\(=\dfrac{2x-3y}{y\left(x-y\right)}+\dfrac{1}{x-y}=\dfrac{2x-3y+y}{y\left(x-y\right)}=\dfrac{2x-2y}{y\left(x-y\right)}=\dfrac{2}{y}\)

\(\dfrac{2x-3y}{xy-y^2}+\dfrac{1}{x-y}=\dfrac{2x-3y}{y\left(x-y\right)}+\dfrac{1}{x-y}=\dfrac{2x-3y+y}{y\left(x-y\right)}=\dfrac{2x-2y}{y\left(x-y\right)}=\dfrac{2}{y}.\)

\(a,\dfrac{x}{x+3}+\dfrac{2-x}{x+3}\\ =\dfrac{x+2-x}{x+3}\\ =\dfrac{2}{x+3}\\b,\dfrac{x^2y}{x-y}-\dfrac{xy^2}{x-y}\\ =\dfrac{x^2y-xy^2}{x-y}\\ =\dfrac{xy\left(x-y\right)}{x-y}\\ =xy\\ c,\dfrac{2x}{2x-y}+\dfrac{y}{y-2x}\\=\dfrac{2x}{2x-y}-\dfrac{y}{2x-y}\\ =\dfrac{2x-y}{2x-y}\\ =1 \)

`a, x/(x+3) + (2-x)/(x+3) = (x+2-x)/(x+3) = 2/(x+3)`

`b, (x^2y)/(x-y) - (xy^2)/(x-y) = (x^2y-xy^2)/(x-y) = (xy(x-y))/(x-y)= xy`

`c, (2x)/(2x-y) - (y)/(2x-y)`

`= (2x-y)/(2x-y) = 1`

Ta có:

+ ⇒ MTC = 2x( x + 3 )

Khi đó ta có:

\(=\frac{16+x}{x^2-2x}-\frac{18}{x^2-2x}\)

\(=\frac{16+x-18}{x\left(x-2\right)}\)

\(=\frac{-2+x}{x\left(x-2\right)}\)

a) \(\frac{16+x}{x^2-2x}+\frac{18}{2x-x^2}=\frac{16+x-18}{x^2-2x}=\frac{x-2}{x\left(x-2\right)}=\frac{1}{x}\)

b) \(\frac{2y}{2x^2-xy}+\frac{4x}{xy-2x^2}=\frac{2y-4x}{2x^2-xy}=\frac{-2\left(2x-y\right)}{x\left(2x-y\right)}=\frac{-2}{x}\)

c) \(\frac{4-x^2}{x-3}+\frac{2x-2x^2}{3-x}+\frac{5-4x}{x-3}=\frac{4-x^2+2x^2-2x+5-4x}{x-3}=\frac{x^2-6x+9}{x-3}=\frac{\left(x-3\right)^2}{x-3}=x-3\)

a)

\(\frac{16+x}{x^2-2x}+\frac{18}{2x-x^2}=\frac{16+x}{x^2-2x}-\frac{18}{x^2-2x}\)

\(=\frac{16+x-18}{x\left(x-2\right)}=\frac{x-2}{x\left(x-2\right)}=\frac{1}{x}\)

b)   \(\frac{2y}{2x^2-xy}+\frac{4x}{xy-2x^2}=\frac{2y}{2x^2-xy}-\frac{4x}{2x^2-xy}\)

\(=\frac{2y-4x}{x\left(2x-y\right)}=\frac{2\left(y-2x\right)}{x\left(2x-y\right)}=-\frac{2}{x}\)

c)  \(\frac{4-x^2}{x-3}+\frac{2x-2x^2}{3-x}+\frac{5-4x}{x-3}\)\(=\frac{4-x^2}{x-3}-\frac{2x-2x^2}{x-3}+\frac{5-4x}{x-3}\)

\(=\frac{4-x^2-2x+2x^2+5-4x}{x-3}\)\(=\frac{x^2-6x+9}{x-3}=\frac{\left(x-3\right)^2}{x-3}=x-3\)

Ta có:

+ ⇒ MTC = 2x( x + 3 )

Khi đó ta có:

a,$\frac{5}{2x^2y}+\frac{3}{5xy^2}+\frac{x}{y^3}$52x2y +35xy2 +xy3 

b,\(\frac{x+1}{2x+6}+\frac{2x+3}{x\left(x+3\right)}\)

Cộng vào sẽ ra kết quả nha !!! 

We are one_I Love you làm j ngu người quá 

\(\frac{2x}{x^2+4x+4}+\frac{x+1}{x+2}+\frac{2-x}{x^2+4x+4}\)

\(=\frac{2x}{\left(x+2\right)^2}+\frac{\left(x+1\right)\left(x+2\right)}{\left(x+2\right)^2}+\frac{2-x}{\left(x+2\right)^2}\)

\(=\frac{2x+x^2+3x+2+2-x}{\left(x+2\right)^2}\)

\(=\frac{x^2+4x+4}{\left(x+2\right)^2}\)

\(=\frac{\left(x+2\right)^2}{\left(x+2\right)^2}\)

\(=1\)

Ta có:

+ ⇒ MTC = - ( x - 1 )( x2 + x + 1 )

Khi đó ta có:

Ta có:

+ ⇒  M T C = - ( x - 1 ) ( x 2 + x + 1 )

Khi đó ta có: