`x xx 6/7=5/14`

`=>x=5/14:6/7`

`=>x=5/14xx7/6`

`=>x=35/84`

`=>x=5/12`

Vậy `x=5/12`

__

`x:2/3=4/9`

`=>x=4/9xx2/3`

`=>x=8/27`

Vậy `x=8/27`

__

`x-1/4=3/2`

`=>x=3/2+1/4`

`=>x=6/4+1/4`

`=>x=7/4`

Vậy `x=7/4`

__

`x+4/5=8/9`

`=>x=8/9-4/5`

`=>x=40/45-36/45`

`=>x=4/45`

Vậy `x=4/45`

\(x\cdot\dfrac{6}{7}=\dfrac{5}{14}\)

\(x\)         \(=\dfrac{5}{14}:\dfrac{6}{7}\)

\(x\)           \(=\dfrac{5}{12}\)

\(x:\dfrac{2}{3}=\dfrac{4}{9}\)

\(x\)        \(=\dfrac{4}{9}\cdot\dfrac{2}{3}\)

\(x\)          \(=\dfrac{8}{27}\)

\(x-\dfrac{1}{4}=\dfrac{3}{2}\)

\(x\)          \(=\dfrac{3}{2}+\dfrac{1}{4}\)

\(x\)            \(=\dfrac{7}{4}\)

\(x+\dfrac{4}{5}=\dfrac{8}{9}\)

\(x\)          \(=\dfrac{8}{9}-\dfrac{4}{5}\)

\(x\)            \(=\dfrac{4}{45}\)

\(\frac{5}{8}-\frac{3}{8}.x=\left(-\frac{1}{2}\right)^4+\frac{5}{6}\)

\(\Leftrightarrow\frac{5}{8}-\frac{3}{8}.x=\frac{1}{16}+\frac{5}{6}\)

\(\Leftrightarrow\frac{3}{8}.x=\frac{5}{8}-\left(\frac{1}{16}+\frac{5}{6}\right)\)

\(\Leftrightarrow\frac{3}{8}.x=\frac{5}{8}-\frac{5}{96}\)

\(\Leftrightarrow\frac{3}{8}.x=\frac{55}{96}\)

\(\Leftrightarrow x=\frac{55}{96}:\frac{3}{8}\)

\(\Leftrightarrow x=\frac{55}{36}\)

Vậy : \(x=\frac{55}{36}\)

Chúc bạn học tốt nhé !

a) \(\dfrac{3}{4}\times x:\dfrac{1}{2}=\dfrac{4}{5}\)

\(\dfrac{3}{4}\times x=\dfrac{4}{5}\times\dfrac{1}{2}\)

\(\dfrac{3}{4}\times x=\dfrac{2}{5}\)

\(x=\dfrac{2}{5}:\dfrac{3}{4}\)

\(x=\dfrac{8}{15}\)

b) \(\left(14-x:6\right)\times7=84\)

\(14-x:6=84:7\)

\(14-x:6=12\)

\(x:6=14-12\)

\(x:6=2\)

\(x=6\times2=12\)

c) \(x\times1,5:2,4=0,3\)

\(x\times1,5=0,3\times2,4\)

\(x\times1,5=0,72\)

\(x=0,72:1,5\)

\(x=0,48\)

d) Thiếu x

a, \(x + 1/6 = -3/8 \)

\(x = -3/8 - 1/6\)

\(x = -13/24\)

Vậy \(x = -13/24\)

b, \(-3/7 - x = 4/5 - 2/3\)

\(-3/7 - x = 2/15\)

\(x = -3/7 - 2/15\)

\(x = -59/105.\)

Vậy \(x = -59/105\)

x+1/6=-3/8

x=-3/8-1/6

x=-13/24

-3/7-x=4/5+-2/3
-3/7-x=2/15

x=-3/7-2/15

x=-59/105

tham khảo

=> cái vế  trong ngoặc là 0.

rồi bạn làm tiếp nha

\(\dfrac{-12}{25}.\left(\dfrac{3}{4}-x+\dfrac{6}{-11}-\dfrac{5}{6}\right)=0\)

\(\dfrac{3}{4}-x+\dfrac{-6}{11}-\dfrac{5}{6}=0\)

\(\dfrac{3}{4}-x+\dfrac{-91}{66}=0\)

\(\dfrac{3}{4}-x=0-\left(\dfrac{-91}{66}\right)\)

\(\dfrac{3}{4}-x=\dfrac{91}{66}\)

\(x=\dfrac{-83}{132}\)

a: Ta có: \(-\dfrac{12}{25}\cdot\left(\dfrac{3}{4}-x+\dfrac{6}{-11}-\dfrac{5}{6}\right)=0\)

\(\Leftrightarrow x+\dfrac{83}{132}=0\)

hay \(x=-\dfrac{83}{132}\)

ĐKXĐ: x ≠ 3, x ≠ 4, x ≠ 5, x ≠ 6.

Ta có:

Vậy phương trình đã cho có nghiệm là x = 0;x = 9/2. 

`a)0,12 xx x=6`

`x=6:0,12`

`x=50`

`b)x:2,5=4`

`x=2,5xx4`

`x=10`

`c)5,6:x=4`

`x=5,6:4`

`x=1,4`

`d)x xx0,1=2/5`

`x = 2/5:0,1`

`x=2/5 :1/10`

`x=2/5xx10/1`

`x=4`

`a) 0,12 xx x = 6`

`x = 6 : 0,12`

`x = 50`

`b) x:2,5=4`

`x=4 xx2,5`

`x=10`

`c) 5,6:x=4`

`x=5,6:4`

`x=1,4`

`d) x xx 0,1 = 2/5`

`x = 2/5 : 0,1`

`x=4`

\(\)a) 

\(0,12\times x=6\)

\(x=6:0,12\)

\(x=50\)

b)

\(x:2,5=4\)

\(x=4\times2,5\)

\(\)\(x=10\)

c)

 \(5,6:x=4\)

\(x=5,6:4\)

\(x=1,4\)

d) 

\(x\times0,1=\dfrac{2}{5}\)

\(x=\dfrac{2}{5}:0,1\)

\(x=\dfrac{2}{5}\times10\)

\(x=4\)

\(\frac{1}{2}.x-\frac{3}{4}=\frac{5}{6}\)

\(\frac{1}{2}.x=\frac{5}{6}+\frac{3}{4}\)

\(\frac{1}{2}.x=\frac{19}{12}\)

\(x=\frac{19}{12}:\frac{1}{2}\)

\(x=\frac{19}{6}\)

Vậy \(x=\frac{19}{6}\)

\(\frac{1}{2}\)x X = \(\frac{5}{6}\)+ \(\frac{3}{4}\)

\(\frac{1}{2}\)x X = \(\frac{19}{12}\)

X = \(\frac{19}{12}\): \(\frac{1}{2}\)

X = \(\frac{19}{6}\)

1/2 x X - 3/4 = 5/6

1/2 x X = 5/6 + 3/4

1/2 x X = 19/12

X = 19/12 : 1/2

X = 19/6