\(a,\dfrac{1}{6}+\dfrac{7}{3}-\dfrac{1}{2}\\ =\dfrac{1}{6}+\dfrac{14}{6}-\dfrac{3}{6}\\ =\dfrac{12}{6}\\ =2\\ b,\left(-1\dfrac{5}{8}\right)+1,25:\left(1-\dfrac{9}{4}\right)\\ =\dfrac{-13}{8}+\dfrac{5}{4}:\dfrac{5}{4}\\ =\dfrac{-13}{8}+1\\ =\dfrac{-13}{8}+\dfrac{8}{8}\\ =\dfrac{5}{8}\)

A) \(\dfrac{1}{6}+\dfrac{7}{3}-\dfrac{1}{2}\)

Quy đồng: 

\(\dfrac{7}{3}=\dfrac{14}{6}\)

\(\dfrac{1}{2}=\dfrac{3}{6}\)

\(\dfrac{1}{6}=\dfrac{1}{6}\)

\(\dfrac{1}{6}+\dfrac{14}{6}-\dfrac{3}{6}=\dfrac{12}{6}\)

Rút gọn: \(\dfrac{12}{6}=\dfrac{12\div6}{6\div6}=2\)

Bài 4: 

a) \(\dfrac{4}{3}+\left(1,25-x\right)=2,25\)

\(1,25-x=2,25-\dfrac{4}{3}=\dfrac{9}{4}-\dfrac{4}{3}\)

\(1,25-x=\dfrac{11}{12}\)

\(x=1,25-\dfrac{11}{12}=\dfrac{5}{4}-\dfrac{11}{12}\)

\(x=\dfrac{1}{3}\)

b) \(\dfrac{17}{6}-\left(x-\dfrac{7}{6}\right)=\dfrac{7}{4}\)

\(x-\dfrac{7}{6}=\dfrac{17}{6}-\dfrac{7}{4}=\dfrac{34}{12}-\dfrac{21}{12}\)

\(x-\dfrac{7}{6}=\dfrac{13}{12}\)

\(x=\dfrac{13}{12}+\dfrac{7}{6}=\dfrac{13}{12}+\dfrac{14}{12}\)

\(x=\dfrac{27}{12}=\dfrac{9}{4}\)

c) \(4-\left(2x+1\right)=3-\dfrac{1}{3}=\dfrac{9}{3}-\dfrac{1}{3}\)

\(4-\left(2x+1\right)=\dfrac{8}{3}\)

\(2x+1=\dfrac{8}{3}+4=\dfrac{8}{3}+\dfrac{12}{3}\)

\(2x+1=\dfrac{20}{3}\)

\(2x=\dfrac{20}{3}-1=\dfrac{20}{3}-\dfrac{3}{3}\)

\(2x=\dfrac{17}{3}\)

\(x=\dfrac{17}{3}.\dfrac{1}{2}=\dfrac{17}{6}\)

Bài 15:

a) \(\left(\dfrac{-2}{3}\right)^9:x=\dfrac{-2}{3}\)

\(x=\left(\dfrac{-2}{3}\right)^9:\dfrac{-2}{3}=\left(\dfrac{-2}{3}\right)^{9-1}\)

\(=>x=\left(\dfrac{-2}{3}\right)^8\)

b) \(x:\left(\dfrac{4}{9}\right)^5=\left(\dfrac{4}{9}\right)^4\)

\(x=\left(\dfrac{4}{9}\right)^4.\left(\dfrac{4}{9}\right)^5=\left(\dfrac{4}{9}\right)^{4+5}\)

\(=>x=\left(\dfrac{4}{9}\right)^9\)

c) \(\left(x+4\right)^3=-125\)

\(\left(x+4\right)^3=\left(-5\right)^3\)

\(=>x+4=-5\)

\(x=-5-4\)

\(=>x=-9\)

d) \(\left(10-5x\right)^3=64\)

\(\left(10-5x\right)^3=4^3\)

\(=>10-5x=4\)

\(5x=10-4\)

\(5x=6\)

\(=>x=\dfrac{6}{5}\)

e) \(\left(4x+5\right)^2=81\)

\(\Leftrightarrow\left[{}\begin{matrix}\left(4x+5\right)^2=\left(-9\right)^2\\\left(4x+5\right)^2=9^2\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}4x+5=-9\\4x+5=9\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}4x=-14\\4x=4\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{-14}{4}\\x=1\end{matrix}\right.\)

Bài 16:

a) \(4-1\dfrac{2}{5}-\dfrac{8}{3}\)

\(=4-\dfrac{7}{5}-\dfrac{8}{3}\)

\(=\dfrac{60-21-40}{15}=\dfrac{-1}{15}\)

b) \(-0,6-\dfrac{-4}{9}-\dfrac{16}{15}\)

\(=\dfrac{-3}{5}+\dfrac{4}{9}-\dfrac{16}{15}\)

\(=\dfrac{\left(-27\right)+20-48}{45}=\dfrac{-55}{45}=\dfrac{-11}{9}\)

c) \(-\dfrac{15}{4}.\left(\dfrac{-7}{15}\right).\left(-2\dfrac{2}{5}\right)\)

\(=\dfrac{7}{4}.\dfrac{-12}{5}\)

\(=\dfrac{-21}{5}\)

\(#Wendy.Dang\)

Uh, chừa sau k dám học muộn nx

Đăng từng bài `1` thôi cậu ơii

a: =1/6+14/6-3/6=12/6=2

b: =-13/8+5/4:(-5/4)

=-13/8-1=-21/8

c: =-3/8(2/5+14/5)

=-3/8*16/5

=-6/5

d: =5/34(1/4+11/9-2/9+29/4)

=5/34*(15/2+1)

=5/34*17/2
=5/4

a: =3/4-5/4+3/2x12/5=-1/2+36/10=-5/10+36/10=31/10

b: \(=\dfrac{-7}{13}\left(\dfrac{5}{9}+\dfrac{4}{9}\right)+\dfrac{7}{13}+8=8\)

\(-1,53:\left(5\dfrac{5}{28}-1\dfrac{8}{9}\cdot1.25+1\dfrac{16}{63}\right)\)

\(=-\dfrac{153}{100}:\left(\dfrac{145}{28}-\dfrac{17}{9}\cdot\dfrac{5}{4}+\dfrac{79}{63}\right)\)

\(=-\dfrac{153}{100}:\left(\dfrac{145}{28}-\dfrac{85}{36}+\dfrac{79}{63}\right)\)

\(=-\dfrac{153}{100}:\dfrac{1395-595+316}{252}\)

\(=-\dfrac{153}{100}\cdot\dfrac{252}{1116}=\dfrac{-153}{100}\cdot\dfrac{7}{31}=\dfrac{-1071}{3100}\)

\(=-\dfrac{357}{950}\)

a, \(2,5:4x=0,5:0,2\)

\(\Rightarrow4x=\dfrac{2,5.0,2}{0,5}\)

\(\Rightarrow4x=1\Rightarrow x=\dfrac{1}{4}\)

b, \(\dfrac{1}{5}x:3=\dfrac{2}{3}:0,5\)

\(\Rightarrow\dfrac{1}{5}x=\dfrac{3.\dfrac{2}{3}}{0,5}\)

\(\Rightarrow\dfrac{1}{5}x=4\Rightarrow x=20\)

c, \(1,25:0,8=\dfrac{3}{8}:0,2x\)

\(\Rightarrow0,2x=\dfrac{0,8.\dfrac{3}{8}}{1,25}\)

\(\Rightarrow0,2x=0,24\Rightarrow x=1,2\)

Chúc bạn học tốt!!

a, \(2,5:4x=0,5:0,2\)

\(2,5:4x=2,5\)

\(4x=2,5:2,5\)

\(4x=1\)

\(x=1:4\)

\(x=\dfrac{1}{4}\)

Vậy .............

b, \(\dfrac{1}{5}x:3=\dfrac{2}{3}\)

\(\dfrac{1}{5}x=\dfrac{2}{3}.3\)

\(\dfrac{1}{5}x=2\)

\(x=2:\dfrac{1}{5}\)

\(x=10\)

Vậy .....

c, \(1,25:0,8=\dfrac{3}{8}:0,2x\)

\(1,5625=\dfrac{3}{8}:0,2x\)

\(0,2x=\dfrac{3}{8}:1,5625\)

\(0,2x=0,24\)

\(x=0,24:0,2\)

\(x=1,2\)

Vậy ...

a) \(2,5:4x=0,5:0,2\)

\(\Rightarrow2,5:4x=2,5\)

\(\Rightarrow4x=1\)

\(\Rightarrow x=0,25\)

b) \(\dfrac{1}{5}x:3=\dfrac{2}{3}:0,25\)

\(\Rightarrow\dfrac{1}{5}x:3=\dfrac{8}{3}\)

\(\Rightarrow\dfrac{1}{5}x=8\)

\(\Rightarrow x=40\)

c) \(1,25:0,8=\dfrac{3}{8}:0,2x\)

\(\Rightarrow\dfrac{3}{8}:0,2x=1,5625\)

\(\Rightarrow0,2x=0,24\)

\(\Rightarrow x=1,2\)

\(2012^0.\left(1,25-\dfrac{1}{4}\right)+\left(\dfrac{3}{5}\right)^8.\left(0,6\right)^7-\left|-5^2\right|\)

\(=1,25-\dfrac{1}{4}+\left(\dfrac{3}{5}\right)^8.\left(0,6\right)^7-\left|-25\right|\)

\(=1,25-\dfrac{1}{4}+\left(\dfrac{3}{5}\right)^8.\left(0,6\right)^7-25\)

\(=1,25-0,25+\left(\dfrac{3}{5}\right)^8.\left(0,6\right)^7-25\)

\(=1+\left(\dfrac{3}{5}\right)^8.\left(0,6\right)^7-25\)

\(=1+\left(\dfrac{3}{5}\right)^8.\left(\dfrac{3}{5}\right)^7-25\)

\(=1+\left(\dfrac{3}{5}\right)^{8+7}-25\)

\(=1+\left(\dfrac{3}{5}\right)^{15}-25\)

\(=1+\dfrac{3^{15}}{5^{15}}-25\)

\(=1,000470185-25\)

\(=-23,99952982\)

GIúp mình với!

#Helpmeplease

a: \(=\dfrac{1}{9}+\dfrac{13}{4}+5+\dfrac{3}{16}+4+\dfrac{1}{3}+\dfrac{14}{5}+\dfrac{1}{2}\)

\(=9+\dfrac{4}{9}+\dfrac{14}{5}+\dfrac{52}{16}+\dfrac{3}{16}+\dfrac{8}{18}\)

\(=9+\dfrac{146}{45}+\dfrac{63}{16}=\dfrac{11651}{720}\)

b: \(=\dfrac{7}{3}+\dfrac{9}{20}+\dfrac{85}{20}+\dfrac{1}{81}+6+\dfrac{8}{27}\)

\(=6+\dfrac{94}{20}+\dfrac{7\cdot27+1+8\cdot3}{81}\)

\(=6+\dfrac{94}{20}+\dfrac{214}{81}=\dfrac{10807}{810}\)