3/5 : x =1/3

=> x = 3/5 : 1/3

=> x = 9/5
x : 7/11 = 22

=> x = 22 x 7/11

=> x = 14
x - 3/2 = 11/4

=> x = 3/2 + 11/4

=> x = 17/4

\(\dfrac{3}{5}:x=\dfrac{1}{3}\)

\(x=\dfrac{3}{5}:\dfrac{1}{3}\)

\(x=\dfrac{9}{5}\)

\(x:\dfrac{7}{11}=22\)

\(x=22\times\dfrac{7}{11}\)

\(x=\dfrac{154}{11}=14\)

\(x-\dfrac{3}{2}=\dfrac{11}{4}\)

\(x=\dfrac{11}{4}+\dfrac{3}{2}\)

\(x=\dfrac{11}{4}+\dfrac{6}{4}=\dfrac{17}{4}\)

a,x=3/5:1/3

x=3/5.3

x=9/5

b,x=22.7/11

x=14

c,x=11/4+3/2

x=11/4+6/4

x=17/4

With \(x< 11\) , we have:

\(\sqrt{121-22x+x^2}=\sqrt{\left(11-x\right)^2}=\left|11-x\right|=11-x\)

\(\Rightarrow A=\sqrt{121-22x+x^2}+x-11=11-x+x-11=0\)

\(-\dfrac{15}{23}:\dfrac{22x}{7}=-\dfrac{14x}{11}:\left(13+\dfrac{4}{5}\right)\)

=>\(-\dfrac{15}{23}\cdot\dfrac{7}{22x}=\dfrac{-14x}{11}:\dfrac{69}{5}\)

=>\(-\dfrac{105}{23\cdot22x}=\dfrac{-70x}{11\cdot69}\)

=>\(\dfrac{-3}{2x}=\dfrac{-2x}{3}\)

=>\(4x^2=9\)

=>\(x^2=\dfrac{9}{4}\)

=>\(\left[{}\begin{matrix}x=\dfrac{3}{2}\\x=-\dfrac{3}{2}\end{matrix}\right.\)

\(\dfrac{-15}{23}:\dfrac{22x}{7}=\dfrac{-14x}{11}:\left(13+\dfrac{4}{5}\right)\)

\(\Leftrightarrow-\dfrac{15}{23}\cdot\dfrac{7}{22x}=\dfrac{-14x}{11}:\dfrac{69}{5}\)

=>\(\dfrac{-15\cdot7}{23\cdot22x}=\dfrac{-14x}{11}\cdot\dfrac{5}{69}\)

=>\(\dfrac{5\cdot3\cdot7}{23\cdot2\cdot11x}=\dfrac{2\cdot7x}{11}\cdot\dfrac{5}{3\cdot23}\)

=>\(\dfrac{3}{2x}=\dfrac{2x}{3}\)

=>\(4x^2=9\)

=>\(x^2=\dfrac{9}{4}\)

=>\(\left[{}\begin{matrix}x=\dfrac{3}{2}\\x=-\dfrac{3}{2}\end{matrix}\right.\)

a) x = 3

b) x = -2

c) x= -8

d) x = -10

e) x= 8 hoặc x = -8

f) x = 11 hoặc x = -11

a) 22x+16y=1997

Vì 1997 là số lẻ

⇒ Một thừa số là lẻ, còn một thừa số là chẵn

Nhưng vì 22x và 16y đều là chẵn với x,y∈N

⇒Ko thỏa mãn x,y theo yêu cầu đề bài

a) \(\left|-\frac{2}{11}+\frac{3}{22}x\right|-\frac{1}{2}=\frac{5}{7}\)

=> \(\left|-\frac{2}{11}+\frac{3}{22}x\right|=\frac{17}{14}\)

=> \(\orbr{\begin{cases}-\frac{2}{11}+\frac{3}{22}x=\frac{17}{14}\\-\frac{2}{11}+\frac{3}{22}x=-\frac{17}{14}\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{215}{21}\\x=-\frac{53}{7}\end{cases}}\)

b) \(-\frac{7}{8}x-5\frac{3}{4}=3\)

=> \(-\frac{7}{8}x-\frac{23}{4}=3\)

=> \(-\frac{7}{8}x=3+\frac{23}{4}=\frac{35}{4}\)

=> \(x=\frac{35}{4}:\left(-\frac{7}{8}\right)=\frac{35}{4}\cdot\left(-\frac{8}{7}\right)=-10\)

c) \(2x+\left(-\frac{2}{7}\right)-7=-11\)

=> \(2x-\frac{2}{7}-7=-11\)

=> \(2x=-11+7+\frac{2}{7}=-\frac{26}{7}\)

=> \(x=\left(-\frac{26}{7}\right):2=-\frac{13}{7}\)

d) \(\frac{3}{7}+x:\frac{14}{15}=\frac{1}{2}\)

=> \(x:\frac{14}{15}=\frac{1}{2}-\frac{3}{7}=\frac{1}{14}\)

=> \(x=\frac{1}{14}\cdot\frac{14}{15}=\frac{1}{15}\)