\(\dfrac{5}{15}\)+\(\dfrac{14}{25}\)-\(\dfrac{4}{3}\)+\(\dfrac{11}{25}\)
Những câu hỏi liên quan
\(A.\dfrac{-15}{28}x\dfrac{7}{25}\\ B.\dfrac{-5}{14}x\dfrac{7}{-3}\\ C.\dfrac{-1}{5}-\dfrac{7}{15}x\dfrac{9}{35}\\ D.\dfrac{-3}{4}-(\dfrac{-1}{2})^2\\ E.\dfrac{-4}{5}-\dfrac{-4}{5}x\dfrac{15}{16}\\F.(\dfrac{3}{4}+\dfrac{-7}{2})x(\dfrac{2}{11}+\dfrac{12}{22})\)
a: \(A=\dfrac{-7}{28}\cdot\dfrac{15}{25}=\dfrac{-1}{4}\cdot\dfrac{3}{5}=\dfrac{-3}{20}\)
b: \(B=\dfrac{-5\cdot7}{14\cdot\left(-3\right)}=\dfrac{35}{42}=\dfrac{5}{6}\)
c: \(C=\dfrac{-1}{5}-\dfrac{1}{5}\cdot\dfrac{3}{5}=\dfrac{-1}{5}-\dfrac{3}{25}=\dfrac{-8}{25}\)
d: \(D=\dfrac{-3}{4}-\dfrac{1}{4}=-1\)
e: \(E=\dfrac{-4}{5}\left(1-\dfrac{15}{16}\right)=\dfrac{-4}{5}\cdot\dfrac{1}{16}=\dfrac{-1}{20}\)
f: \(F=\dfrac{6-7}{4}\cdot\dfrac{4+12}{22}=\dfrac{-1}{4}\cdot\dfrac{8}{11}=\dfrac{-2}{11}\)
Đúng 1
Bình luận (0)
Tính một cách hợp lí.
a) \(A=\dfrac{-3}{14}+\dfrac{2}{13}+\dfrac{-25}{14}+\dfrac{-15}{13};\)
b) \(B=\dfrac{5}{3}\cdot\dfrac{7}{25}+\dfrac{5}{3}\cdot\dfrac{21}{25}-\dfrac{5}{3}\cdot\dfrac{7}{25}\).
a, \(\begin{array}{l}A = \dfrac{{ - 3}}{{14}} + \dfrac{2}{{13}} + \dfrac{{ - 25}}{{14}} + \dfrac{{ - 15}}{{13}}\\A = \left( {\dfrac{{ - 3}}{{14}} + \dfrac{{ - 25}}{{14}}} \right) + \left( {\dfrac{2}{{13}} + \dfrac{{ - 15}}{{13}}} \right)\\A = \dfrac{{ - 3 + \left( { - 25} \right)}}{{14}} + \dfrac{{2 + \left( { - 15} \right)}}{{13}}\\A = \dfrac{{ - 28}}{{14}} + \dfrac{{ - 13}}{{13}}\\A = - 2 + (-1)\\A = - 3\end{array}\)
b,
Cách 1:
\(\begin{array}{l}B = \dfrac{5}{3}.\dfrac{7}{{25}} + \dfrac{5}{3}.\dfrac{{21}}{{25}} - \dfrac{5}{3}.\dfrac{7}{{25}}\\B = \left( {\dfrac{5}{3}.\dfrac{7}{{25}} - \dfrac{5}{3}.\dfrac{7}{{25}}} \right) + \dfrac{5}{3}.\dfrac{{21}}{{25}}\\B = 0 + \dfrac{5}{3}.\dfrac{{21}}{{25}}\\B = \dfrac{{5.21}}{{3.25}}\\B = \dfrac{7}{5}\end{array}\)
Cách 2:
\(B = \dfrac{5}{3}.\dfrac{7}{{25}} + \dfrac{5}{3}.\dfrac{{21}}{{25}} - \dfrac{5}{3}.\dfrac{7}{{25}}\\B = \dfrac{5}{3}.({\dfrac{7}{{25}} -\dfrac{7}{{25}} + \dfrac{{21}}{{25}}})\\B = \dfrac{5}{3}.\dfrac{{21}}{{25}}\\B = \dfrac{{5.21}}{{3.25}}\\B = \dfrac{7}{5}\)
Đúng 0
Bình luận (0)
tính
dfrac{-5}{8}:dfrac{15}{4} dfrac{-15}{17}:dfrac{25}{-34} -48:(dfrac{-24}{5}) dfrac{-30}{7}:(dfrac{-5}{-14})
dfrac{15}{28}:(dfrac{-9}{14}) dfrac{-7}{40}:(-dfrac{21}{20}) (dfrac{-4}{15}).(-dfrac{-25}{8}) dfrac{5}{-14}.(-dfrac{7}{10})
dfrac{-15}{4}.(-dfrac{16}{25}) 15.(-dfrac{13}{10}) (-dfrac{14}{5}).-10 (dfrac{3}{-10}).(-dfrac{-15}{2})
Đọc tiếp
tính
\(\dfrac{-5}{8}:\dfrac{15}{4}\) \(\dfrac{-15}{17}:\dfrac{25}{-34}\) \(-48:(\dfrac{-24}{5})\) \(\dfrac{-30}{7}:(\dfrac{-5}{-14})\)
\(\dfrac{15}{28}:(\dfrac{-9}{14})\) \(\dfrac{-7}{40}:(-\dfrac{21}{20})\) \((\dfrac{-4}{15}).(-\dfrac{-25}{8})\) \(\dfrac{5}{-14}.(-\dfrac{7}{10})\)
\(\dfrac{-15}{4}.(-\dfrac{16}{25})\) \(15.(-\dfrac{13}{10})\) \((-\dfrac{14}{5}).-10\) \((\dfrac{3}{-10}).(-\dfrac{-15}{2})\)
mình ghi nhầm nên các bạn cứ hết hai phân số là một câu nhé ví dụ như \(\dfrac{-5}{8}\):\(\dfrac{15}{4}\)
Đúng 0
Bình luận (0)
1, A= \(\dfrac{-3}{4}.\left(0,125-1\dfrac{1}{2}\right):\dfrac{33}{16}-25\%\)
2, B= \(1\dfrac{13}{15}.0,75-\left(\dfrac{11}{20}+25\%\right):\dfrac{7}{3}\)
3, C= \(\dfrac{5}{16}:0,125-\left(2\dfrac{1}{4}-0,6\right).\dfrac{10}{11}\)
4, D= \(6\dfrac{5}{12}:2\dfrac{5}{4}+11\dfrac{1}{4}.\left(\dfrac{1}{3}-\dfrac{1}{5}\right)\)
\(1,A=-\dfrac{3}{4}.\left(0,125-1\dfrac{1}{2}\right):\dfrac{33}{16}-25\%\)
\(A=-\dfrac{3}{4}.\left(0,125-\dfrac{3}{2}\right):\dfrac{33}{16}-\dfrac{1}{4}\)
\(A=-\dfrac{3}{4}.\left(-\dfrac{11}{8}\right):\dfrac{33}{16}-\dfrac{1}{4}\)
\(A=\dfrac{33}{32}:\dfrac{33}{16}-\dfrac{1}{4}\)
\(A=\dfrac{33}{32}.\dfrac{16}{33}-\dfrac{1}{4}\)
\(A=\dfrac{1}{2}-\dfrac{1}{4}\)
\(A=\dfrac{2}{4}-\dfrac{1}{4}\)
\(A=\dfrac{1}{4}\)
Đúng 2
Bình luận (3)
\(D=6\dfrac{5}{12}:2\dfrac{5}{4}+11\dfrac{1}{4}.\left(\dfrac{1}{3}-\dfrac{1}{5}\right)\)
\(D=\dfrac{77}{12}:\dfrac{13}{4}+\dfrac{45}{4}.\dfrac{2}{15}\)
\(D=\dfrac{77}{39}+\dfrac{3}{2}\)
\(D=\dfrac{271}{78}\)
Đúng 1
Bình luận (0)
\(C=\dfrac{5}{16}:0,125-\left(2\dfrac{1}{4}-0,6\right).\dfrac{10}{11}\)
\(C=\dfrac{5}{16}:0,125-\left(\dfrac{9}{4}-0,6\right).\dfrac{10}{11}\)
\(C=\dfrac{5}{16}:0,125-\dfrac{33}{20}.\dfrac{10}{11}\)
\(C=\dfrac{5}{2}-\dfrac{3}{2}\)
\(C=1\)
Đúng 1
Bình luận (7)
Bài 1: Thực hiện phép tính:
1) \(\dfrac{-17}{30}-\dfrac{11}{-15}+\dfrac{-7}{12}\)
2) \(\dfrac{-5}{9}+\dfrac{5}{9}:\left(1\dfrac{2}{3}-2\dfrac{1}{12}\right)\)
3) \(\dfrac{-7}{25}.\dfrac{11}{13}+\dfrac{-7}{25}.\dfrac{2}{13}-\dfrac{18}{25}\)
1) âm năm phần 12
2) âm mười bảy phần 9
3) -1
Đây là đáp án còn làm bài từ làm nhé
Đúng 0
Bình luận (0)
Tìm x, biết:
\(x=\dfrac{19}{11}\cdot\dfrac{5}{14}+\dfrac{1}{11}\cdot\dfrac{5}{7}-\sqrt{\dfrac{25}{4}}\cdot\dfrac{2}{11}\)
Tính hợp lí
\(\dfrac{5}{15}\)+ \(\dfrac{14}{25}-\dfrac{12}{9}+\dfrac{2}{7}-\dfrac{-11}{25}\)
\(\dfrac{5}{15}+\dfrac{14}{25}-\dfrac{12}{9}+\dfrac{2}{7}-\dfrac{-11}{25}\)
\(=\dfrac{1}{3}+\dfrac{14}{25}-\dfrac{4}{3}+\dfrac{2}{7}+\dfrac{11}{25}\)
\(=\left(\dfrac{1}{3}-\dfrac{4}{3}\right)+\left(\dfrac{14}{25}+\dfrac{11}{25}\right)+\dfrac{2}{7}\)
\(=-1+1+\dfrac{2}{7}\)
\(=\dfrac{2}{7}\)
Đúng 0
Bình luận (0)
các bạn giúp mình nhé mình đang cần gấp ạ
a.dfrac{5}{-4}.dfrac{16}{25}+dfrac{-5}{4}.dfrac{9}{25} (. là nhân nhé ạ ) e.11dfrac{1}{4}-(2dfrac{5}{7}+5dfrac{1}{4})
b.4dfrac{11}{23}-dfrac{9}{14}+2dfrac{12}{23}-dfrac{5}{4} g.dfrac{7}{19}.dfrac{8}{11}+dfrac{7}{19}.dfrac{3}{11}+dfrac{12}{19}
c.2dfrac{13}{27}-dfrac{7}{15}+3dfrac{14}{27}-dfrac{8}{15} h.-left(dfrac{1}{2}right)^2 .13dfrac{9}{11}-...
Đọc tiếp
các bạn giúp mình nhé mình đang cần gấp ạ
a.\(\dfrac{5}{-4}\).\(\dfrac{16}{25}\)+\(\dfrac{-5}{4}\).\(\dfrac{9}{25}\) (. là nhân nhé ạ ) e.\(11\dfrac{1}{4}\)-(\(2\dfrac{5}{7}\)+\(5\dfrac{1}{4}\))
b.\(4\dfrac{11}{23}\)-\(\dfrac{9}{14}\)+\(2\dfrac{12}{23}\)-\(\dfrac{5}{4}\) g.\(\dfrac{7}{19}\).\(\dfrac{8}{11}\)+\(\dfrac{7}{19}\).\(\dfrac{3}{11}\)+\(\dfrac{12}{19}\)
c.\(2\dfrac{13}{27}\)-\(\dfrac{7}{15}\)+\(3\dfrac{14}{27}\)-\(\dfrac{8}{15}\) h.\(-\left(\dfrac{1}{2}\right)^2\) .13\(\dfrac{9}{11}\)-25%.6\(\dfrac{2}{11}\)
d.\(\dfrac{-4}{9}\).\(\dfrac{7}{15}\)+\(\dfrac{4}{-9}\).\(\dfrac{8}{15}\) i.57%+1\(\dfrac{2}{15}\):\(\dfrac{68}{25}\)-2,82
Dấu " / " là phân số nhé
a) 5/-4 . 16/25 + -5/4 . 9/25
= -5/4 . 16/25 + -5/4 . 9/25
= -5/4 . ( 16/25 + 9/25 )
= -5/4 . 1
= -5/4
b) 4 11/23 - 9/14 + 2 12/23 - 5/4
= 103/23 - 9/14 + 58/23 - 5/4
= 103/23 + 58/23 - 9/14 - 5/4
= 7 - 9/14 - 5/4
= 143/28
c) 2 13/27 - 7/15 + 3 14/27 - 8/15
= 67/27 - 7/15 + 95/27 - 8/15
= 67/27 + 95/27 - 7/15 - 8/15
= 6 - 7/15 - 8/15
= 5
Đúng 0
Bình luận (0)
4. thực hiện phép tính
a.\(\dfrac{4}{9}+\dfrac{11}{125}-\dfrac{17}{18}+\dfrac{17}{14}-\dfrac{5}{7}\)
b. \(1-\dfrac{1}{2}+2-\dfrac{2}{3}+3-\dfrac{3}{4}+4-\dfrac{1}{4}-3-\dfrac{1}{3}-2-\dfrac{1}{2}-1\)
c.\(\dfrac{1}{3}.\dfrac{14}{25}-\dfrac{1}{2}:\dfrac{25}{14}\)
d. \(\dfrac{3}{7}+\dfrac{5}{13}+\dfrac{4}{7}-\dfrac{18}{13}\)
a)= \(\left(\dfrac{4}{9}-\dfrac{17}{18}\right)+\left(\dfrac{17}{14}-\dfrac{5}{7}\right)+\dfrac{11}{125}\)
= \(\dfrac{-1}{2}\) + \(\dfrac{1}{2}\) + \(\dfrac{11}{125}\)
= 0 + \(\dfrac{11}{125}\)
= \(\dfrac{11}{125}\)
b) \(=\left(1-1\right)+\left(\dfrac{-1}{2}-\dfrac{1}{2}\right)+\left(2-2\right)\) +
\(\left(\dfrac{-2}{3}-\dfrac{1}{3}\right)+\left(3-3\right)+\left(\dfrac{-3}{4}-\dfrac{1}{4}\right)\) + 4
= 0 + (-1) + 0 + (-1) + 0 + (-1) + 4
= -1
c) = \(\dfrac{1}{3}.\dfrac{14}{25}-\dfrac{1}{2}.\dfrac{14}{25}\)
= \(\dfrac{14}{25}.\left(\dfrac{1}{3}-\dfrac{1}{2}\right)\)
= \(\dfrac{14}{25}.\left(\dfrac{-1}{6}\right)\)
= \(\dfrac{-7}{75}\)
d) = \(\left(\dfrac{3}{7}+\dfrac{4}{7}\right)+\left(\dfrac{5}{13}-\dfrac{18}{13}\right)\)
= 1 + (-1)
= 0
Đúng 0
Bình luận (0)