Tìm x:
x^2+5.x<0
giúp mình câu này nhé!!
Tìm x:
X x 2/5 = 4/15
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3.tìm x:x*0,25-72,5=22,2
tìm x:x*3+x*4+x=172
4.tổng 2 số là 68,2; thương 2 số là 4,5.tìm 2 số đó
5.hiệu 2 số là 0,6,thương 2 số cũng la 0,6.tìm 2 số đó
tìm x:
X:1/3=1/2+1/3 (X:2/3):2/5=7/10
x : 1/3 = 1/2 +1/3
=>x:1/3=5/6
=>x=5/6 x 1/3
=>x=5/18
(x:2/3):2/5=7/10
=>x:2/3=7/10 x 2/5
=>x:2/3=7/25
=>x=7/25x2/3
=>x=14/75
CHÚC BẠN HỌC TỐT
tìm x:
X:1/3=1/2+1/3 (X:2/3):2/5=7/10
x:1/3=1/2+1/3
x:1/3=5/6
x =5/6.1/3
x =5/18
(x:2/3):2/5=7/10
x:2/3 =7/10.2/5
x:2/3 =7/25
x:2/3 =7/25.2/3
x:2/3 =14/75
tìm x:
X:1/3=1/2+1/3 (X:2/3):2/5=7/10
Giúp cháuuuuuu!!!!
1) \(x:\dfrac{1}{3}=\dfrac{1}{2}+\dfrac{1}{3}\)
\(\Rightarrow3\times x=\dfrac{5}{6}\Rightarrow x=\dfrac{5}{18}\)
2) \(\left(x:\dfrac{2}{3}\right):\dfrac{2}{5}=\dfrac{7}{10}\)
\(\Rightarrow\dfrac{3}{2}\times x=\dfrac{7}{10}\times\dfrac{2}{5}=\dfrac{7}{25}\)
\(\Rightarrow x=\dfrac{7}{25}:\dfrac{3}{2}=\dfrac{14}{75}\)
X : 1/3 = 1/2 + 1/3
X = 5/18
( X : 2/3 ) : 2/5 = 7/10
X = 14/75
Tìm x:
X x 3/4 = 4/5
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5/9 : x = 8/3
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x = 4/5 : 3/4
x = 16/15
x = 5/9 : 8/3
x = 5/9 x 3/8
x = 5/24
\(x=\dfrac{4}{5}\times\dfrac{4}{3}\)
\(x=\dfrac{16}{15}\)
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\(x=\dfrac{5}{9}\times\dfrac{3}{8}\)
\(x=\dfrac{5}{24}\)
\(x\times\dfrac{3}{4}=\dfrac{4}{5}\)
\(x=\dfrac{4}{5}:\dfrac{3}{4}\)
\(x=\dfrac{4}{5}\times\dfrac{4}{3}\)
\(x=\dfrac{16}{15}\)
\(\dfrac{5}{9}:x=\dfrac{8}{3}\)
\(x=\dfrac{5}{9}:\dfrac{8}{3}\)
\(x=\dfrac{5}{9}\times\dfrac{3}{8}\)
\(x=\dfrac{15}{72}\)
\(x=\dfrac{5}{24}\)
Tìm x:
X:x+9<x×5<20
x:x+9<xX5<20
1+9<xX5<20
10<xX5<20
2X5<xX5<4X5
x=3
tìm x:
x^2+x=12
\(x^2+x=12\)
\(\Rightarrow x^2+x-12=0\)
\(\Rightarrow x\left(x-3\right)+4\left(x-3\right)=0\Rightarrow\left(x-3\right)\left(x+4\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=3\\x=-4\end{matrix}\right.\)
tìm x:
x + x * 1/9 : 1/3 + y : 1/3 = 1/5
\(x+x.\dfrac{1}{3}+3y=\dfrac{1}{5}\)
\(x.\dfrac{4}{3}+3y=\dfrac{1}{5}\)
\(x.\dfrac{4}{3}=\dfrac{1}{5}-3y\)
\(x=\left(\dfrac{1}{5}-3y\right):\dfrac{4}{3}=\dfrac{3}{20}-\dfrac{9y}{4}\)
Tìm X:
X x \(\dfrac{4}{5}=3-\dfrac{2}{5}\)
Một hình chữ nhật có diện tích \(\dfrac{5}{6}\)m²; chiều rộng \(\dfrac{2}{3}\) m. Tính chu vi.
\(x\times\dfrac{4}{5}=3-\dfrac{2}{5}\)
\(x\times\dfrac{4}{5}=\dfrac{13}{5}\)
\(x=\dfrac{13}{5}:\dfrac{4}{5}\)
\(x=\dfrac{13}{5}\times\dfrac{5}{4}\)
\(x=\dfrac{13}{4}\)
Chiều dài HCN là :
\(\dfrac{5}{6}:\dfrac{2}{3}=\dfrac{5}{4}\left(m\right)\)
Chu vi HCN là :
\(\left(\dfrac{5}{4}+\dfrac{2}{3}\right)\times2=\dfrac{23}{6}\left(m\right)\)
Đ/s :...
\(x\times\dfrac{4}{5}=\dfrac{13}{5}\\ x=\dfrac{13}{5}\div\dfrac{4}{5}\\ x=\dfrac{13}{4}\)
\(CD=\dfrac{5}{6}\div\dfrac{2}{3}=\dfrac{5}{4}\\ P=\left(\dfrac{5}{4}+\dfrac{2}{3}\right)\times2=\dfrac{23}{6}\)