tìm x , biết
x + 124 = 200
1) thực hiện phép tính
-126+67+[32-(-126)]-64
240-[(82-49):3+135]:18
A+1+2+22+23+...+22021
-205+37-(-200)
2) Tìm x∈z biết
x-45=48-68
35+5(6-x)=-12-(-112)
517-(x-124)=-483
46-(3x-2)3=(-38)+20
Bài 2:
a: =>x-45=-20
hay x=25
b: =>35+30-5x=-12+112
=>65-5x=100
=>5x=-35
hay x=-7
c: =>x-124=1000
hay x=1124
d: \(\Leftrightarrow46-\left(3x-2\right)^3=-18\)
\(\Leftrightarrow\left(3x-2\right)^3=64\)
=>3x-2=4
hay x=2
1) thực hiện phép tính
-126+67+[32-(-126)]-64
240-[(82-49):3+135]:18
A+1+2+22+23+...+22021
-205+37-(-200)
2) Tìm x∈z biết
x-45=48-68
35+5(6-x)=-12-(-112)
517-(x-124)=-483
46-(3x-2)3=(-38)+20
Bài 2:
a: =>x-45=-20
hay x=25
b: =>35+30-5x=-12+112=100
=>65-5x=100
=>5x=-35
hay x=-7
c: =>x-124=1000
hay x=1124
d: \(\Leftrightarrow46-\left(3x-2\right)^3=-18\)
\(\Leftrightarrow\left(3x-2\right)^3=64\)
=>3x-2=4
hay x=2
tìm x thuộc n, biết
x mũ 20=x
\(x^{20}=x\)
⇒\(x^{20}-x=0\)
⇒\(x\left(x^{19}-1\right)=0\)
⇔\(x^{19}-1=0\) hoặc x=0
⇔x=1 hoặc x=0
\(x^{20}=x\\ \Leftrightarrow x^{20}-x=0\\ \Leftrightarrow x\left(x^{19}-1\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=0\\x=1\end{matrix}\right.\)
\(x^{20}=x\\ \Rightarrow x\in\left\{0;1\right\}\)vì \(x\in N\)
Tìm x, biết
x×2,5 + 7,5 = 36,5
X × 2,5 + 7,5 = 36,5
X × 2,5 = 36,5 - 7,5
X × 2,5 = 29
X = 29 : 2,5
X = 11,6
\(x\times2,5+7,5=36,5\\ x\times2,5=36,5-7,5\\ x\times2,5=29\\ x=29:2,5\\ x=11,6\)
tìm x, biết
x : 15 = 8 : 24
\(x:15=\dfrac{8}{24}\)
\(\Rightarrow x:8=\dfrac{1}{3}\)
\(\Rightarrow x=\dfrac{1}{3}.15\)
\(\Rightarrow x=5\)
Tìm x, biết
x+ 1538 = 3215
x- 215 = 1578
345- x =182
\(x+1538=3215\\ \Rightarrow x=3215-1538=1677\\ x-215=1578\\ \Rightarrow x=1578+215=1793\\ 345-x=182\\ \Rightarrow x=345-182=163\)
x+1538=3215⇒x=3215−1538=1677x−215=1578⇒x=1578+215=1793345−x=182⇒x=345−182=163
x+1538=3215⇒x=3215−1538=1677x−215=1578⇒x=1578+215=1793345−x=182⇒x=345−182=163
Tìm x biết
x-11/13=15/13
\(x=\dfrac{15}{13}+\dfrac{11}{13}=\dfrac{15+11}{13}=\dfrac{26}{13}\)
\(x=\dfrac{15}{13}+\dfrac{11}{13}\\ x=\dfrac{26}{13}\)
Tìm X biết
X^2/20 = 4/5
\(\dfrac{x^2}{20}=\dfrac{4}{5}\)
\(\Leftrightarrow x^2=16\)
hay \(x\in\left\{4;-4\right\}\)
Tìm số nguyên x biết
x-1/8= 4/x-2
\(x-\dfrac{1}{8}=\dfrac{4}{x-2}\) hay \(x-\dfrac{1}{8}=\dfrac{4}{x}-2\) vậy bạn?
\(\dfrac{x-1}{8}=\dfrac{4}{x-2}\)
=>\(\dfrac{\left(x-1\right)\left(x-2\right)}{8.\left(x-2\right)}=\dfrac{4.8}{\left(x-2\right).8}\)
=>khử mẫu
=>(x-1)(x-2)=32
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