mở bài là giới thiệu về cụ nha mn em viết lộn ạ 

thân bài là đóng góp ạ 

a) ĐKXĐ: \(2x-3\ge0\Rightarrow x\ge\dfrac{3}{2}\)

b) ĐKXĐ: \(-\dfrac{2}{x}+5\ge0\Rightarrow x\ge\dfrac{2}{5}\)

c)ĐKXĐ: \(-3x-5>0\Rightarrow x>-\dfrac{5}{3}\)

d) ĐKXĐ: \(4x^2-4x+1\ge0\Rightarrow\left(2x-1\right)^2\ge0\) (luôn đúng)

a: ĐKXĐ: \(x\ge\dfrac{2}{3}\)

c: ĐKXĐ: \(x< -\dfrac{5}{3}\)

d: ĐKXĐ: \(x\in R\)

e: ĐKXĐ: \(x< -\dfrac{1}{2}\)

f: ĐKXĐ: \(x\ne-1\)

g: ĐKXĐ: \(x\in R\)

h: ĐKXĐ: \(x>-\dfrac{1}{2}\)

b: ĐKXĐ: \(\left\{{}\begin{matrix}x\le\dfrac{2}{5}\\x\ne0\end{matrix}\right.\)

Refer

1. “Your cousin speaks English very well” Paul told me

Paul said that ___________my cousin spoke English very well____________

2. “The man broke out of prison yesterday” said the policeman

The policeman told us_that the man had broken out of prison the day beforr__

3. “I’ll lend you this book as soon as I finish it” Owen said to me

Owen said __me that he would lend me that book as soon as he finished it___

4. “I think I forgot to turn off the lights this morning” Brenda told Brian

Brenda told Brian ____that he thought he had forgotten to turn off the lights that morning.____

5. “I work eight hours a day, except when the children are on holiday” said Mrs. Wood

Mrs. Wood said me that he worked eight hours a day, excepted when the children were on holiday

6. “You’ve been making good progress this semester” Miss Lynn told me

Miss Lynn said that _____I had been making good progress that semester_________

7. “If you bought all the tickets, you would win the lottery” the man said

The man told me ______that If I had bought all the tickets, I would win the lottery______________

8. “I like swimming but I don’t go very often” Jill said to Pam

Jill said that ______he liked swimming but he didn’t go very often___________________________

9. “I want to buy it, but I haven’t brought any money” said Patrick

Patrick told me _________that he wanted to buy it, but he hadn’t brought any money_______________________

10. “I’m going to visit my aunt in Hue, but I’m not sure when” said Mai

Mai told me _________that she was going to visit her aunt in Hue, but she was not sure when__________________

Đăng tách ra đi bạn

Bài 5: 

Theo đề, ta có:

\(\left(2x+5\right)^2-4x^2-12x=41\)

\(\Leftrightarrow20x-12x=41+25=66\)

hay \(x=8.25\left(m\right)\)

Chu vi là:

\(\left[\left(2\cdot8.25+5\right)^2+\left(4\cdot8.25^2+12\cdot8.25\right)\right]\cdot2=1667\left(m\right)\)

Bài 3: 

a: Ta có: \(A=\left(2a+3\right)^2-13\left(a+1\right)\left(a-1\right)+\left(3a-2\right)^2\)

\(=4a^2+12a+9+9a^2-12a+4-13\left(a^2-1\right)\)

\(=13a^2+13-13a^2+13\)

=26

b: Ta có: \(B=\left(4x-1\right)^3-\left(4x-3\right)\left(16x^2+3\right)\)

\(=64x^3-48x^2+12x-1-64x^3-12x+48x^2+9\)

=8

Bài 5.

Thời gian vật rơi cả quãng đường:

\(t=\sqrt{\dfrac{2S}{g}}=\sqrt{\dfrac{2\cdot125}{10}}=5s\)

Vạn tốc vật khi chạm đất:

\(v=g\cdot t=10\cdot5=50\)m/s

Quãng đường đi trong 4s đầu:

\(S'=\dfrac{1}{2}gt^{'2}=\dfrac{1}{2}\cdot10\cdot4^2=80m\)

Quãng đường vật đi trong 1s cuối:

\(S=125-80=45m\)

\(a,A=0,2\left(5x-1\right)-\dfrac{1}{2}\left(\dfrac{2}{3}x+4\right)+\dfrac{2}{3}\left(3-x\right)\)

\(=x-0,2-\dfrac{1}{3}x-2+2-\dfrac{2}{3}x\)

\(=\left(-0,2-2+2\right)+\left(x-\dfrac{1}{3}x-\dfrac{2}{3}x\right)\)

\(=-0,2\)

\(b,B=\left(x-2y\right)\left(x^2+2xy+4y^2\right)-\left(x^3-8y^3+10\right)\)

\(=x^3-8y^3-x^3+8y^3-10\)

\(=-10\)

\(c,C=4\left(x+1\right)^2+\left(2x-1\right)^2-8\left(x-1\right)\left(x+1\right)-4x\)

\(=4\left(x^2+2x+1\right)+\left(4x^2-4x+1\right)-8\left(x^2-1\right)-4x\)

\(=4x^2+8x+4+4x^2-4x+1-8x^2+8-4x\)

\(=13\)

a) \(A=0,2\left(5x-1\right)-\dfrac{1}{2}\left(\dfrac{2}{3}x+4\right)+\dfrac{2}{3}\left(3-x\right)\)

\(A=x-\dfrac{1}{5}-\dfrac{1}{3}x-2+2-\dfrac{2}{3}x\)

\(A=\left(x-\dfrac{1}{3}x-\dfrac{2}{3}x\right)-\left(\dfrac{1}{5}+2-2\right)\)

\(A=-\dfrac{1}{5}\)

Vậy: ...

b) \(B=\left(x-2y\right)\left(x^2+2xy+4y^2\right)-\left(x^3-8y^3+10\right)\)

\(B=\left[x^3-\left(2y\right)^3\right]-\left[x^3-\left(2y\right)^3\right]-10\)

\(B=-10\)

Vậy: ...

c) \(4\left(x+1\right)^2+\left(2x-1\right)^2-8\left(x+1\right)\left(x-1\right)-4x\)

\(=4\left(x^2+2x+4\right)+\left(4x^2-4x+1\right)-8\left(x^2-1\right)-4x\)

\(=4x^2+8x+4+4x^2-4x+1-8x^2+8-4x\)

\(=\left(4x^2+4x^2-8x^2\right)+\left(8x-4x-4x\right)+\left(4+1+8\right)\)

\(=13\)

Vậy:...

=x−0,2−13x−2+2−23x=�−0,2−13�−2+2−23�

1) Áp dụng định lí Pytago vào ΔABC vuông tại A, ta được:

\(BC^2=AB^2+AC^2\)

\(\Leftrightarrow BC^2=6^2+8^2=100\)

hay BC=10(cm)

Áp dụng hệ thức lượng trong tam giác vuông vào ΔABC vuông tại A có AH là đường cao ứng với cạnh huyền BC, ta được:

\(AH\cdot BC=AB\cdot AC\)

\(\Leftrightarrow AH\cdot10=6\cdot8=48\)

hay AH=4,8(cm)