a)  \(\frac{6}{5}.{\left( {1,2} \right)^8} = 1,2.{(1,2)^8} = {(1,2)^{1 + 8}} = {(1,2)^9}\)

b) \({\left( {\frac{{ - 4}}{9}} \right)^7}:\frac{{16}}{{81}} = {\left( {\frac{{ - 4}}{9}} \right)^7}:{\left( {\frac{{ - 4}}{9}} \right)^2} = {\left( {\frac{{ - 4}}{9}} \right)^{7 - 2}} = {\left( {\frac{{ - 4}}{9}} \right)^5}\)

a) \({\left( {\frac{8}{9}} \right)^3} \cdot \frac{4}{3} \cdot \frac{2}{3} = {\left( {\frac{8}{9}} \right)^3}.\frac{8}{9} = {\left( {\frac{8}{9}} \right)^{3+1}}={\left( {\frac{8}{9}} \right)^4}\)

b) \({\left( {\frac{1}{4}} \right)^7} \cdot 0,25 = {\left( {0,25} \right)^7}.0,25 ={\left( {0,25} \right)^{7+1}}= {\left( {0,25} \right)^8}\)

c) \({( - 0,125)^6}:\frac{{ - 1}}{8} = {\left( {\frac{{ - 1}}{8}} \right)^6}:\frac{{ - 1}}{8} = {\left( {\frac{{ - 1}}{8}} \right)^{6-1}}= {\left( {\frac{{ - 1}}{8}} \right)^5}\)

d) \({\left[ {{{\left( {\frac{{ - 3}}{2}} \right)}^3}} \right]^2} = {\left( {\frac{{ - 3}}{2}} \right)^{3.2}} = {\left( {\frac{{ - 3}}{2}} \right)^6}\)

3

= 3

3

3

3

3 nhé

3

\(\dfrac{17}{9}+\dfrac{19}{7}-\dfrac{8}{9}-\dfrac{5}{7}\)

\(=\left(\dfrac{17}{9}-\dfrac{8}{9}\right)+\left(\dfrac{19}{7}-\dfrac{5}{7}\right)=1+2=3\)

\(\left(\dfrac{17}{9}-\dfrac{8}{9}\right)+\left(\dfrac{19}{7}-\dfrac{5}{7}\right)=1+2=3\)

\(\frac{1}{7}+\frac{2}{9}+\frac{3}{10}+\frac{7}{9}+\frac{6}{7}+\frac{7}{10}\)

\(=\left(\frac{1}{7}+\frac{6}{7}\right)+\left(\frac{2}{9}+\frac{7}{9}\right)+\left(\frac{3}{10}+\frac{7}{10}\right)\)

\(=\frac{7}{7}+\frac{9}{9}+\frac{10}{10}=1+1+1=3\)

kết quả: 3

kết quả : 3

a) 7-(-9)-3

=7+9+(-3)

=13

b) (-3)+8-11

=(-3)+8+(-11)

=-6

_19/9

19/9

19/9

Đáp án A

\(\dfrac{2}{15}-\dfrac{7}{9}\\ =\dfrac{-29}{45}\\ \dfrac{5}{-12}-\dfrac{-3}{8}\\ =\dfrac{-5}{12}+\dfrac{3}{8}\\ =\dfrac{-1}{24}\)

-29/45; 1/-21 

đấp án đó nhe nhớ tick cho mik

 -29/45

 -1/24