Trả lời

568-{5.[143-3.(14-1)]+10}:10

=568-{5.[143-3.13]+10}:10

=568-{5.[143-39]+10}:10

=568-{5.104+10}:10

=568-530:10

=568-53

=515

568-{5x[143-3x13+10}:10

=568-{5x[143-39+10}:10

=568-(5x114):10

=568-570:10

=568-57

=511

\(3x^2\left(2x^3-x+5\right)=6x^5-3x^3+15x^2\)

\(\Rightarrow\) Hệ số của \(x^5\) là 6

`1,14 . 6,4 + 1,14 . 3,6 + 0,2 . 1,14 . 5`

`= 1,14 . (3,6 + 6,4 + 1)`

`= 1,14 . 11`

`= 12,54`

\(\dfrac{20^3.\left(-49\right)^2}{14^3.5^4}=\dfrac{2^3.2^3.5^3.7^4}{2^3.7^3.5^4}=\dfrac{2^3.7}{5}=\dfrac{8.7}{5}=\dfrac{56}{5}\)

b)1024(5)-132(5)=892(5)

c)214(5).32(5)=6848(5)

d)211(5):13(5)=17(5)

2,1001(2):11(2)=91(2)

hehe làm bừa sai xin lỗivì tui ko hiểu

Bài 1:

a, 144(5) + 330(5) = 474(5)

b, 1024(5) - 132(5) = 892(5)

c)214(5) . 32(5) = 6848(5)

d)211(5) : 13(5) = 17(5)

Bài 2:

1001(2) : 11(2) = 91(2)

\(112\cdot35+112\cdot65+800\)

\(=112\cdot\left(35+65\right)+800\)

\(=112\cdot100+800\)

\(=11200+800\)

\(=12000\)

\(x\left(1-3x\right)\left(4-3x\right)-\left(x-4\right)\left(3x+5\right)=4x-15x^2+9x^3-3x^2+7x+20=9x^3-18x^2+11x+20\)

x(1 - 3x)(4 - 3x) - (x - 4)(3x + 5)

= (x - 3x²)(4 - 3x) - 3x² - 5x + 12x + 20

= 4x - 3x² - 12x² + 9x³ - 3x² - 5x + 12x + 20

= 9x³ - 18x² + 11x + 20