Question

0,5x-2/3.(x-2)=1/6

Giúp mik vs.Mik đg gấp.Pls!!!

Answer 1

0,5x-\(\dfrac{2}{3}.\left(x-2\right)=\dfrac{1}{6}\) 

\(\dfrac{1}{2}x-\dfrac{2}{3}x-\dfrac{4}{3}=\dfrac{1}{6}\) 

   \(x.\left(\dfrac{1}{2}+\dfrac{2}{3}\right)=\dfrac{1}{6}+\dfrac{4}{3}\) 

                \(x.\dfrac{7}{6}=\dfrac{3}{2}\) 

                    \(x=\dfrac{3}{2}:\dfrac{7}{6}\) 

                    \(x=\dfrac{9}{7}\)

Answer 2

`0,5x-2/3 .(x-2)=1/6`

`0,5x - 2/3 x + 4/3= 1/6`

` -1/6x = -7/6`

`x=7`

Answer 3

\(0,5x-\dfrac{2}{3}.\left(x-2\right)=\dfrac{1}{6}\) 

     \(\dfrac{1}{2}x-\dfrac{2}{3}x-\dfrac{4}{3}=\dfrac{1}{6}\) 

        \(x.\left(\dfrac{1}{2}-\dfrac{2}{3}\right)=\dfrac{1}{6}+\dfrac{4}{3}\) 

        \(x.\dfrac{-1}{6}=\dfrac{3}{2}\) 

                \(x=\dfrac{3}{2}:\dfrac{-1}{6}\) 

                \(x=-9\)

Answer 4

\(0,5x-\dfrac{2}{3}.\left(x-2\right)=\dfrac{1}{6}\) 

     \(\dfrac{1}{2}x-\dfrac{2}{3}x+\dfrac{4}{3}=\dfrac{1}{6}\)

         \(x.\left(\dfrac{1}{2}-\dfrac{2}{3}\right)=\dfrac{1}{6}-\dfrac{4}{3}\) 

                   \(x.\dfrac{-1}{6}=\dfrac{-7}{6}\) 

                          \(x=\dfrac{-7}{6}:\dfrac{-1}{6}\) 

                          \(x=7\)

Answer 5

Ta có: \(0.5x-\dfrac{2}{3}\left(x-2\right)=\dfrac{1}{6}\)

\(\Leftrightarrow\dfrac{1}{2}x-\dfrac{2}{3}x+\dfrac{4}{3}=\dfrac{1}{6}\)

\(\Leftrightarrow\dfrac{-1}{6}x=\dfrac{1}{6}-\dfrac{4}{3}=\dfrac{1}{6}-\dfrac{8}{6}=\dfrac{-7}{6}\)

hay x=7

Vậy: x=7