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Nguyễn Hoàng Châu
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a: \(x^3-9x^2+6x+16\)

\(=x^3-8x^2-x^2+8x-2x+16\)

\(=x^2\left(x-8\right)-x\left(x-8\right)-2\left(x-8\right)\)

\(=\left(x-8\right)\left(x^2-x-2\right)\)

\(=\left(x-8\right)\left(x-2\right)\left(x+1\right)\)

b: \(x^3-x^2-x-2\)

\(=x^3-2x^2+x^2-2x+x-2\)

\(=x^2\left(x-2\right)+x\left(x-2\right)+\left(x-2\right)\)

\(=\left(x-2\right)\cdot\left(x^2+x+1\right)\)

c: \(x^3+x^2-x+2\)

\(=x^3+2x^2-x^2-2x+x+2\)

\(=x^2\left(x+2\right)-x\left(x+2\right)+\left(x+2\right)\)

\(=\left(x+2\right)\left(x^2-x+1\right)\)

d: \(x^3-6x^2-x+30\)

\(=x^3+2x^2-8x^2-16x+15x+30\)

\(=x^2\left(x+2\right)-8x\left(x+2\right)+15\left(x+2\right)\)

\(=\left(x+2\right)\left(x^2-8x+15\right)\)

\(=\left(x+2\right)\left(x-3\right)\left(x-5\right)\)

e: Sửa đề: \(x^3-7x-6\)

\(=x^3-x-6x-6\)

\(=x\left(x^2-1\right)-6\left(x+1\right)\)

\(=x\left(x-1\right)\left(x+1\right)-6\left(x+1\right)\)

\(=\left(x+1\right)\left(x^2-x-6\right)\)

\(=\left(x+1\right)\left(x-3\right)\left(x+2\right)\)

f: \(27x^3-27x^2+18x-4\)

\(=27x^3-9x^2-18x^2+6x+12x-4\)

\(=9x^2\left(3x-1\right)-6x\left(3x-1\right)+4\left(3x-1\right)\)

\(=\left(3x-1\right)\left(9x^2-6x+4\right)\)

g: \(2x^3-x^2+5x+3\)

\(=2x^3+x^2-2x^2-x+6x+3\)

\(=x^2\left(2x+1\right)-x\left(2x+1\right)+3\left(2x+1\right)\)

\(=\left(2x+1\right)\left(x^2-x+3\right)\)

h: \(\left(x^2-3\right)^2+16\)

\(=x^4-6x^2+9+16\)

\(=x^4-6x^2+25\)

\(=x^4+10x^2+25-16x^2\)

\(=\left(x^2+5\right)^2-\left(4x\right)^2\)

\(=\left(x^2+5+4x\right)\left(x^2+5-4x\right)\)

 

Ngọc Thanh
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Tô Mì
15 tháng 11 2021 lúc 15:47

\(x^2-9x-y^2-9y\)

\(=\left(x^2-y^2\right)-\left(9x+9y\right)\)

\(=\left(x-y\right)\left(x+y\right)-9\left(x+y\right)\)

\(=\left(x+y\right)\left(x-y-9\right)\)

Học ngu lắm
Xem chi tiết
Toru
17 tháng 10 2023 lúc 20:53

\(x^3-9x^2+6x+16\\=x^3+x^2-10x^2-10x+16x+16\\=x^2(x+1)-10x(x+1)+16(x+1)\\=(x+1)(x^2-10x+16)\\=(x+1)(x^2-2x-8x+16)\\=(x+1)[x(x-2)-8(x-2)]\\=(x+1)(x-2)(x-8)\\Toru\)

Minh Hiếu
17 tháng 10 2023 lúc 20:52

\(x^3-9x^2+6x+16\)

\(=x^3-8x^2-x^2+8x-2x+16\)

\(=x^2\left(x-8\right)-x\left(x-8\right)-2\left(x-8\right)\)

\(=\left(x^2-x-2\right)\left(x-8\right)\)

\(=\left(x^2+x-2x-2\right)\left(x-8\right)\)

\(=\left(x+1\right)\left(x-2\right)\left(x-8\right)\)

『Kuroba ム Tsuki Ryoo...
17 tháng 10 2023 lúc 20:54

`#3107.101107`

`x^3 - 9x^2 + 6x + 16`

`= x^3 - x^2 - 8x^2 - 2x + 8x + 16`

`= (x^3 - x^2 - 2x) - (8x^2 - 8x - 16)`

`= x(x^2 - x - 2) - 8(x^2 - x - 2)`

`= (x - 8)(x^2 - x - 2)`

`= (x - 8)(x - 2)(x + 1)`

Thanh Huyền
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Nguyễn Hoàng Minh
15 tháng 11 2021 lúc 8:24

\(=x^2-6x+9-2=\left(x-3\right)^2-2=\left(x-3-\sqrt{2}\right)\left(x-3+\sqrt{2}\right)\)

ILoveMath
15 tháng 11 2021 lúc 8:24

\(=\left(x^2-6x+9\right)-2=\left(x-3\right)^2-\sqrt{2^2}=\left(x-3-\sqrt{2}\right)\left(x-3+\sqrt{2}\right)\)

Khánh Quỳnh Lê
15 tháng 11 2021 lúc 8:28

=x2−6x+9−2=(x−3)2−2=(x−3−√2)(x−3+√2)

Hoàng Ngọc Tuyết Nhung
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HeroZombie
18 tháng 8 2017 lúc 17:45

\(x^3+9x^2+6x-16\)

\(=x^3+x^2-2x+8x^2+8x-16\)

\(=x\left(x^2+x-2\right)+8\left(x^2+x-2\right)\)

\(=\left(x^2+x-2\right)\left(x+8\right)\)

\(=\left(x^2-x+2x-2\right)\left(x+8\right)\)

\(=\left[x\left(x-1\right)+2\left(x-1\right)\right]\left(x+8\right)\)

\(=\left(x-1\right)\left(x+2\right)\left(x+8\right)\)

Nguyễn Thị Cẩm Nhung
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titanic
14 tháng 9 2018 lúc 17:01

\(x^3-9x^2+6x+16=x^3-8x^2-x^2+8x-2x+16\)

\(=x^2.\left(x-8\right)-x.\left(x-8\right)-2.\left(x-8\right)\)

\(=\left(x-8\right).\left(x^2-x-2\right)=\left(x-8\right).\left(x^2-2x+x-2\right)\)

\(=\left(x+8\right)\left[x.\left(x-2\right)+\left(x-2\right)\right]\)

\(=\left(x+8\right).\left(x-2\right)\left(x+1\right)\)

kudo shinichi
14 tháng 9 2018 lúc 17:02

\(x^3-9x^2+6x+16\)

\(=\left(x^3+x^2\right)-\left(10x^2+10x\right)+\left(16x+16\right)\)

\(=x^2.\left(x+1\right)-10x\left(x+1\right)+16\left(x+1\right)\)

\(=\left(x+1\right)\left(x^2-10x+16\right)\)

Tham khảo nhé~

Pham Van Hung
14 tháng 9 2018 lúc 17:51

      \(x^3-9x^2+6x+16\)

\(=x^3+x^2-10x^2-10x+16x+16\)

\(=x^2\left(x+1\right)-10x\left(x+1\right)+16\left(x+1\right)\)

\(=\left(x+1\right)\left(x^2-10x+16\right)\)

\(=\left(x+1\right)\left[x^2-2x-8x+16\right]\)

\(=\left(x+1\right)\left[x\left(x-2\right)-8\left(x-2\right)\right]\)

\(=\left(x+1\right)\left(x-2\right)\left(x-8\right)\)

Chúc bạn học tốt.

Nguyễn Văn Thông
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Nguyễn Hoàng Minh
23 tháng 11 2021 lúc 10:59

\(=x^2\left(x-6\right)-24\left(x-6\right)=\left(x^2-24\right)\left(x-6\right)\)

Rin•Jinツ
23 tháng 11 2021 lúc 11:02

\(x^3-6x^2-24x+144=\left(x^3-6x^2\right)-\left(24x-144\right)=x^2\left(x-6\right)-24\left(x-6\right)=\left(x-6\right)\left(x^2-24\right)\)

Hoàng Ngọc Tuyết Nhung
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Nobi Nobita
13 tháng 10 2020 lúc 8:27

\(x^3-9x^2+6x+16=\left(x^3+x^2\right)-\left(10x^2+10x\right)+\left(16x+16\right)\)

\(=x^2.\left(x+1\right)-10x\left(x+1\right)+16\left(x+1\right)\)

\(=\left(x+1\right).\left(x^2-10x+16\right)\)

\(=\left(x+1\right).\left[\left(x^2-8x\right)-\left(2x-16\right)\right]\)

\(=\left(x+1\right)\left[x\left(x-8\right)-2\left(x-8\right)\right]\)

\(=\left(x+1\right)\left(x-2\right)\left(x-8\right)\)

Khách vãng lai đã xóa
Bùi Huy Khôi
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nguyễn Thanh
13 tháng 10 2014 lúc 18:10

x^3-9x^2+6x+16

=x^3+x^2-10x^2-10x+16x+16

=(x^3+x^2)-(10x^2+10x)+(16x+16)

=x^2(x+1)-10x(x+1)+16(x+1)

=(x+1)(x^2-10x+16)

=(x+1)(x^2-2x-8x+16)

=(x+1)[(x^2-2x)-(8x-16)]

=(x+1)[x(x-2)-8(x-2)]

=(x+1)(x-2)(x-8)