D

chắc A

 B đúng hơn

Tổng của 2 số là số bé nhất có 3 chữ số nên tổng 2 số là 100

Gọi 2 số đó là a và b.

suy ra a+b=100 và a:b=1/4

a=1/4xb

thay vào suy ra

1/4xb +b=100

5/4 x b=100

b=100:5/4

b=100 x 4/5

b=80

suy ra a=1/4 x 80=20

Vậy số lớn là 80

gets dressed

washes his face

do morning exercise

do homework

cooks dinner

1. gets dressed

2.washes his face

3 do morning exercise

4. do homework

5.cooks dinner

5A

1B

3C

4D

\(#TyHM\)

15d

16b

17a

18c

19d

20a

21b

22a

\(=lim_{x\rightarrow0}\left(\dfrac{5\cdot x\cdot\left(4x+2\right)}{5\cdot sin5x\cdot\left(\sqrt{4x^2+2x+1}+1\right)}-\dfrac{5\cdot x}{5\cdot sin5x\cdot\left(\sqrt[3]{\left(x+1\right)^2}+\sqrt[3]{x+1}+1\right)}\right)\)\(lim_{x\rightarrow0}\dfrac{\sqrt{4x^2+2x+1}-\sqrt[3]{x+1}}{sin5x}=lim_{x\rightarrow0}(\dfrac{\sqrt{4x^2+2x+1}-1}{sin5x}-\dfrac{\sqrt[3]{x+1}-1}{sin5x})\)\(=lim_{x\rightarrow0}\left(\dfrac{1}{\dfrac{sin5x}{5x}}\cdot\left(\dfrac{4x+2}{(\sqrt{4x^2+2x+1}+1)\cdot5}-\dfrac{1}{5\cdot\left(\sqrt[3]{\left(x+1\right)^2}+\sqrt[3]{x+1}+1\right)}\right)\right)\)(1)

chú ý : \(lim _{x\rightarrow0}\dfrac{1}{\dfrac{sin5x}{5x}}=\dfrac{1}{5}\) 

Hay (1)= \(\dfrac{1}{5}\cdot\left(\dfrac{2}{2\cdot5}-\dfrac{1}{5\cdot3}\right)=\dfrac{2}{75}\)

1033/57

\(...=\dfrac{152}{10}-\dfrac{15}{9}+\dfrac{48}{10}-\dfrac{4}{19}=\dfrac{76}{5}-\dfrac{5}{3}+\dfrac{24}{5}-\dfrac{4}{19}\)

\(=\dfrac{76}{5}-\dfrac{5}{3}+\dfrac{24}{5}-\dfrac{4}{19}=\dfrac{76}{5}+\dfrac{24}{5}-\dfrac{5}{3}-\dfrac{4}{19}\)

\(=\dfrac{100}{5}-\dfrac{5}{3}-\dfrac{4}{19}=20-\dfrac{5}{3}-\dfrac{4}{19}=\dfrac{20.57-5.19-4.3}{57}=\dfrac{1033}{57}\)

15,2 - 15/9 -(-4,8 ) - 4/19

= 15,2 - 15/9 + 4,8 - 4/19

= ( 15,2 + 4,8 ) + ( -15/9 - 4/19 )

= 20 + (-107/57 )

= 1033/57.