C

\(\left(4xy^2-6x^2y+8x^2y^2\right):\left(2xy\right)-3y\\ =\left(4xy^2:2xy-6x^2y:2xy+8x^2y^2:2xy\right)-3y\\ =2y-3x+4xy-3y=-y-3x+4xy\)

293717+65218=358935

293717+65218=358935

= 358935

\(c,\overline{735a2b}⋮̸2;⋮5\Rightarrow b=5\\ \Rightarrow\overline{735a25}⋮9\\ \Rightarrow7+3+5+a+2+5⋮9\\ \Rightarrow22+a⋮9\\ \Rightarrow a=5\\ \Rightarrow\overline{735a2b}=735525\\ b,\overline{5a27b}⋮2;⋮5\Rightarrow b=0\\ \Rightarrow\overline{5a270}⋮9\\ \Rightarrow5+a+2+7+0⋮9\\ \Rightarrow14+a⋮9\\ \Rightarrow a=4\\ \Rightarrow\overline{5a27b}=54270\)

c) \(735525\)
d) \(54270\)

\(2022\times2005-2000\times2022+15\times2022-20\times2021\)

\(=2022\times\left(2005-2000+15\right)-20\times2021\)

\(=2022\times20-20\times2021\)

\(=20\times\left(2022-2021\right)\)

\(=20\times1\)

\(=20\)

a, 2022 \(\times\) 2005 - 2000 \(\times\) 2022 + 15 \(\times\) 2022 - 20 \(\times\) 2021

= (2022  \(\times\) 2005 - 2000 \(\times\) 2022 + 15 \(\times\) 2022 )- 20 \(\times\) 2021

= 2022 \(\times\) (2005 - 2000 + 15) - 20  \(\times\) 2021

= 2022 \(\times\) (5 +15)  - 20 \(\times\) 2021

= 2022 \(\times\) 20 - 20 \(\times\) 2021

= 20 \(\times\) (2022 - 2021)

= 20 \(\times\) 1

= 20 

She went to the supermarket yesterday.

We didn't go to school last week.

9. She went to the supermarket yesterday.

10. We didn't go to school last week.

She went to the supermarket yesterday

We didn't go to school last week

\(P=\left(\dfrac{x^2+1}{x^2-9}-\dfrac{x}{x+3}+\dfrac{5}{3-x}\right):\left(\dfrac{2x+10}{x+3}-1\right)\)

\(=\left(\dfrac{x^2+1}{\left(x-3\right)\left(x+3\right)}-\dfrac{x\left(x-3\right)}{\left(x-3\right)\left(x+3\right)}-\dfrac{5\left(x+3\right)}{\left(x-3\right)\left(x+3\right)}\right):\left(\dfrac{2x+10}{x+3}-\dfrac{x+3}{x+3}\right)\)

\(=\left(\dfrac{x^2+1-x^2+3x-5x-15}{\left(x-3\right)\left(x+3\right)}\right):\left(\dfrac{2x+10-x-3}{x+3}\right)\)

\(=\left(\dfrac{-2x-14}{\left(x-3\right)\left(x+3\right)}\right):\left(\dfrac{x+7}{x+3}\right)\)

\(=\dfrac{-2\left(x+7\right)}{\left(x-3\right)\left(x+3\right)}.\dfrac{x+3}{x+7}\)

\(=\dfrac{-2}{x-3}\)

đk : x khác -3 ; 3 ; -7 

\(P=\left(\dfrac{x^2+1+x\left(x-3\right)+5x+15}{x^2-9}\right):\left(\dfrac{2x+10-x-3}{x+3}\right)\)

\(=\dfrac{2x^2+1+2x+15}{x^2-9}:\dfrac{x+7}{x+3}=\dfrac{2x^2+2x+16}{\left(x-3\right)\left(x+7\right)}\)

6, \(\Rightarrow-2\left(x-3\right)-8=5\left(x+2\right)\Leftrightarrow-2x-2=5x+10\)

\(\Leftrightarrow7x=-12\Leftrightarrow x=-\dfrac{12}{7}\)

7, \(\Rightarrow6\left(2x+1\right)-5\left(x+6\right)=5-4x\Leftrightarrow7x-24=5-4x\)

\(\Leftrightarrow11x=29\Leftrightarrow x=\dfrac{29}{11}\)

8, \(\Rightarrow35-15x-10-2x=10\Leftrightarrow25-17x=10\Leftrightarrow x=\dfrac{15}{17}\)

6: \(\Leftrightarrow-2\left(x-3\right)-8=5x+10\)

=>5x+10=-2x+6-8

=>5x+10=-2x-2

=>7x=-12

hay x=-12/7

7: \(\Leftrightarrow6\left(2x+1\right)-5\left(x+6\right)=5-4x\)

=>12x+6-5x-30-5+4x=0

=>11x-29=0

hay x=29/11

8: \(\Leftrightarrow5\left(7-3x\right)-2\left(x+5\right)=10\)

=>35-15x-2x-10=10

=>-17x=-15

hay x=15/17

\(\dfrac{-x+3}{2}-2=\dfrac{5x+10}{4}\)

\(\dfrac{-x-1}{2}=\dfrac{5x+10}{4}\)

\(-4x-4=10x+20\)

\(-14x=24\)

\(x=\dfrac{24}{-14}=-\dfrac{12}{7}\)

chắc là ;Ngăn cách các vế câu trong câu ghép.