1. Tính
a. A= (2.872 x 0.25 + 2.166 : 0.1) x 0.05
b. B= (2-1/4+1/3-3/5)/(3-1/5-5/3) & viết kết quả dưới dạng hỗn số
2. Hai số tự nhiên có tổng là 694. Tìm 2 số biết số lớn chia số bé được thương là 4 dư 64
mk cảm ơn các bn đã lm bài giúp mk
Tính
a. A= (2.872 x 0.25 + 2.166 : 0.1) x 0.05
b. B= (2-1/4+1/3-3/5)/(3-1/5-5/3) & viết kết quả dưới dạng hỗn số
tính
a)1 + 3/4 b)4/5 -3/8 c)1 : 2/3 d)2/5 x 5/2
a, \(1+\dfrac{3}{4}=\dfrac{7}{4}\)
b, \(\dfrac{4}{5}-\dfrac{3}{8}=\dfrac{32-15}{40}=\dfrac{17}{40}\)
c, \(1:\dfrac{2}{3}=\dfrac{1.3}{2}=\dfrac{3}{2}\)
d, \(\dfrac{2}{5}.\dfrac{5}{2}=1\)
a)1 + 3/4=7/4
b)4/5 -3/8=17/40
c)1 : 2/3=3/2
d)2/5 x 5/2=1
Đáp án:
a)1 + 3/4=7/4
b)4/5 -3/8=17/40
c)1 : 2/3=3/2
d)2/5 x 5/2=1
Tính
a) 5/6 x 3/7 + 1/2 =
b) 1/3 : 1/5 - 1 =
c) 4/3 - 1/2 : 3/2=
thực hiện phép tính
a. A = \(\left(-\dfrac{2}{3}x^5+\dfrac{3}{4}x^4y^3-\dfrac{4}{5}x^3y^4\right):\left(-6x^2y^2\right)\)
b.B = \(\dfrac{2a-b}{a+1}-\dfrac{a^2-2a+1}{b-2}:\dfrac{a^2-1}{b^2-4}\)
\(A=\dfrac{x^3}{9y^2}-\dfrac{1}{8}x^2y+\dfrac{2}{15}xy^2\\ B=\dfrac{2a-b}{a+1}-\dfrac{\left(a-1\right)^2}{b-2}\cdot\dfrac{\left(b-2\right)\left(b+2\right)}{\left(a-1\right)\left(a+1\right)}\\ B=\dfrac{2a-b}{a+1}-\dfrac{\left(a-1\right)\left(b+2\right)}{a+1}\\ B=\dfrac{2a-b-\left(a-1\right)\left(b+2\right)}{a+1}\\ B=\dfrac{2a-b-ab-2a+b+2}{a+1}=\dfrac{2-ab}{a+1}\)
Bài 1:Thực hiện phép tính
a,(5-2x)(x+3)-4x(x+2) b,(3x+1)(x-3)-4(x+2)(x-2)
c,3(x-4)(x+3)+(x-5)(x+3) d,2x(x-4)+(3x-1)(2x-5)
Bài 2:Tìm x biết
a,5x(x+3)-(5x+2)(x+3)=7
b,(3x-1)(3x+2)-9(x+2)(x-2)=10
c,(x+1)(2x-5)+2(3-x)(x+2)=7
d,(1-3x)(x+2)+3x(x-5)=8
Tìm x :
a) x : 0.25 + x : 0.1 = 10.3
b) x * 3 : 7.5 + 42.6 = 51.6
c) 4/7 : x * 3/2 + 1/2 = 13/7
3/2 . x + 3/7 = -4/5
-11/12 . x + 0.25 =5/6
(x - 2)2 =1
(2x - 1)3 = -8
\(\dfrac{3}{2}x+\dfrac{3}{7}=-\dfrac{4}{5}\)
\(\Leftrightarrow\dfrac{3}{2}x=-\dfrac{43}{35}\)
\(\Leftrightarrow x=-\dfrac{86}{105}\)
Vậy \(x=-\dfrac{86}{105}\)
\(-\dfrac{11}{12}x+0,25=\dfrac{5}{6}\)
\(\Leftrightarrow-\dfrac{11}{12}x+\dfrac{1}{4}=\dfrac{5}{6}\)
\(\Leftrightarrow-\dfrac{11}{12}x=\dfrac{7}{12}\)
\(\Leftrightarrow x=-\dfrac{7}{11}\)
Vậy \(x=-\dfrac{7}{11}\)
\(\left(x-2\right)^2=1\)
\(\Leftrightarrow\left(x-2\right)^2-1=0\)
\(\Leftrightarrow\left(x-2-1\right)\left(x-2+1\right)=0\)
\(\Leftrightarrow\left(x-3\right)\left(x-1\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x-3=0\\x-1=0\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=3\\x=1\end{matrix}\right.\)
Vậy x = {3; 1}\(\left(2x-1\right)^3=-8\)
\(\Leftrightarrow2x-1=-2\)
\(\Leftrightarrow2x=-1\)
\(\Leftrightarrow x=-\dfrac{1}{2}\)
Vậy \(x=-\dfrac{1}{2}\)
(x - 2)2 = 1
<=>\(\left[{}\begin{matrix}x-2=1\\x-2=-1\end{matrix}\right.< =>\left[{}\begin{matrix}x=3\\x=1\end{matrix}\right.\)
Vậy x = 3; 1
(2x - 1)3 = -8
<=> 2x - 1 = -2
<=> 2x = -1
<=> x = \(\dfrac{-1}{2}\)
Vậy x = \(\dfrac{-1}{2}\)
\(|\) 2,5 - x\(|\) = 1,3
1,6- \(|\)x - 0,2 \(|\)= 0
13x = 169
\(\dfrac{-2}{x}\)=\(\dfrac{-x}{8\dfrac{ }{25}}\)
\(\dfrac{x}{-15}\)=\(\dfrac{-60}{x}\)
\(|\)x\(|\)+0,573=2
1,4 x 15/49 - (4/5+2/3) : 2 và 1/5
3 và 1/3 x X + 16 và 3/4 = -13,25
(2 và 1/5 + 3/5 x X) =3/4
(2.4 x X - 36) : 1 và 5/7 = -1
0.25 : ( 10,3 - 9,8) - 3/4
(3 và 4/5 - 2 x X ) x 1 VÀ 1/3 = 5 và 5 /7
=1,4 x\(\dfrac{15}{49}-\) \(\left(\dfrac{4}{5}+\dfrac{2}{3}\right)\) : 2\(\dfrac{1}{5}\)
= \(\dfrac{3}{7}\) - \(\dfrac{22}{15}\) : \(\dfrac{11}{5}\)
= \(\dfrac{3}{7}\) - \(\dfrac{2}{3}\)
= \(-\dfrac{5}{21}\)
( 2\(\dfrac{1}{5}\) + \(\dfrac{3}{5}\) \(\times\) \(x\)) = \(\dfrac{3}{4}\)
\(\dfrac{11}{5}\) + \(\dfrac{3}{5}\)\(x\) = \(\dfrac{3}{4}\)
\(\dfrac{3}{5}\)\(x\) = \(\dfrac{3}{4}\) - \(\dfrac{11}{5}\)
\(\dfrac{3}{5}\)\(x\) = - \(\dfrac{29}{20}\)
\(x\) = -\(\dfrac{29}{12}\)
3\(\dfrac{1}{3}\) x \(x+16\)\(\dfrac{3}{4}\)= 13,25
\(\dfrac{10}{3}\) x \(x\) + \(\dfrac{67}{4}\) = 13,25
\(\dfrac{10}{3}\) x \(x\) = 13,25 - \(\dfrac{67}{4}\)
\(\dfrac{10}{3}\times x=\) \(\dfrac{103}{28}\)
\(x\) = \(\dfrac{103}{28}:\dfrac{10}{3}\)
\(x=\) \(\dfrac{309}{280}\)
Bài 3 : Tính
a) 11/7 + 3/5 , 4 + 1/9 b) 21/5 - 5/8 , 2 - 11/15
c) 3/19 x 38/9 , 21/5 x 2 c) 7/3 : 4/9 , 12/7 : 3
a) = 76/35 ; 37/9
b) 143/40 ; 19/15
c) 2/3 ; 42/5
d) 21/4 ; 4/7
a, 11/7 + 3/5
= \(\dfrac{11x5}{7x5}+\dfrac{3x7}{5x7}=\dfrac{55}{35}+\dfrac{21}{35}=\dfrac{76}{35}\)
4 + 1/9
= \(\dfrac{4}{1}+\dfrac{1}{9}=\dfrac{4x9}{1x9}+\dfrac{1x1}{9x1}=\dfrac{36}{9}+\dfrac{1}{9}=\dfrac{37}{9}\)
b, 21/5 - 5/8
= \(\dfrac{21x8}{5x8}-\dfrac{5x5}{8x5}=\dfrac{168}{40}-\dfrac{25}{40}=\dfrac{143}{40}\)
2 - 11/15
=\(\dfrac{2}{1}-\dfrac{11}{15}=\dfrac{30}{15}-\dfrac{11}{15}=\dfrac{19}{15}\)
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