tách ra

KHCO3, CaSO4, HNO3, Cu(OH)2, Zn(NO3)2, Fe2O3, HBr, PbCl2, Al2(SO4)3, KOH, Ba3(PO4)2, Al2(CO3)3, CO2, CrO3, AlCl3, Ca(H2PO4)2, N2O3, H2SO4, MgO, H2SO3, Fe(OH)3, MnO2, KBr

\(C+O_2\underrightarrow{t^0}CO_2\) ( Cacbon dioxit) 

\(4P+5O_2\underrightarrow{t^0}2P_2O_5\)( Diphotpho pentaoxit)

\(H_2+\dfrac{1}{2}O_2\underrightarrow{t^0}H_2O\) ( Nước hay dihidro monooxit)

\(4Al+3O_2\underrightarrow{t^0}2Al_2O_3\) ( Nhôm oxit) 

C + O₂ --t^o--> CO₂ (Khí cacbonic)

4P + 5O₂ --t^O--> 2P₂O₅ (đi photpho pentaoxit)

H + O₂ --t^o--> H₂O (Nước)

4Al + 3O₂ --t^o--> 2Al₂O₃ (Nhôm oxit)

C + O2  CO2. Cacbon đioxit.

4P + 5O2  2P2O5. Điphotpho pentaoxit.

2H2 + O2  2H2O. Nước.

4Al + 3O2  2Al2O3. Nhôm oxit.

Bài 8:

\(V_{O_2}=20.100=2000\left(ml\right)=2\left(l\right)\\ a,PTHH:2KMnO_4\rightarrow\left(t^o\right)K_2MnO_4+MnO_2+O_2\\ n_{O_2}=\dfrac{2}{22,4}=\dfrac{5}{56}\left(mol\right)\\ n_{O_2\left(p.ứ\right)}=\dfrac{5}{56}.90\%=\dfrac{9}{112}\left(mol\right)\\ n_{KMnO_4\left(dùng\right)}=\dfrac{9}{112}.2=\dfrac{9}{56}\left(mol\right)\\ \Rightarrow m_{KMnO_4}=\dfrac{9}{56}.158=\dfrac{711}{28}\left(g\right)\\ b,2KClO_3\rightarrow\left(t^o,xt\right)2KCl+3O_2\\ n_{KClO_3}=\dfrac{2}{56}.\dfrac{2}{3}=\dfrac{1}{42}\left(mol\right)\\ m_{KClO_3}=122,5.\dfrac{1}{42}=\dfrac{35}{12}\left(g\right)\)

Bài 1:

\(C+O_2\rightarrow\left(t^o\right)CO_2\)

Tên sản phẩm: Cacbon dioxit/ Khí cacbonic

\(4P+5O_2\rightarrow\left(t^o\right)2P_2O_5\)

Tên sản phẩm: Điphotpho pentaoxit

\(2H_2+O_2\rightarrow\left(t^o\right)2H_2O\)

Tên sản phẩm: Nước

\(4Al+3O_2\rightarrow\left(t^o\right)2Al_2O_3\)

Tên sản phẩm: Nhôm oxit

3Fe + 2O2 -> (t°) Fe3O4

4P + 5O2 -> (t°) 2P2O5

S + O2 -> (t°) SO2

4Al + 3O2 -> (t°) 2Al2O3

\(3Fe+2O_2\rightarrow\left(t^o\right)Fe_3O_4\)

\(4P+5O_2\rightarrow\left(t^o\right)2P_2O_5\)

\(S+O_2\rightarrow\left(t^o\right)SO_2\)

\(4Al+3O_2\rightarrow\left(t^o\right)2Al_2O_3\)

a, 2Cu + O₂ --to--> 2CuO

d, 3Fe + 2O₂ --to--> Fe₃O₄

e, 4Al + 3O₂ --to--> 2Al₂O₃

g, C + O₂ --to--> CO₂

i, 4Al + 3O₂ --to--> 2Al₂O₃

c, 2C₂H₂ + 5O₂ --to--> 4CO₂ + 2H₂O

2C₂H₆ + 7O₂ --to--> 4CO₂ + 6H₂O

2C₃H₃O + 8O₂ --to--> 6CO₂ + 6H₂O

h, 2Zn + O₂ --to--> 2ZnO

a)

\(3Fe+2O_2\underrightarrow{t^o}Fe_3O_4\)

\(C+O_2\underrightarrow{t^o}CO_2\)

\(2Mg+O_2\underrightarrow{t^o}2MgO\)

\(S+O_2\underrightarrow{t^o}SO_2\)

b) 

\(2C_2H_2+5O_2\underrightarrow{t^o}4CO_2+2H_2O\)

\(H_2S+\dfrac{3}{2}O_2\underrightarrow{t^o}SO_2+H_2O\)

\(2FeS+\dfrac{7}{2}O_2\underrightarrow{t^o}Fe_2O_3+2SO_2\)

\(a,3Fe+2O_2\rightarrow\left(t^o\right)Fe_3O_4\\ C+O_2\rightarrow\left(t^o\right)CO_2\\ 2Mg+O_2\rightarrow\left(t^o\right)2MgO\\ S+O_2\rightarrow\left(t^o\right)SO_2\\ b,2C_2H_2+5O_2\rightarrow\left(t^o\right)4CO_2+2H_2O\\ 2H_2S+3O_2\rightarrow\left(t^o\right)2SO_2+2H_2O\\ 4FeS+7O_2\rightarrow\left(t^o\right)2Fe_2O_3+4SO_2\)

a. 

\(3Fe+2O_2\rightarrow\left(t^o\right)Fe_3O_4\)

\(C+O_2\rightarrow\left(t^o\right)CO_2\)

\(Mg+\dfrac{1}{2}O_2\rightarrow\left(t^o\right)MgO\)

\(S+O_2\rightarrow\left(t^o\right)SO_2\)

b.

\(C_2H_2+\dfrac{5}{2}O_2\rightarrow\left(t^o\right)2CO_2+H_2O\)

\(2H_2S+3O_2\rightarrow\left(t^o\right)2SO_2+2H_2O\)

\(4FeS+7O_2\rightarrow\left(t^o\right)2Fe_2O_3+4SO_2\)

a)\(2Cu+O_2\underrightarrow{t^o}2CuO\)

   \(4Al+3O_2\underrightarrow{t^o}2Al_2O_3\)

   \(S+O_2\underrightarrow{t^o}SO_2\)

   \(C_4H_{10}+\dfrac{13}{2}O_2\underrightarrow{t^o}4CO_2+5H_2O\)

b)Gọi CTHH là \(Fe_xO_y\)

\(x:y=\dfrac{m_{Fe}}{56}:\dfrac{m_O}{16}=\dfrac{7}{56}:\dfrac{3}{16}=0,125:0,1875=2:3\)

\(\Rightarrow\left\{{}\begin{matrix}x=2\\y=3\end{matrix}\right.\Rightarrow Fe_2O_3\)

\(a,2Fe+3Cl_2\buildrel{{t^o}}\over\to 2FeCl_3\\ 2:3:2\\ b,4Al+3O_2\buildrel{{t^o}}\over\to 2Al_2O_3\\ 4:3:2\\ c,2H_2+O_2\buildrel{{t^o}}\over\to 2H_2O\\ 2:1:2\\ d,CuO+CO\buildrel{{t^o}}\over\to Cu+CO_2\\ 1:1:1:1\\ e,2Na+2H_2O\to 2NaOH+H_2\\ 2:2:2:1 \)