a,   (-2).(-5).(-6).15

      =  10.  -60

      =    -600

a; = -30 . 30

=-900

b; = 28 . 22

= 616

bạn pham minh quang làm sai bước 3

a, 

15.(-2).(-5).(-6)

=  (-30).(-5).(-6)

=  150 . (-6)

= -900

b,    

4.7.(-11).(-2)

= 28 .(-11).(-2)

= (-308) . (-2)

= 616

Thực hiện các phép tính :

a) 15.(-2).(-5).(-6)

= 15. (-6). (-2). (-5)

= -90. 10

= -900

b)4.7.(-11).(-2)

= 28. 22

= 616

\(a) 15.(-2).(-5).(-6) \)

\(= [15.(-2)].(-5).(-6)\)

\(= [(- 30) . (-5)].(-6)\)

\(= 150 . (-6)\)

\(= -900\)

\(b)4.7.(-11).(-2)\)

\(= (4.7).(-11).(-2) \)

\(= 28.(-11).(-2)\)

\(= -308.(-2)\)

\(= 616\)

a)\(15.\left(-2\right).\left(-5\right).\left(-6\right)=\left(-30\right).30=\left(-900\right)\)

\(15.\left(-2\right).\left(-5\right).\left(-6\right)\)

\(=\left[15.\left(-2\right)\right].\left[\left(-5\right).\left(-6\right)\right]\)

\(=-30.30\)

\(=-900\)

\(4.7.\left(-11\right).\left(-2\right)\)

\(=28.\left(-11\right).\left(-2\right)\)

\(=\left[28.\left(-2\right)\right].\left(-11\right)\)

\(=\left(-56\right).\left(-11\right)\)

\(=616\)

a: Ta có: \(\sqrt{4+\sqrt{15}}\)

\(=\dfrac{\sqrt{8+2\sqrt{15}}}{\sqrt{2}}\)

\(=\dfrac{\sqrt{5}+\sqrt{3}}{\sqrt{2}}=\dfrac{\sqrt{10}+\sqrt{6}}{2}\)

b: Ta có: \(\left(3-\sqrt{2}\right)\cdot\sqrt{11+6\sqrt{2}}\)

\(=\left(3-\sqrt{2}\right)\left(3+\sqrt{2}\right)\)

=9-2

=7

c: Ta có: \(\left(\sqrt{7}+\sqrt{5}\right)\cdot\sqrt{12-2\sqrt{35}}\)

\(=\left(\sqrt{7}+\sqrt{5}\right)\left(\sqrt{7}-\sqrt{5}\right)\)

=2

Bài giải:

a) 15 . (-2) . (-5) . (-6) = [15 . (-6)] . [(-2) . (-5)] = (-90) . 10 = -900.

b) 4 . 7 . (-11) . (-2) = [4 . 7 . (-2)] . (-11) = (-56) . (-11) = 616.

a ) 15 . ( -2 ) . ( -5 ) . ( -6 )

= [ 15 . ( -6 ) ] . [ ( -2) . ( -5 )]

= -60 . 10

= -600

b ) 4 . 7 . ( -11 ) . ( - 2 )

= ( 4 . 7) . [ -11 . ( - 2 ) ]

= 28 . 22

= 616

A. 15. (-2) . (-5). (-6) = -900

B. 4. 7 . (-11). (-2) = 616

A) 15.(-2).(-5).(-6)= \(\left[15.\left(-6\right)\right]\) . \(\left[\left(-2\right).\left(-5\right)\right]\)= (-90).10= -900

B)4.7.(-11).(-2)=(4. 7). \(\left[\left(-11\right).\left(-2\right)\right]\) =28. 22= 616

`@` `\text {Ans}`

`\downarrow`

`1,`

`a)`

`-7/25 + (-8)/25`

`= (-7 - 8)/25`

`= -15/25`

`= -3/5`

`b)`

`6/13 + (-15)/39`

`= 18/39 + (-15)/39`

`= (18 - 15)/39`

`= 3/39`

`= 1/13`

`c)`

`5/7 + 4/(-14)`

`= 10/14 + (-4)/14`

`= (10 - 4)/14`

`= 6/14`

`= 3/7`

`d)`

`-8/18 + (-15)/27`

`= -4/9 + (-5)/9`

`= (-4-5)/9`

`= -9/9 = -1`

`2,`

`a)`

`3/5 + (-7)/4`

`= 12/20 + (-35)/20`

`= (12 - 35)/20`

`=-23/20`

`b)`

`(-2) + (-5)/8`

`= (-16)/8 + (-5)/8`

`= (-16 - 5)/8`

`= -21/8`

`c)`

`1/8 + (-5)/9`

`= 9/72 + (-40)/72`

`= (9-40)/72`

`= -31/72`

`d)`

`6/13 + (-14)/39`

`= 18/39 + (-14)/39`

`= (18 - 14)/39`

`= 4/39`

`e)`

`(-18)/24 + 15/21`

`= (-3)/4 + 5/7`

`= (-21)/28 + 20/28`

`= (-21 + 20)/28`

`= -1/28`

a) 15.(- 2).(-5).(-6)                                      b) 4.7.(-11).(- 2)

=15.(-6).(- 2).(-5)                                        = 28 .  22 = 616

=-90    .     10 = -900

a) -900

=[15.(-6)].[(-2).(-5)]=-90.10= -900

b) 616

\(a,\sqrt{8+2\sqrt{15}}-\sqrt{8-2\sqrt{15}}\\ =\sqrt{\sqrt{5^2}+2\sqrt{5}.\sqrt{3}+\sqrt{3^2}}-\sqrt{\sqrt{5^2}-2\sqrt{5}.\sqrt{3}+\sqrt{3^2}}\\ =\sqrt{\left(\sqrt{5}+\sqrt{3}\right)^2}-\sqrt{\left(\sqrt{5}-\sqrt{3}\right)^2}\\ =\left|\sqrt{5}+\sqrt{3}\right|-\left|\sqrt{5}-\sqrt{3}\right|\\ =\sqrt{5}+\sqrt{3}-\sqrt{5}+\sqrt{3}\\ =2\sqrt{3}\)

\(b,\sqrt{5+2\sqrt{6}}+\sqrt{5-2\sqrt{6}}\\ =\sqrt{\sqrt{2^2}+2.\sqrt{3}.\sqrt{2}+\sqrt{3^2}}+\sqrt{\sqrt{2^2}-2.\sqrt{3}.\sqrt{2}+\sqrt{3^2}}\\ =\sqrt{\left(\sqrt{2}+\sqrt{3}\right)^2}+\sqrt{\left(\sqrt{2}-\sqrt{3}\right)^2}\\ =\left|\sqrt{2}+\sqrt{3}\right|+\left|\sqrt{2}-\sqrt{3}\right|\\ =\sqrt{2}+\sqrt{3}-\sqrt{2}+\sqrt{3}=2\sqrt{3}\)

a) \(\sqrt{8-2\sqrt{15}}-\sqrt{8+2\sqrt{15}}\)

\(=\sqrt{5-2\cdot\sqrt{5\cdot3}+3}-\sqrt{5+2\cdot\sqrt{5\cdot3}+1}\)

\(=\sqrt{\left(\sqrt{5}-\sqrt{3}\right)^2}-\sqrt{\left(\sqrt{5}+\sqrt{3}\right)^2}\)

\(=\sqrt{5}-\sqrt{3}-\sqrt{5}-\sqrt{3}\)

\(=-2\sqrt{3}\)

b. \(\sqrt{5+2\sqrt{6}}-\sqrt{5-2\sqrt{6}}\)

\(=\sqrt{2+2\cdot\sqrt{2}\cdot\sqrt{3}+3}-\sqrt{3-2\cdot\sqrt{2}+2}\)

\(=\sqrt{\left(\sqrt{2}+\sqrt{3}\right)^2}-\sqrt{\left(\sqrt{3}-\sqrt{2}\right)^2}\)

\(=\left(\sqrt{2}+\sqrt{3}\right)-\left(\sqrt{3}-\sqrt{2}\right)\)

\(=\sqrt{2}+\sqrt{3}-\sqrt{3}+\sqrt{2}\)

\(=2\sqrt{2}\)