\(a̸\)   

\(\frac{3}{5}-\frac{1}{2}.x=\frac{1}{4}\)

            \(\frac{1}{2}.x=\frac{3}{5}-\frac{1}{4}\)

           \(\frac{1}{2}.x=\frac{7}{20}\)

            \(\Rightarrow\frac{7}{10}\)

\(b̸\)

\(11,3+2\left[x-\frac{1}{3}\right]=\frac{25}{6}\)

\(2\left[x-\frac{1}{3}\right]=\frac{25}{6}-11,3\)

\(2\left[x-\frac{1}{3}\right]=\frac{-107}{15}\)

\(x-\frac{1}{3}=\frac{-107}{15}:2\)

 \(x-\frac{1}{3}=\frac{-107}{30}\)

\(x=\frac{-107}{30}+\frac{1}{3}\)

\(x=\frac{-97}{30}\)

\(a)\frac{3}{5}-\frac{1}{2}x=\frac{1}{4}\)

\(\implies\frac{1}{2}x=\frac{3}{5}-\frac{1}{4}\)

\(\implies\frac{1}{2}x=\frac{7}{20}\)

\(\implies x=\frac{7}{20}:\frac{1}{2}\)

\(\implies x=\frac{7}{10}\)

Vậy...

\(b) 11,3+2(x-\frac{1}{3})=\frac{25}{6}\)

\(\implies \frac{113}{10}+2x-2.\frac{1}{3}=\frac{25}{6}\)

\(\implies \frac{113}{10}+2x-\frac{2}{3}=\frac{25}{6}\)

\(\implies \frac{113}{10}+2x=\frac{25}{6}+\frac{2}{3}\)

\(\implies \frac{113}{10}+2x=\frac{29}{6}\)

\(\implies 2x=\frac{29}{6}-\frac{113}{10}\)

\(\implies 2x=\frac{-97}{15}\)

\(\implies x=\frac{-97}{30}\)

Vậy..

\(c)5x-435+2x+140+3x=565\)

\(\implies (5x+2x+3x)+(-435+140)=565\)

\(\implies 10x+(-295)=565\)

\(\implies 10x=565-(-295)\)

\(\implies 10x=860\)

\(\implies x=86\)

Vậy...

~ hok tốt a~

`1/2+3/4-5/6=6/12+9/12-10/12=5/12`

`(5/6+3/8)xx2/7=(20/24+9/24)xx2/7=29/24xx2/7=29/84`

`(7/6-3/4):3/5=(14/12-9/12)xx5/3=5/12xx5/3=25/36`

`6/7xx2/3:5/7=6/7xx2/3xx7/5=4/5`

` 1/2 + 3/4 - 5/6 = 6/12 + 9/12 - 10/12 = 5/12`

` ( 5/6 + 3/8) xx 2/7 =  ( 20/24 + 9/24) xx 2/7 = 29/24 xx 2/7 = 29/84`

` ( 7/6 - 3/4) : 3/5 = ( 14/12 - 9/12) : 3/5 = 5/12 : 3/5 = 5/12 xx 5/3 = 25/36`

` 6/7 xx 2/3 : 5/7 = 6/7 xx 2/3 xx 7/5  = 4/5`

` 1/2 + 3/4 - 5/6 = 6/12 + 9/12 - 10/12 = 5/12`

` ( 5/6 + 3/8) xx 2/7 =  ( 15/24 + 9/24) xx 2/7 = 29/24 xx 2/7 = 29/84`

` ( 7/6 - 3/4) : 3/5 = ( 14/12 - 9/12) : 3/5 = 5/12 : 3/5 = 5/12 xx 5/3 = 25/36`

` 6/7 xx 2/3 : 5/7 = 6/7 xx 2/3 xx 7/5  = 4/5`

a) \(6-2\left(x+4\right)=-4\)

\(\Leftrightarrow6-2x-8=-4\)

\(\Leftrightarrow-2-2x=-4\)

\(\Leftrightarrow-2x=-4+2\)

\(\Leftrightarrow-2x=-2\)

\(\Leftrightarrow x=1\)

Vậy \(x=1\)

b) tự làm.

c) \(2x-15:5=-7\)

\(\Leftrightarrow2x-7,5=-7\)

\(\Leftrightarrow2x=-7+7,5\)

\(\Leftrightarrow2x=0,5\)

\(\Leftrightarrow x=0,25\)

\(\Leftrightarrow x=\dfrac{1}{4}\)

Vậy \(x=\dfrac{1}{4}\)

d) \(231-\left(x-6\right)=1339:13\)

\(\Leftrightarrow231-x+6=103\)

\(\Leftrightarrow237-x=103\)

\(\Leftrightarrow237-x+6=103\)

\(\Leftrightarrow-x=103-237\)

\(\Leftrightarrow-x=-134\)

\(\Leftrightarrow x=134\)

e) đề j mà có 2 dấu bằng >> sai :v

f) \(28-x^3=1\)

\(\Leftrightarrow-x^3=1-28\)

\(\Leftrightarrow-x^3=-27\)

\(\Leftrightarrow x^3=27\)

\(\Leftrightarrow x^3=3^3\)

\(\Leftrightarrow x=3\)

Vậy \(x=3\)

g) \(\left(x+2\right)^3=27\)

\(\Leftrightarrow\left(x+2\right)^3=3^3\)

\(\Leftrightarrow x+2=3\)

\(\Leftrightarrow x=3-2\)

\(\Leftrightarrow x=1\)

Vậy \(x=1\)

h) \(81-\left(x-5\right)^2=56\)

\(\Leftrightarrow-\left(x-5\right)^2=56-81\)

\(\Leftrightarrow-\left(x-5\right)^2=-25\)

\(\Leftrightarrow\left(x-5\right)^2=25\)

\(\Leftrightarrow x-5=\pm5\)

\(\Leftrightarrow\left[{}\begin{matrix}x-5=5\\x-5=-5\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=5+5\\x=-5+5\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=10\\x=0\end{matrix}\right.\)

Vậy \(x_1=0;x_2=10\)

j) \(x^2=9\)

\(\Leftrightarrow x=\pm3\)

\(\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-3\end{matrix}\right.\)

Vậy \(x_1=-3;x_2=3\)

l) tự làm.

1.(18 - 18) x (2 + 8) + ( 4 + 6) + 10 = 30

có rút gọn phân số 35/6 về phân số đc ko ? Nếu có thì mn rút gọn cho mik nhé !

 Ai xong tr tui k cho

khó quá ko làm đc tự đi mà làm

a) \(6-2x-8=-4\Leftrightarrow2x=2\Leftrightarrow x=1\)

b) \(6⋮x\Rightarrow x=\left\{-6;-3;-2;-1;1;2;3;6\right\}\)

c) \(2x-3=-7\Leftrightarrow2x=-4\Leftrightarrow x=-2\)

d) \(231-x+6=103\Leftrightarrow x=124\)

e) hình như sai đề

f) \(x^3=27\Leftrightarrow x=3\)

g) \(x+2=3\Leftrightarrow x=1\)

h) \(\left(x+5\right)^2=25\Leftrightarrow x+5=5\Leftrightarrow x=0\)

i) \(x^2=9\Leftrightarrow\orbr{\begin{cases}x=-3\\x=3\end{cases}}\)

j) \(14⋮\left(x+3\right)\Rightarrow x=\left\{-17;-10;-5;-4;-2;4;11\right\}\)

1: =>3^x=81

=>x=4

2: =>2^x=8

=>x=3

3: =>x^3=2^3

=>x=2

4: =>x^20-x=0

=>x(x^19-1)=0

=>x=0 hoặc x=1

5: =>2^x=32

=>x=5

6: =>(2x+1)^3=9^3

=>2x+1=9

=>2x=8

=>x=4

7: =>x^3=115

=>\(x=\sqrt[3]{115}\)

8: =>(2x-15)^5-(2x-15)^3=0

=>(2x-15)^3*[(2x-15)^2-1]=0

=>2x-15=0 hoặc (2x-15)^2-1=0

=>2x-15=0 hoặc 2x-15=1 hoặc 2x-15=-1

=>x=15/2 hoặc x=8 hoặc x=7

1. Tìm số tự nhiên x biết:

1) \(3^x.3=243\)

\(3^x=243:3\)

\(3^x=81\)

\(3^x=3^4\)

\(\Rightarrow x=4\)

_____

2) \(7.2^x=56\)

\(2^x=56:7\)

\(2^x=8\)

\(2^x=2^3\)

\(\Rightarrow x=3\)

_____

3) \(x^3=8\)

\(x^3=2^3\)

\(\Rightarrow x=3\)

_____

4) \(x^{20}=x\)

\(x^{20}-x=0\)

\(x\left(x^{19}-1\right)=0\)

\(\Rightarrow x=0\) hoặc \(x=1\)

5) \(2^x-15=17\)

\(2^x=17+15\)

\(2^x=32\)

\(2^x=2^5\)

\(\Rightarrow x=5\)

_____

6) \(\left(2x+1\right)^3=9.81\)

\(\left(2x+1\right)^3=729=9^3\)

\(\rightarrow2x+1=9\)

\(2x=9-1\)

\(2x=8\)

\(x=8:2\)

\(\Rightarrow x=4\)

_____

7) \(x^6:x^3=125\)

\(x^3=125\)

\(x^3=5^3\)

\(\Rightarrow x=5\)

_____

8) \(\left(2x-15\right)^5=\left(2x-15\right)^3\)

\(\rightarrow\left(2x-15\right)^5-\left(2x-15\right)^3=0\)

\(\left(2x-15\right)^3.\left[\left(2x-15\right)^2-1\right]=0\)

\(\Leftrightarrow\left\{{}\begin{matrix}\left(2x-15\right)^3=0\\\left(2x-15\right)^2-1=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{15}{2}\\x=7\\x=8\end{matrix}\right.\)

_____

9) \(3^{x+2}-5.3^x=36\)

\(3^x.\left(3^2-5\right)=36\)

\(3^x.\left(9-5\right)=36\)

\(3^x.4=36\)

\(3^x=36:4\)

\(3^x=9\)

\(3^x=3^2\)

\(\Rightarrow x=2\)

_____

10) \(7.4^{x-1}+4^{x+1}=23\)

\(\rightarrow7.4^{x-1}+4^{x-1}.4^2=23\)

\(4^{x-1}.\left(7+4^2\right)=23\)

\(4^{x-1}.\left(7+16\right)=23\)

\(4^{x-1}.23=23\)

\(4^{x-1}=23:23\)

\(4^{x-1}=1\)

\(4^{x-1}=4^1\)

\(\rightarrow x-1=0\)

\(x=0+1\)

\(\Rightarrow x=1\)

Chúc bạn học tốt

a)\(x=\left(\dfrac{3}{56}\cdot\dfrac{28}{9}\right):\dfrac{-3}{7}=\dfrac{1}{6}:\dfrac{-3}{7}=-\dfrac{7}{18}\)

b)\(x=\left(\dfrac{7}{15}\cdot\dfrac{5}{3}\right)+\dfrac{3}{16}=\dfrac{7}{9}+\dfrac{3}{16}=\dfrac{139}{144}\)

c)\(x=\left(\dfrac{5}{6}-\dfrac{2}{5}\right).5=\dfrac{13}{6}\)

d)\(=>x\left(\dfrac{3}{4}-\dfrac{2}{5}\right)=\dfrac{1}{6}\cdot\left(\dfrac{3}{7}+\dfrac{5}{7}\right)\)

\(x\cdot\dfrac{7}{20}=\dfrac{4}{21}=>x=\dfrac{4}{21}\cdot\dfrac{20}{7}=\dfrac{80}{147}\)

1. 

$(5^{1986}-5^{1985}):5^{1985}=5^{1985}(5-1):5^{1985}=5-1=4$

2.

\((7^{846}+7^{847}):7^{846}=7^{846}(1+7):7^{846}=1+7=8\)

3.

\((9^{2018}-3^{4036}):6^{2006}=[(3^2)^{2018}-3^{4036}]:6^{2006}\)

$=(3^{4036}-3^{4036}):6^{2006}=0:6^{2006}=0$

4.

$(7^{80}.8^{70}-56^{70}):56^{70}$

$=[7^{10}(7.8)^{70}-56^{70}]:56^{70}$

$=[7^{10}.56^{70}-56^{70}]:56^{70}$

$=56^{70}(7^{10}-1):56^{70}=7^{10}-1$

5.

$4^{4016}:(4^{4017}-4^{4016})=4^{4016}:[4^{4016}(4-1)]$

$=4^{4016}:4^{4016}:3=1:3=\frac{1}{3}$

6.

$(12^{206}.2^{207}-24^{206}):24^{206}$

$=(12^{206}.2^{206}.2-24^{206}):24^{206}$

$=[(12.2)^{206}.2-24^{206}]:24^{206}$

$=(24^{206}.2-24^{206}):24^{206}$

$=24^{206}(2-1):24^{206}=2-1=1$

7.

$(5^2-24)^{8946}+4^{30}:2^{60}=1^{8946}+(2^2)^{30}:2^{60}$

$=1+2^{60}:2^{60}=1+1=2$

8.

$(37.8^{1007}-7.2^{3021}):8^{1007}=[37.8^{1007}-7.(2^3)^{1007}]:8^{1007}$

$=[37.8^{1007}-7.8^{1007}]:8^{1007}$

$=8^{1007}(37-7):8^{1007}=37-7=30$

a, \(\dfrac{62}{7}.x=\dfrac{29}{90}.\dfrac{3}{56}\)

\(\dfrac{62}{7}.x=\dfrac{29}{1680}\)

\(x=\dfrac{29}{1680}:\dfrac{62}{7}\)

\(x=\dfrac{29}{14880}\)

b, \(\dfrac{1}{5}:x=\dfrac{1}{5}-\dfrac{1}{7}\)

\(\dfrac{1}{5}:x=\dfrac{2}{35}\)

\(x=\dfrac{1}{5}:\dfrac{2}{35}\)

\(x=\dfrac{7}{2}\)

c, \(\left(x+\dfrac{1}{4}-\dfrac{1}{3}\right):\left(2+\dfrac{1}{6}-\dfrac{1}{4}\right)=\dfrac{7}{46}\)

\(\left(x+\dfrac{1}{4}-\dfrac{1}{3}\right):\left(\dfrac{13}{6}-\dfrac{1}{4}\right)=\dfrac{7}{46}\)

\(\left(x+\dfrac{1}{4}-\dfrac{1}{3}\right):\dfrac{23}{12}=\dfrac{7}{46}\)

\(\left(x+\dfrac{-1}{12}\right):\dfrac{23}{12}=\dfrac{7}{46}\)

\(\left(x+\dfrac{-1}{12}\right)=\dfrac{7}{46}.\dfrac{23}{12}\)

\(x+\dfrac{-1}{12}=\dfrac{7}{24}\)

\(x=\dfrac{7}{24}-\dfrac{-1}{12}\)

\(x=\dfrac{3}{8}\)