\(\dfrac{56}{15}\) .... \(\dfrac{-56}{15}\)
Những câu hỏi liên quan
\(\dfrac{15}{19}\)x\(\dfrac{38}{5}\)<x<\(\dfrac{67}{15}\)+\(\dfrac{56}{15}\)
\(\dfrac{69}{56}\) - \(\dfrac{3}{8}\) .......\(\dfrac{4}{5}\)nhân\(\dfrac{15}{14}\)
\(\dfrac{69}{56}\)- \(\dfrac{3}{8}\)...<...\(\dfrac{4}{5}\)x \(\dfrac{15}{14}\)
Đúng 1
Bình luận (0)
A=\(\dfrac{38}{50}\)+\(\dfrac{9}{20}\)-\(\dfrac{11}{30}\)+\(\dfrac{13}{42}\)-\(\dfrac{15}{56}\)+\(\dfrac{17}{72}\)-...+\(\dfrac{197}{9702}\)-\(\dfrac{199}{9900}\)
Hỗn số \(7\dfrac{8}{9}\) được viết dưới dạng phân số là:
A. \(\dfrac{15}{9}\) B. \(\dfrac{56}{9}\) C. \(\dfrac{71}{9}\)
Xem thêm câu trả lời
Tính
B=\(\dfrac{3}{2}-\dfrac{5}{6}+\dfrac{7}{12}-\dfrac{9}{20}+\dfrac{11}{30}-\dfrac{13}{42}+\dfrac{15}{56}\)
B= \(\dfrac{3}{2}-\dfrac{5}{6}+\dfrac{7}{12}-\dfrac{9}{20}+\dfrac{11}{30}-\dfrac{13}{42}+\dfrac{15}{56}\)
= \(\left(1+\dfrac{1}{2}\right)-\left(\dfrac{1}{2}+\dfrac{1}{3}\right)+\left(\dfrac{1}{3}+\dfrac{1}{4}\right)-\left(\dfrac{1}{4}+\dfrac{1}{5}\right)+\left(\dfrac{1}{5}+\dfrac{1}{6}\right)-\left(\dfrac{1}{6}+\dfrac{1}{7}\right)+\left(\dfrac{1}{7}+\dfrac{1}{8}\right)\)
= 1+\(\dfrac{1}{8}\)=\(\dfrac{9}{8}\)
Đúng 0
Bình luận (0)
8 tháng 2 2022 lúc 9:29
Tính nhanhA dfrac{1}{2} + ^{dfrac{1}{3}} + dfrac{1}{6} + dfrac{1}{12} + dfrac{1}{15} + dfrac{1}{20} + dfrac{1}{25} + dfrac{1}{30} + dfrac{1}{35} + dfrac{1}{42} + dfrac{1}{56} + dfrac{1}{63}Mình đang cần gấp , mong mn giúp mình với ạ
Đọc tiếp
Tính nhanh
A = \(\dfrac{1}{2}\) + \(^{\dfrac{1}{3}}\) + \(\dfrac{1}{6}\) + \(\dfrac{1}{12}\) + \(\dfrac{1}{15}\) + \(\dfrac{1}{20}\) + \(\dfrac{1}{25}\) + \(\dfrac{1}{30}\) + \(\dfrac{1}{35}\) + \(\dfrac{1}{42}\) + \(\dfrac{1}{56}\) + \(\dfrac{1}{63}\)
Mình đang cần gấp , mong mn giúp mình với ạ
quy đòng r tính nha ra \(\dfrac{199}{33}\)
Đúng 0
Bình luận (0)
Cho 2 số dương x,y thỏa mãn x+y≥5
Tìm GTNN của biểu thức
A= \(18x+\dfrac{56}{3}y+\dfrac{4}{x}+\dfrac{15}{y}\)
Min của A là 99 khi (x;y)=(2;3).
Chúc abh học tốt.
Đúng 0
Bình luận (0)
\(A=\left(x+\dfrac{4}{x}\right)+5\left(\dfrac{y}{3}+\dfrac{3}{y}\right)+17\left(x+y\right)\)
\(A\ge2\sqrt{\dfrac{4x}{x}}+5.2\sqrt{\dfrac{3y}{3y}}+17.5=99\)
Dấu "=" xảy ra khi \(\left(x;y\right)=\left(2;3\right)\)
Đúng 2
Bình luận (0)
Tính thuận tiện A=\(\dfrac{3}{2}-\dfrac{5}{6}+\dfrac{7}{12}-\dfrac{9}{20}+\dfrac{11}{30}-\dfrac{13}{42}+\dfrac{15}{56}-\dfrac{17}{72}\)
A = \(\dfrac{3}{2}\) - \(\dfrac{5}{6}\) + \(\dfrac{7}{12}\) - \(\dfrac{9}{20}\) + \(\dfrac{11}{30}\) - \(\dfrac{13}{42}\) + \(\dfrac{15}{56}\) - \(\dfrac{17}{72}\)
A = (1 + \(\dfrac{1}{2}\)) - (\(\dfrac{1}{2}\) + \(\dfrac{1}{3}\)) + (\(\dfrac{1}{3}\) + \(\dfrac{1}{4}\)) - (\(\dfrac{1}{4}\) + \(\dfrac{1}{5}\)) + (\(\dfrac{1}{5}\) + \(\dfrac{1}{6}\)) - (\(\dfrac{1}{6}\) + \(\dfrac{1}{7}\)) + (\(\dfrac{1}{7}\) + \(\dfrac{1}{8}\)) - (\(\dfrac{1}{8}\) + \(\dfrac{1}{9}\))
A = 1 + \(\dfrac{1}{2}\) - \(\dfrac{1}{2}\) - \(\dfrac{1}{3}\) + \(\dfrac{1}{3}\) + \(\dfrac{1}{4}\) - \(\dfrac{1}{4}\) - \(\dfrac{1}{5}\) + \(\dfrac{1}{5}\) + \(\dfrac{1}{6}\) - \(\dfrac{1}{6}\) - \(\dfrac{1}{7}\) + \(\dfrac{1}{7}\) + \(\dfrac{1}{8}\) - \(\dfrac{1}{8}\) - \(\dfrac{1}{9}\)
A = 1 - \(\dfrac{1}{9}\)
A = \(\dfrac{8}{9}\)
Đúng 0
Bình luận (0)
\(A=\left(1+\dfrac{1}{2}\right)-\left(\dfrac{1}{2}+\dfrac{1}{3}\right)+\left(\dfrac{1}{3}+\dfrac{1}{4}\right)-\left(\dfrac{1}{4}+\dfrac{1}{5}\right)+\left(\dfrac{1}{5}+\dfrac{1}{6}\right)-\left(\dfrac{1}{6}+\dfrac{1}{7}\right)+\left(\dfrac{1}{7}+\dfrac{1}{8}\right)-\left(\dfrac{1}{8}+\dfrac{1}{9}\right)\)
\(A=1+\dfrac{1}{2}-\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}+\dfrac{1}{4}-\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{5}+\dfrac{1}{6}-\dfrac{1}{6}-\dfrac{1}{7}+\dfrac{1}{7}+\dfrac{1}{8}-\dfrac{1}{8}-\dfrac{1}{9}\)
\(A=1+\dfrac{1}{9}=\dfrac{10}{9}\)
Đúng 0
Bình luận (0)
Thực hiện phép tính : \(\dfrac{3}{2}-\dfrac{5}{6}-\dfrac{9}{20}-\dfrac{13}{42}+\dfrac{11}{30}+\dfrac{15}{56}+\dfrac{7}{12}\)
\(=\left(\dfrac{3}{2}-\dfrac{5}{6}+\dfrac{7}{12}\right)+\left(-\dfrac{9}{20}+\dfrac{11}{30}\right)+\left(\dfrac{-13}{42}+\dfrac{15}{56}\right)\)
\(=\dfrac{18-10+7}{12}+\dfrac{-27+22}{60}+\dfrac{-1}{24}\)
\(=\dfrac{15}{12}+\dfrac{-5}{60}+\dfrac{-1}{24}\)
\(=\dfrac{30-1+\left(-2\right)}{24}=\dfrac{27}{24}=\dfrac{9}{8}\)
Đúng 0
Bình luận (0)