a) \(2+2+2+2+2=2\times5=10\)

\(2\times5=10\)

\(5+5=2\times5=10\)

\(5\times2=10\)

b) \(3\times5=3+3+3+3+3=15\)

\(5\times3=5+5+5=15\)

\(3\times5=5+5+5=15\)

\(5\times3=3+3+3+3+3=15\)

a) 2 + 2 + 2 + 2 + 2 = 10
    2 x 5 = 10
    5 + 5 = 10
    5 x 2 = 10
b) 3 x 5 = 3 + 3 + 3 + 3 + 3 = 15
    5 x 3 = 5 + 5 + 5 = 15
    3 x 5 = 15
    5 x 3 = 15

Bài 1

a) 3 2/5 - 1/2

= 17/5 - 1/2

= 34/10 - 5/10

= 29/10

b) 4/5 + 1/5 × 3/4

= 4/5 + 3/20

= 16/20 + 3/20

= 19/20

c) 3 1/2 × 1 1/7

= 7/2 × 8/7

= 4

d) 4 1/6 : 2 1/3

= 25/6 : 7/3

= 25/14

Bài 2

a) 3 × 1/2 + 1/4 × 1/3

= 3/2 + 1/12

= 18/12 + 1/12

= 19/12

b) 1 4/5 - 2/3 : 2 1/3

= 9/5 - 2/3 : 7/3

= 9/5 - 2/7

= 63/35 - 10/35

= 53/35

Bài 1

a) 3 2/5 - 1/2

= 17/5 - 1/2

= 34/10 - 5/10

= 29/10

b) 4/5 + 1/5 × 3/4

= 4/5 + 3/20

= 16/20 + 3/20

= 19/20

c) 3 1/2 × 1 1/7

= 7/2 × 8/7

= 4

d) 4 1/6 : 2 1/3

= 25/6 : 7/3

= 25/14

bủh

e tách ra nhé.☘

;))

a: =>x-2/5=3/4:1/3=3/4*3=9/4

=>x=9/4+2/5=45/20+8/20=53/20

b: =>x-2/3=7/3:4/5=7/3*5/4=35/12

=>x=35/12+2/3=43/12

c: 1/3(x-2/5)=4/5

=>x-2/5=4/5*3=12/5

=>x=12/5+2/5=14/5

d: =>2/3x-1/3-1/4x+1/10=7/3

=>5/12x-7/30=7/3

=>5/12x=7/3+7/30=77/30

=>x=77/30:5/12=154/25

e: \(\Leftrightarrow x\cdot\dfrac{3}{7}-\dfrac{2}{7}+\dfrac{1}{2}-\dfrac{5}{4}x+\dfrac{5}{2}=0\)

=>\(x\cdot\dfrac{-23}{28}=\dfrac{2}{7}-3=\dfrac{-19}{7}\)

=>x=19/7:23/28=76/23

f: =>1/2x-3/2+1/3x-4/3+1/4x-5/4=1/5

=>13/12x=1/5+3/2+4/3+5/4=257/60

=>x=257/65

i: =>x^2-2/5x-x^2-2x+11/4=4/3

=>-12/5x=4/3-11/4=-17/12

=>x=17/12:12/5=85/144

`@` `\text {Ans}`

`\downarrow`

`a,`

`2/5 + x = 2/7`         

`=> x = 2/7 -2/5`

`=> x= - 4/35`

Vậy, `x=-4/35`

`b,`

`x + 3/5 = -2/5`

`=> x = -2/5 - 3/5`

`=> x=-1`

Vậy, `x=-1`

`c, `

`x - 8/5 = 3/7`

`=> x=3/7 + 8/5`

`=> x=71/35`

Vậy, `x=71/35`

`d,`

`3/5 - x = 7/3`

`=> x=3/5 - 7/3`

`=> x=-26/15`

Vậy, `x=-26/15`

a) \(\dfrac{2}{5}+x=\dfrac{2}{7}\)

\(\Rightarrow x=\dfrac{2}{7}-\dfrac{2}{5}\)

\(\Rightarrow x=-\dfrac{4}{35}\)

b) \(x+\dfrac{3}{5}=-\dfrac{2}{5}\)

\(\Rightarrow x=-\dfrac{2}{5}-\dfrac{3}{5}\)

\(\Rightarrow x=-1\)

c) \(x-\dfrac{8}{5}=\dfrac{3}{7}\)

\(\Rightarrow x=\dfrac{3}{7}+\dfrac{8}{5}\)

\(\Rightarrow x=\dfrac{71}{35}\)

d) \(\dfrac{3}{5}-x=\dfrac{7}{3}\)

\(\Rightarrow x=\dfrac{3}{5}-\dfrac{7}{3}\)

\(\Rightarrow x=-\dfrac{26}{15}\)

\(a,\dfrac{2}{5}+x=\dfrac{2}{7}\\ x=\dfrac{2}{7}-\dfrac{2}{5}\\ x=\dfrac{10}{35}-\dfrac{14}{35}\\ x=\dfrac{4}{35}\\ b,x+\dfrac{3}{5}=\dfrac{-2}{5}\\ x=\dfrac{-2}{5}-\dfrac{3}{5}\\ x=\dfrac{-5}{5}\\ x=-1\\ c,x-\dfrac{8}{5}=\dfrac{3}{7}\\ x=\dfrac{3}{7}+\dfrac{8}{5}\\ x=\dfrac{15}{35}+\dfrac{56}{35}\\ x=\dfrac{71}{35}\\ d,\dfrac{3}{5}-x=\dfrac{7}{3}\\ x=\dfrac{3}{5}-\dfrac{7}{3}\\ x=\dfrac{9}{15}-\dfrac{35}{15}\\ x=\dfrac{-26}{15}\)

Bài 1: 

a) \(-5\left(x^2-3x+1\right)+x\left(1+5x\right)=x-2\)

\(\Rightarrow-5x^2+15x-5+x+5x^2=x-2\)

\(\Rightarrow16x-5=x-2\)

\(\Rightarrow16x-x=5-2\)

\(\Rightarrow15x=3\)

\(\Rightarrow x=\dfrac{15}{3}=5\)

b) \(12x^2-4x\left(3x+5\right)=10x-17\)

\(\Rightarrow12x^2-12x^2-20x=10x-17\)

\(\Rightarrow-20x=10x-17\)

\(\Rightarrow-20x-10x=-17\)

\(\Rightarrow-30x=-17\)

\(\Rightarrow x=\dfrac{-30}{-17}=\dfrac{30}{17}\)

c) \(-4x\left(x-5\right)+7x\left(x-4\right)-3x^2=12\)

\(\Rightarrow-4x^2+20x+7x^2-28x-3x^2=12\)

\(\Rightarrow-8x=12\)

\(\Rightarrow x=\dfrac{12}{-8}=-\dfrac{4}{3}\)

Bài 2: 

a) \(\left(x+5\right)\left(x-7\right)-7x\left(x-3\right)\)

\(=x^2-7x+5x-35-7x^2+21x\)

\(=-6x^2+19x-35\)

b) \(x\left(x^2-x-2\right)-\left(x-5\right)\left(x+1\right)\)

\(=x^3-x^2-2x-x^2+x-5x-5\)

\(=x^3-2x^2-6x-5\)

c) \(\left(x-5\right)\left(x-7\right)-\left(x+4\right)\left(x-3\right)\)

\(=x^2-7x-5x+35-x^2-3x+4x-12\)

\(=11x+23\)

d) \(\left(x-1\right)\left(x-2\right)-\left(x+5\right)\left(x+2\right)\)

\(=x^2-2x-x+2-x^2+2x+5x+10\)

\(=4x+12\)

Bạn chia từng bài ra được chứ?

\(A=x^2+6x+9-4x-1-2x-x^2=9\\ B=2x^2+3x-10x-15-2x^2+6x+x+7=-8\\ C=\left(3x+5-3x+5\right)^2=100\)

a: \(A=x^2+6x+9-4x-1-2x-x^2=8\)

b: \(B=2x^2+3x-10x-15-2x^2+6x+x+7=-8\)