Tìm x biết:
a, ( 2 4/5 x -50 ):2/3 =51
Tìm số tự nhiên x,biết:
a)58 + 7x = 100
b) ( x –12):12=12
c) x -56 : 4= 16
d) 101 +(36 –4x) =105
e) 2(x-51) = 2.23+ 20
f) 10 -(x –3): 2 = 72–110
g) 2x –49 = 5.32h) [(8x -12) : 4].33= 36
i) 52x –3–2 . 52= 52. 3 k) (x3–7) : 4 = 5
a: 7x+58=100
nên 7x=42
hay x=6
c: x-56:x=16
nên x-14=16
hay x=30
c)x - 56 : 4 = 16
x - 56 = 16 : 4
x- 56 = 4
x =4 + 56
x = 60
d)101 + (36 - 4x) = 105
(36- 4x ) = 105 - 101
36 - 4x = 4
4x = 36 - 4
4x = 32
x = 32:4
x = 8
a) 58 + 7x = 100
7x = 100 - 58
7x = 42
x = 42 : 7
x = 6
b) (x - 12) : 12 = 12
x - 12 = 12 . 12
x - 12 = 144
x = 144 + 12
x = 156
Tìm số tự nhiên x, biết:
a, 2(x - 51) = 2.23+20
b, 2x - 49 = 5.32
c, [(8x - 12) : 4].33 = 36
d, 2x+1- 22 = 32
e, (x3 - 77): 4 = 5
a: \(2\left(x-51\right)=2\cdot2^3+20\)
=>\(2\left(x-51\right)=2^4+20=36\)
=>x-51=36/2=18
=>x=18+51=69
b: \(2x-49=5\cdot3^2\)
=>\(2x-49=5\cdot9=45\)
=>2x=45+49=94
=>x=94/2=47
c: \(\left[\left(8x-12\right):4\right]\cdot3^3=3^6\)
=>\(\left[4\cdot\dfrac{\left(2x-3\right)}{4}\right]=3^3\)
=>\(2x-3=3^3=27\)
=>2x=3+27=30
=>x=30/2=15
d: \(2^{x+1}-2^2=32\)
=>\(2^{x+1}=32+2^2=32+4=36\)
=>\(x+1=log_236\)
=>\(x=log_236-1\)
e: \(\left(x^3-77\right):4=5\)
=>\(x^3-77=20\)
=>\(x^3=77+20=97\)
=>\(x=\sqrt[3]{97}\)
Bài 3. Tìm số tự nhiên x, biết:
a) 150 – x = - 9 b) 4(x – 3) = 48 c) 71 – (33 + x) = 26 d) 2(x – 51) = 2.23 + 20 e) 450 : (x – 19) = 50 f) 135 – 5(x + 4) = 35 g) (15 – 6x). 35 = 36 | h) 32(x + 4) – 52 = 5.22 i) 4 – ( 7 – x) = 2x – ( 13 – 4) k) ( 7 – x) – ( 25 + 7 ) = - 25 l) 7x – x = 521 : 519 + 3.22 – 70 m) 2x+1 – 2 = 14 o) 4x + 4x+1 = 320 p) ( 2x +1)3 = 125 q) (x - 2)2 = ( x – 2)5 |
a) 150- x = -9
x = 150 -(-9)
x=150+9
x=159
b)4 (x-3)=48
x-3=48÷4
x-3=12
x=12+3
x=15
Bài 1: Tìm số nguyên x, biết:
a)\(\dfrac{6}{x-3}\) = \(\dfrac{2}{3}\)
b) \(\dfrac{14}{13}\) = \(\dfrac{-28}{10-x}\)
c) \(\dfrac{1}{5}\) = \(\dfrac{x:4-1}{10}\)
d) \(\dfrac{x}{4}\)= \(\dfrac{1}{x}\)
e) \(\dfrac{x-2}{50}\) = \(\dfrac{2}{x-2}\)
giúp ưm
a: =>x-3=9
=>x=12
b: =>10-x=-26
=>x=36
c: =>x:4-1=2
=>x:4=3
=>x=12
d: =>x^2=4
=>x=2 hoặc x=-2
e: =>(x-2)^2=100
=>x-2=10 hoặc x-2=-10
=>x=12 hoặc x=-8
Bài 4. Tìm số nguyên x , biết:
a) |x - 2|= 0 b) |x + 3|= 1 c) -3 |4 - x|= -9 d) |2x + 1|= -2
Bài 5. Tìm số nguyên x, biết:
a) (x + 3)mũ 2 = 36 b) (x + 5)mũ 2 =100 c) (2x - 4)mũ 2 = 0 d) (x - 1)mũ 3 = 27
tìm x biết
( 2 4/5 . x - 50 ) : 2/3 = 51
\(\left(2\frac{4}{5}.x-50\right):\frac{2}{3}=51\)
\(\Leftrightarrow\)\(\frac{14}{5}.x-50=51.\frac{2}{3}=34\)
\(\Leftrightarrow\)\(\frac{14}{5}x=34+50=84\)
\(\Leftrightarrow\)\(x=84:\frac{14}{5}=30\)
Vậy....
\(\left(2\frac{4}{5}x-50\right):\frac{2}{3}=51\)
\(\left(\frac{14}{5}x-50\right)=51\times\frac{2}{3}\)
\(\left(\frac{14}{5}x-50\right)=34\)
\(\frac{14}{5}x=34+50\)
\(\frac{14}{5}x=84\)
\(x=84:\frac{14}{5}\)
\(x=30\)
(24/5 . x - 50) : 2/3 = 51
(24/5 . x - 50) = 51 x 2/3 = 34
24/5 . x = 34 + 50 = 84
x = 84 : 24/5 = 35/2
Đáp số: 35/2
tìm x: biết :
( 2 4/5 .X-50) :2/3 = 51
2/3 X = 5/12
-2/3 X + 1/5 = 3/10
5 4/7 : X =13
\(2\frac{4}{5}.x-50:\frac{2}{3}=51\)
\(\frac{14}{5}.x-50:\frac{2}{3}=51\)
\(\frac{14}{51}.x=51+50:\frac{2}{3}\)
\(\frac{14}{51}.x=51+75\)
\(\frac{14}{51}.x=126\)
\(x=126:\frac{14}{51}\)
x=459
Vậy x=459
\(\frac{2}{3}.x=\frac{5}{12}=>x=\frac{5}{12}:\frac{2}{3}=\frac{5.3}{12.2}=\frac{15}{24}\)=\(\frac{3}{8}\)
vậy x=3/8
\(-\frac{2}{3}.x+\frac{1}{5}=\frac{3}{10}nên-\frac{2}{3}.x=\frac{3}{10}-\frac{1}{5}\)
\(-\frac{2}{3}x=\frac{1}{10}nênx=\frac{1}{10}:-\frac{2}{3}=-\frac{3}{20}\)
Vậy x=-3/20
tìm x biết:
a/2*(x^4+3)-(-9)=17
b/5^2*x+1-3*4^2=-47
2(x4+3)-(9)=17
⇒2x4+6+9=17
⇒2x4+15=17
⇒ 2x4=2
⇒ x4=1
⇒ x=\(\pm1\)
b) 5x2.x+1-3.42=-47
⇒5x3+1-48=-47
⇒5x3-47=-47
⇒5x3=0
⇒x3=0
⇒x=0
a) \(2\left(x^4+3\right)-\left(-9\right)=17\)
\(2x^4+6+9=17\)
\(2x^4=2\)
\(x^4=1\)
⇒ \(x=1\)
a) 2*(x⁴+3)-(-9)=17
=>2x⁴+2*3+9=17
=>2x⁴+6=17-9=8
=>2x⁴=8-6=2
=>x⁴=2/2=1
=>x=1
Tìm x biết:
a)3x(x-5)+2(5-x)=0
b)(x+2)^3-x^2(x-6)=4
a) \(\Rightarrow3x\left(x-5\right)-2\left(x-5\right)=0\)
\(\Rightarrow\left(x-5\right)\left(3x-2\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=5\\x=\dfrac{2}{3}\end{matrix}\right.\)
b) \(\Rightarrow x^3+6x^2+12x+8-x^3+6x^2=4\)
\(\Rightarrow12x^2+12x+4=0\)
\(\Rightarrow x\in\varnothing\)(do \(12x^2+12x+4=12\left(x^2+x+\dfrac{1}{4}\right)+1=12\left(x+\dfrac{1}{2}\right)^2+1\ge1>0\))