƯC\left(45;75;105\right)=\left\{1;3;5;15\right\}\)

c: \(ƯC\left(14;33\right)=\left\{1\right\}\)

\(a,ƯCLN\left(540,168\right)=12\\ \RightarrowƯC\left(540,168\right)=Ư\left(12\right)=\left\{-12;-6;-4;-3;-2;-1;1;2;3;4;6;12\right\}\\ b,ƯCLN\left(735,350\right)=35\\ \RightarrowƯC\left(735,350\right)=Ư\left(35\right)=\left\{-35;-7;-5;-1;1;5;7;35\right\}\)

\(a.540=2^2.3^3.5\)

\(168=2^3.3.7\)

\(ƯCLN\left(540;168\right)=2^2.3=12\)

\(ƯC\left(540;168\right)=\left\{12;24;36;...\right\}\)

\(b.735=3.5.7^2\)

\(350=2.5^2.7\)

\(ƯCLN\left(735;350\right)=5.7=35\)

\(ƯC\left(735;350\right)=\left\{35;70;105;...\right\}\)

\(a,ƯC\left(30,45\right)=Ư\left(15\right)=\left\{1;3;5;15\right\}\\ b,ƯC\left(42,77\right)=Ư\left(7\right)=\left\{1;7\right\}\)

a) 54 và 126 ƯC :1,2,6,18,9

b) 154 và 264 ƯC :2,11,1

c) 1264 và 384 ƯC :2,4,8,16,1

a) 72 và 60.     ===> Lưu ý: VD: 2^2 = 2 mũ 2

72 = 3^2.2^3

60 = 5.3.2^2

ƯCLN (72,60) = 3.2^2 = 12

ƯC = Ư(12) = {1,2,3,4,6,12}

b) 90; 180 và 315

90 = 5.3^2.2

180 = 5.3^2.2^2

315 = 5.3^2.7

ƯCLN  (90,180,315) = 5.3^2 = 125

ƯC = Ư(125) = { 1,125 }

a: UCLN(16;42)=2

UC(16;42)={1;2}

b: UCLN(16;42;86)=2

UC(16;42;86)={1;2}

c: UCLN(25;75)=25

UC(25;75)={1;5;25}

d: UCLN(25;55;75)=5

UC(25;55;75)={1;5}

a: UCLN(16;42)=2

UC(16;42)={1;2}

b: UCLN(16;42;86)=2

UC(16;42;86)={1;2}

c: UCLN(25;75)=25

UC(25;75)={1;5;25}

d: UCLN(25;55;75)=5

UC(25;55;75)={1;5}