Question

\(\dfrac{5}{15}\)+\(\dfrac{14}{25}\)-\(\dfrac{4}{3}\)+\(\dfrac{11}{25}\)

Answer 1

\(\dfrac{5}{15}+\dfrac{14}{25}-\dfrac{4}{3}+\dfrac{11}{25}\\ =\left(\dfrac{5}{15}-\dfrac{4}{3}\right)+\left(\dfrac{14}{25}+\dfrac{11}{25}\right)\\ =\left(\dfrac{5}{15}-\dfrac{20}{15}\right)+\dfrac{25}{25}\\ =\dfrac{-15}{15}+\dfrac{25}{25}\\ =-1+1\\ =0\)

Answer 2

\(\dfrac{5}{15}\) +  \(\dfrac{14}{25}\) − \(\dfrac{4}{3}\) + \(\dfrac{11}{25}\)\(\dfrac{11}{25}\)

=   [ \(\dfrac{5}{15}\)− \(\dfrac{4}{3}\) ] + [ \(\dfrac{14}{25}\) + 

Answer 3

515+1425−43+1125=(515−43)+(1425+1125)=(515−2015)+2525=−1515+2525=−1+1=0