-8/27 = (-2/3) mũ 3

còn 81/125 chắc đề bài sai

-8/27=(-2/3)^3=-2^3/3^3

còn cái kia mk k bt

\(\dfrac{81}{125}-\dfrac{8}{27}=\dfrac{3^4}{5^3}-\dfrac{2^3}{3^3}\)

\(\frac{9^2}{5^3}\)- \(\frac{2^3}{3^3}\)

\(a:\dfrac{81}{125}=\dfrac{3^4}{5^3}\)

\(b:\dfrac{-8}{27}=-\dfrac{2^3}{3^3}\)

81/125 bằng 81/125 mũ 1

-8/27 bằng -2/3 mũ 3

câu này mink đã được học rồi nên chắc đúng

\(\dfrac{81}{125}=\dfrac{3^4}{5^3}\) ; \(-\dfrac{8}{27}=-\left(\dfrac{2}{3}\right)^3\)

\(\frac{81}{125}\) viết dưới dạng luỹ thừa là : \(\frac{3^4}{5^3}\)

\(-\frac{8}{27}\) viết dưới dạng luỹ thừa là : \(-\frac{2^3}{3^3}\)

0,25 = (0,5)²

\(\dfrac{1}{49}\) = (\(\dfrac{1}{7}\))²

- \(\dfrac{27}{125}\) = (- \(\dfrac{3}{5}\))³

 \(\dfrac{81}{16}\) = ( \(\dfrac{9}{4}\))²

\(\dfrac{169}{196}\) = (\(\dfrac{13}{14}\))²

\(\dfrac{81}{125}=\dfrac{3^4}{5^3}\)

\(\dfrac{-8}{27}=\dfrac{\left(-2\right)^3}{3^3}=\left(\dfrac{-2}{3}\right)^3\)

Ta có:

\(\dfrac{81}{125}=\dfrac{3^4}{5^4}=\left(\dfrac{3}{5}\right)^4\)

\(-\dfrac{8}{27}=-\dfrac{2^3}{3^3}=\left(-\dfrac{2}{3}\right)^3\)

\(\dfrac{81}{125}=\dfrac{3^4}{5^4}=\left(\dfrac{3}{5}\right)^4\)

\(\dfrac{-8}{27}=\dfrac{\left(-2\right)^3}{3^3}=\left(\dfrac{-2}{3}\right)^3\)

Chúc bạn học tốt!

\(\begin{array}{l}0,49 = {\left( {0,7} \right)^2};\\\,\frac{1}{{32}} =\frac{1^5}{2^5}={\left( {\frac{1}{2}} \right)^5};\\\,\frac{{ - 8}}{{125}} =\frac{(-2)^3}{5^3}= {\left( {\frac{{ - 2}}{5}} \right)^3};\end{array}\)

\(\frac{{16}}{{81}} =\frac{4^2}{9^2}= {\left( {\frac{4}{9}} \right)^2} (hoặc \,\frac{{16}}{{81}} =\frac{2^4}{3^4}= {\left( {\frac{2}{3}} \right)^4});\\\,\frac{{121}}{{169}} =\frac{11^2}{13^2}= {\left( {\frac{{11}}{{13}}} \right)^2}\)