\(=\dfrac{1}{10}+\dfrac{1}{12}+\dfrac{1}{15}=\dfrac{6}{60}+\dfrac{5}{60}+\dfrac{4}{60}=\dfrac{15}{60}=\dfrac{1}{4}\)

\(=\dfrac{1.6}{10.6}-\dfrac{\left(-1\right).5}{12.5}+\dfrac{1.4}{15.4}=\dfrac{6}{60}+\dfrac{-5}{60}+\dfrac{4}{60}=\dfrac{5}{60}=\dfrac{1}{12}\)

\(=\dfrac{7}{20}-\dfrac{1}{4}=\dfrac{7}{20}-\dfrac{5}{20}=\dfrac{1}{10}\)

\(\dfrac{7}{20}+\dfrac{-1}{4}=\dfrac{7}{20}+\dfrac{-5}{20}=\dfrac{2}{20}=\dfrac{1}{10}\)

=1/10

giúp em vs ạ

em nên gõ công thức trực quan để đề bài rõ ràng nhé

\(\frac{3}{4}+\frac{-1}{3}+\frac{-5}{18}\)

\(=\frac{5}{12}+\frac{-5}{18}\)

\(=\frac{5}{36}\)

4 câu nè bn

\(\frac{3}{4}+(-\frac{1}{3})+(-\frac{5}{18})\)\(=\frac{3}{4}-\frac{1}{3}-\frac{5}{18}=\frac{27}{36}-\frac{12}{36}-\frac{10}{36}=\frac{27-12-10}{36}=\frac{5}{36}\)

học tốt

mấy câu sau tương tự

1D vì

D trọng âm 2 còn lại trọng âm 1

2A vì

A trọng âm 2 còn lại trọng âm 1

1. D

2. A

D

A

a, Ta có : \(-\dfrac{3}{2}-2x+\dfrac{3}{4}=-2\)

\(\Rightarrow-2x=-2+\dfrac{3}{2}-\dfrac{3}{4}=-\dfrac{5}{4}\)

\(\Rightarrow x=\dfrac{5}{8}\)

Vậy ...

b, Ta có : \(\left(-\dfrac{2}{3}x-\dfrac{3}{5}\right)\left(-\dfrac{3}{2}-\dfrac{10}{3}\right)=\dfrac{2}{5}\)

\(\Rightarrow-\dfrac{29}{6}\left(-\dfrac{2}{3}x-\dfrac{3}{5}\right)=\dfrac{2}{5}\)

\(\Rightarrow-\dfrac{2}{3}x-\dfrac{3}{5}=-\dfrac{12}{145}\)

\(\Rightarrow-\dfrac{2}{3}x=-\dfrac{12}{145}+\dfrac{3}{5}=\dfrac{15}{29}\)

\(\Rightarrow x=-\dfrac{45}{58}\)

Vậy...

- Tham khảo thanh này để đánh nha bạn ;-;

a) Ta có: \(\dfrac{-3}{2}-\dfrac{2x+3}{4}=-2\)

\(\Leftrightarrow\dfrac{-6-2x-3}{4}=-2\)

\(\Leftrightarrow-2x-9=-8\)
\(\Leftrightarrow-2x=1\)

hay \(x=-\dfrac{1}{2}\)

b) Ta có: \(\left(-\dfrac{2}{3}x-\dfrac{3}{5}\right)\left(\dfrac{3}{2}-\dfrac{10}{3}\right)=\dfrac{2}{5}\)

\(\Leftrightarrow\dfrac{-2}{3}x-\dfrac{3}{5}=\dfrac{2}{5}:\dfrac{-11}{6}=-\dfrac{12}{55}\)

\(\Leftrightarrow\dfrac{-2}{3}x=\dfrac{21}{55}\)

hay \(x=-\dfrac{63}{110}\)