Tìm X biết:
x x 2 + x x 3 + x x 4 + x = 2130
Tìm x:
x x 2 + x x 3 + x x 4 + x = 2130
x * 2 + x * 3 + x * 4 + x = 2130
x * (2 + 3 + 4 + 1) = 2130
x * 10 = 2130
x = 2130 : 10 = 213
2x + 3x + 4x + x = 2130
10x = 2130
x = 2130 ÷ 10
x = 213
tìm x biết : X x 2 + X x 3 + X x 4 + X = 2130
x.(2+3+4+1)=2130
x.10=2130
x=2130:10
x=213
X x 2 + X x 3 + X x 4 + X = 2130
X x ( 2 + 3 + 4 + 1) = 2130
X x 10 = 2130
X = 2130 : 10
X = 213
tìm x:
a. X x 2 + X x 3 + X x 4 + X = 2130
b. 83584: X - 26 x 17 = 211
a) X x ( 2 + 3 + 4 + 1 ) = 2130
X x 10 = 2130
X = 2130 : 10
X = 213
b) 83584 : X - 442 = 211
83584 : X = 211 + 442
83584 : X = 653
X = 83584 : 653
X = 128
a, X x 2 + X x 3 + X x 4 + X = 2130
X x ( 2 + 3 + 4 + 1 ) = 2130
X x 10 = 2130
X = 2130 : 10
x = 213
tk mk nhé !!!!!
a, \(x\times2+x\times3+x\times4+x=2130\)
\(x\times\left(2+3+4+1\right)=2130\)
\(x\times10=2130\)
\(x=2130:10\)
\(x=213\)
b, \(83584:x-26\times17=211\)
\(83584:x-442=211\)
\(83584:x=211+442\)
\(83584:x=653\)
\(x=83584:653\)
\(x=128\)
chúc giáng sinh vui vẻ
Tìm x biết x*2+x*3+x*4+x=2130
Giúp mình nha mình cần gấp
Bài làm
X x 2 + X x 3 + X x 4 + X = 2130
X x ( 2 + 3 + 4 + 1 ) = 2130
X x 10 = 2130
X = 2130 : 10
X = 2130
Vậy X = 2130
# Học tốt #
\(x\times2+x\times3+x\times4+x=2130\)
\(\Rightarrow x\times2+x\times3+x\times4+x\times1=2130\)
\(\Rightarrow x\times\left(2+3+4+1\right)=2130\)
\(\Rightarrow10x=2130\)
\(\Rightarrow x=213\)
~Std well~
#Lâm
Xem chó https://olm.vn/thanhvien/kimmai123az, PTD/KM ? nè, thánh copy ,mời mn xem tcn của nó
tìm x biết:x(x^2-25)-(x+2)(x^2-2x+4)=3
X x 2 + X + 3 +X x 4 + X = 2130
X x 2 + X + 3 +X x 4 + X = 2130
X x 2 + X + 3 +X x 4 + X x 1 = 2130
X x (2+3+4+1) = 2130
X x 10 = 2130
X = 2130 : 10
X = 213
x.2+x.3+x.4+x=2130
x.(2+3+4+1)=2130
x.10=2130
x=2130:10=213
vậy x=213
chú thich: dấu ''.'' là dấu nhân
Tìm x ϵ Z biết:
x-1/2011 + x-2/2010 - x-3/2009 = x-4/2008
\(\dfrac{x-1}{2011}+\dfrac{x-2}{2010}-\dfrac{x-3}{2009}=\dfrac{x-4}{2008}\)
<=> \(\left(\dfrac{x-1}{2011}-1\right)+\left(\dfrac{x-2}{2010}-1\right)-\left(\dfrac{x-3}{2009}-1\right)=\left(\dfrac{x-4}{2008}-1\right)\)
<=> \(\dfrac{x-2012}{2011}+\dfrac{x-2012}{2010}-\dfrac{x-2012}{2009}-\dfrac{x-2012}{2008}=0\)
<=> \(\left(x-2012\right)\left(\dfrac{1}{2011}+\dfrac{1}{2010}-\dfrac{1}{2009}-\dfrac{1}{2008}\right)=0\)
<=> x - 2012 = 0
<=> x = 2012
X nhân 2+x nhân 3+x nhân 4+x=2130
x.2+x.3+x.4+x=2130
x.(2+3+4+1)=2130
x.10=2130
x=2130:10
x=213
x . 2 + x . 3 + x . 4 + x = 2130
x . ( 2 + 3 + 4 + 1 ) = 2130
x . 10 = 2130
x = 2130 : 10
x = 213
tìm x biết:x+1/2+x+1/3+x+1/4+x+1/5=x+1/6
\(\Rightarrow x+\frac{1}{2}+x+\frac{1}{3}+x+\frac{1}{4}+x+\frac{1}{5}-x+\frac{1}{6}=0\)
\(\Rightarrow3x+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{1}{6}\)
k cho minh
\(x+\frac{1}{2}+x+\frac{1}{3}+x+\frac{1}{4}+x+\frac{1}{5}=x+\frac{1}{6}\)
\(\Leftrightarrow x+\frac{1}{2}+x+\frac{1}{3}+x+\frac{1}{4}+x+\frac{1}{5}-x-\frac{1}{6}=0\)
\(\Leftrightarrow3x+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{5}-\frac{1}{6}=0\)
Tính ra nhé !
\(x+\frac{1}{2}+x+\frac{1}{3}+x+\frac{1}{4}+x+\frac{1}{5}=x+\frac{1}{6}\)
\(\left(x+x+x+x\right)+\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{5}\right)=x+\frac{1}{6}\)
\(\Rightarrow4x+\frac{77}{60}=x+\frac{1}{6}\)
\(\Rightarrow3x=\frac{1}{6}-\frac{77}{60}\)
\(\Rightarrow3x=-\frac{67}{60}\)
\(\Rightarrow x=-\frac{67}{60}\div3=\frac{-67}{60.3}=-\frac{67}{180}\)
Vậy x = .........