1 I wear colorful clothes during Tet Holiday

2 I will say happy new year to my mother

3 She won't ask for lucky money

4 I won't sweep the floor

5 He won't take the things related to the house out of water

1. I wear colorful clothes during Tet Holiday.

2. I will to say happy new year.....đoạn này mk hơi bí.

3. She won't ask for lucky money.

4. I won't sweep the floor.

5. He won't take the things related to the house out of water.

1. I will wear colorful clothes during Tet holiday.

2. I will say happy new year to my mother.

3. She won't ask for lucky money.

4. I won't sweep the floor.

5. He won't take the things related to the house out of water.

Mạch khuôn: \(-T-A-X-G-G-A-T-X-X-\)

Mạch BS: \(-A-T-G-X-X-T-A-G-G-\)

Mạch khuôn: 

Mạch Bổ sung : 

Do M thuộc d nên tọa độ có dạng: \(M\left(2+2t;3+t\right)\)

\(\Rightarrow\overrightarrow{AM}=\left(2+2t;2+t\right)\)

\(\Rightarrow AM=\sqrt{\left(2+2t\right)^2+\left(2+t\right)^2}=\sqrt{5t^2+12t+8}\)

Mà \(AM=5\Rightarrow\sqrt{5t^2+12t+8}=5\)

\(\Rightarrow5t^2+12t+8=25\)

\(\Rightarrow5t^2+12t-17=0\Rightarrow\left[{}\begin{matrix}t=1\\t=-\dfrac{17}{5}\end{matrix}\right.\)

Với \(t=1\Rightarrow M\left(4;4\right)\) loại do hoành độ dương

Với \(t=-\dfrac{17}{5}\Rightarrow M\left(-\dfrac{24}{5};-\dfrac{2}{5}\right)\) thỏa mãn

M thuộc D nên tọa độ M có dạng (2+2a;3+a) . Vì M có hoành độ âm nên a<-1.

 Theo bài ra, ta có : \(AM=5\Leftrightarrow\sqrt{\left(2+2a\right)^2+\left(2+a\right)^2}=5\)

\(\Leftrightarrow5a^2+12a-17=0\)

\(\Leftrightarrow\left[{}\begin{matrix}a=1\left(loại\right)\\a=-\dfrac{17}{5}\left(nhận\right)\end{matrix}\right.\)

Với a = -17 /5 

=> \(M\left(-\dfrac{24}{5};-\dfrac{2}{5}\right)\)

Giúp vs :((

Bạn cần giúp gì nhỉ? <3

a: Ta có: \(\widehat{ADE}=\widehat{C}\)

mà hai góc này là hai góc ở vị trí so le trong

nên DE//BC

Xét ΔBAC có \(\widehat{ABC}+\widehat{ACB}+\widehat{BAC}=180^0\)

hay \(\widehat{ABC}=50^0\left(1\right)\)

Ta có: \(\widehat{DAB}+\widehat{BAC}=180^0\)

\(\Leftrightarrow\widehat{MAB}=\dfrac{180^0-80^0}{2}=50^0\left(2\right)\)

Từ \(\left(1\right),\left(2\right)\) suy ra AM//BC

mà BC//DE

nên AM//DE

A.

\(C_2H_2+H_2\xrightarrow[t^o]{Pd}C_2H_4\\ C_2H_4+H_2\xrightarrow[t^o]{Ni}C_2H_6\)

A

a