xin lỗi, bn cóa thể bấm ∑ cái nài để lm lại đề đc hăm :v?

\(\dfrac{2x-3}{4-x}+\dfrac{1}{3}>\dfrac{1}{2}-\dfrac{3-x}{5}\) 

đúng ko ???

Áp dụng tính chất của dãy tỉ số bằng nhau, ta được:

\(\dfrac{x}{4}=\dfrac{y}{5}=\dfrac{x+y}{4+5}=\dfrac{18}{9}=2\)

Do đó: x=8; y=10

5/6 : x= 1/6 - 4/5 

5/6 : x= -19/30

x = 5/6 : (-19)/30

x = -25/19

\(x=\dfrac{5}{6}:\left(\dfrac{1}{6}-\dfrac{4}{5}\right)=\dfrac{5}{6}:\left(-\dfrac{19}{30}\right)=-\dfrac{25}{19}\)

\(\dfrac{5}{6}:x=\dfrac{1}{6}-\dfrac{4}{5}\)
\(\dfrac{5}{6}:x=-\dfrac{19}{30}\)
      \(x=\dfrac{5}{6}:\left(-\dfrac{19}{30}\right)\)
      \(x=-\dfrac{25}{19}\)

A=\(\dfrac{18360}{151}\)

B=\(\dfrac{1510}{3}\)

*Giải bằng casio

ghi phép tính đầy đủ ạ

\(x^2+\left(x+3\right)\left(x-9\right)=-27\\ \Rightarrow x^2+x^2+3x-9x-27=-27\\ \Rightarrow2x^2-6x=0\\ \Rightarrow2x\left(x-3\right)=0\\ \Rightarrow\left[{}\begin{matrix}x=0\\x=3\end{matrix}\right.\)

\(x^2+\left(x+3\right)\left(x-9\right)=-27\)

\(\Rightarrow2x^2-6x=0\)

\(\Rightarrow2x\left(x-3\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}x=0\\x=3\end{matrix}\right.\)

\(\Rightarrow x^2+x^2-6x-27=-27\\ \Rightarrow2x^2-6x=0\\ \Rightarrow2x\left(x-3\right)=0\Rightarrow\left[{}\begin{matrix}x=0\\x=3\end{matrix}\right.\)

1)x^4+x^2-6x+1=0>>>x^4+4x^2+4-3x^2-6x-3=0>>>(x^2+2)^2=3(x-1)^2.

>>Sau đó giải bt.

2)Đặt x^2-x+1=a;x+1=b thì:x^3+1=ab.

Pt:2a+5b^2+14ab=0(tự giải nha)

\(x\times9,25\times x=55,35\)

\(x\times x=55,35:9,25\)

\(x\times x\approx5,98\)

\(x\approx2,45\)

hình như em chép sai đề bài

x=2,446177382

0,5x-\(\dfrac{2}{3}.\left(x-2\right)=\dfrac{1}{6}\) 

\(\dfrac{1}{2}x-\dfrac{2}{3}x-\dfrac{4}{3}=\dfrac{1}{6}\) 

   \(x.\left(\dfrac{1}{2}+\dfrac{2}{3}\right)=\dfrac{1}{6}+\dfrac{4}{3}\) 

                \(x.\dfrac{7}{6}=\dfrac{3}{2}\) 

                    \(x=\dfrac{3}{2}:\dfrac{7}{6}\) 

                    \(x=\dfrac{9}{7}\)

`0,5x-2/3 .(x-2)=1/6`

`0,5x - 2/3 x + 4/3= 1/6`

` -1/6x = -7/6`

`x=7`

\(0,5x-\dfrac{2}{3}.\left(x-2\right)=\dfrac{1}{6}\) 

     \(\dfrac{1}{2}x-\dfrac{2}{3}x-\dfrac{4}{3}=\dfrac{1}{6}\) 

        \(x.\left(\dfrac{1}{2}-\dfrac{2}{3}\right)=\dfrac{1}{6}+\dfrac{4}{3}\) 

        \(x.\dfrac{-1}{6}=\dfrac{3}{2}\) 

                \(x=\dfrac{3}{2}:\dfrac{-1}{6}\) 

                \(x=-9\)

2x + 13/6 =8/27

2x            = 8/27 - 13/6

2x            = - 101/54

x            = - 101/54 : 2

x              = - 101/108