phân số thứ nhất =16/11

phân số thứ hai = -5/9

phân số thứ ba = 10/77

a: \(\dfrac{4\cdot5+4\cdot11}{8\cdot7+4\cdot3}=\dfrac{4\cdot16}{4\left(2\cdot7+3\right)}=\dfrac{16}{17}=\dfrac{11088}{11781}\)

\(\dfrac{-15\cdot8+10\cdot7}{5\cdot6+20\cdot3}=\dfrac{-120+170}{30+60}=\dfrac{50}{90}=\dfrac{5}{9}=\dfrac{6545}{11781}\)

\(\dfrac{2^4\cdot5^2\cdot7}{2^3\cdot5\cdot7^2\cdot11}=2\cdot5\cdot\dfrac{1}{77}=\dfrac{10}{77}=\dfrac{1530}{11781}\)

A=\(\dfrac{4.5+4.11}{8.7-4.3}=\dfrac{4.\left(5+11\right)}{56-12}=\dfrac{4.16}{44}\dfrac{1.16}{11}=\dfrac{16}{11}\)

Câu B chỉ cần phân tích số 6 và 20 ở dưới mẫu thành 6=3.2, 20=4.5 rồi bn cứ thế mà tiếp tục!

a: \(\dfrac{4\cdot5+4\cdot11}{8\cdot7+4\cdot3}=\dfrac{20+44}{56+12}=\dfrac{64}{68}=\dfrac{16}{17}=\dfrac{11088}{11781}\)

\(\dfrac{-15\cdot8+10\cdot7}{5\cdot6+20\cdot3}=\dfrac{-120+70}{30+60}=\dfrac{-50}{90}=\dfrac{-5}{9}=\dfrac{-6545}{11781}\)

\(\dfrac{2^4\cdot5^2\cdot7}{2^3\cdot5\cdot7^2\cdot11}=\dfrac{2\cdot5}{7\cdot11}=\dfrac{10}{77}=\dfrac{1530}{11781}\)

b)\(\frac{-15.8+10.7}{5.6+20.3}=\frac{-15.8+10.7}{5.2.3+5.4.3}=\frac{-90+70}{5.3.\left(2+4\right)}=\frac{-20}{90}=-\frac{2}{9}\)

\(\frac{2^4.5^2.7}{2^3.5.7^2.11}=\frac{2.5.1}{1.1.7.11}=\frac{10}{77}\)

MSC:77.9=693

\(\frac{-2}{9}=\frac{-2.693}{9.693}=\frac{-1386}{6237}\)

\(\frac{10}{77}=\frac{10.693}{77.693}=\frac{6930}{53361}\)

a) \(\frac{4.5+4.11}{8.7+4.3}=\frac{4.\left(5+11\right)}{56+12}=\frac{4.16}{68}=\frac{64}{68}=\frac{16}{17}.\)

Mình chỉ làm câu a) thôi nhé.

Chúc bạn học tốt!

a)\(\frac{4.5+4.11}{8.7+4.3}=\frac{4.\left(5+11\right)}{56+12}=\frac{4.16}{78}=\frac{64}{78}=\frac{32}{39}\)

a) \(\dfrac{2^4\cdot5^2\cdot7}{2^3\cdot5\cdot7^2\cdot11}=\dfrac{2^3\cdot5\cdot10\cdot7}{2^3\cdot5\cdot7\cdot77}=\dfrac{10}{77}\)

\(\dfrac{2^3\cdot3^3\cdot5^3\cdot7\cdot8}{3\cdot2^4\cdot5^3\cdot14}=\dfrac{2^3\cdot3\cdot5^3\cdot7\cdot3^2\cdot8}{3\cdot2^3\cdot2\cdot5^3\cdot14}=\dfrac{7\cdot3^2\cdot8}{2\cdot14}=\dfrac{63\cdot8}{2\cdot14}=18=\dfrac{1386}{77}\)

rút gọn rồi quy đồng nha

Câu 1: 

\(\dfrac{14\cdot34-21\cdot10}{28\cdot10-28\cdot16}=\dfrac{7\cdot2\cdot34-7\cdot3\cdot10}{28\left(10-16\right)}\)

\(=\dfrac{7\left(2\cdot34-3\cdot10\right)}{28\cdot\left(-6\right)}=\dfrac{1}{4}\cdot\dfrac{68-30}{-6}=\dfrac{1}{4}\cdot\dfrac{38}{-6}=\dfrac{38}{-24}=-\dfrac{19}{12}\)

\(-\frac{20+44}{56-12}=\frac{-64}{44}=\)\(\frac{-16}{11}\)

\(\frac{-120+70}{30+60}\)=\(\frac{-5}{9}\)

Ta có \(\frac{-16}{11}< \frac{-11}{11}=-1\)

\(\frac{-5}{9}>\frac{-9}{9}=-1\)

nên \(\frac{-5}{9}>-1>\frac{-16}{11}\)

Vậy \(\frac{-5}{9}>\frac{-16}{11}\)

tự kết luận nhé