A = (3,1 – 2,5)  – (-2,5 + 3,1) = 3,1 – 2,5 + 2,5 – 3,1 = 0

B  = (5,3 – 2,8) – (4 + 5,3) = 5,3 – 2,8 – 4 – 5,3

A=(3,1-2,5)-(-2,5+3,1)=3,1-2,5+2,5-3,1=0

B=(5,3-2,8)-(4+5,3)=5,3-2,8-4-5,3=-6,8

A= (3,1 - 2,5) - (-2,5 + 3,1)

=3.1-2.5+2.5-3.1

=0

B= (5,3 - 2,8) - (4 + 5,3)

=5.3 - 2.8-4-5.3

= -6.8

C= -(251.3 + 281) + 3.251 - (1-281)

=-251.3-281+3.251-1+281

=-1

D= -(3/5+3/4)−(−3/4+2/5)

= -3/5-3/4+3/4-2/5

= -5/5

=-1

\(A=\left(3,1-2,5\right)-\left(-2,5+3,1\right)=3,1-2,5+2,5-3,1=0\)

\(B=\left(5,3-2,8\right)-\left(4+5,3\right)=5,3-2,8-4-5,3=-6,8\)

\(C=-\left(215\cdot3+281\right)+3\cdot215-\left(1-281\right)=-215\cdot3-281+3\cdot215-1+281=1\)

\(D=-\left(\frac{3}{5}+\frac{3}{4}\right)-\left(-\frac{3}{4}+\frac{2}{5}\right)=-\frac{3}{5}-\frac{3}{4}+\frac{3}{4}-\frac{2}{5}=-1\)

Bài 1 : Tính giá trị của các biểu thức sau đã bỏ dấu ngoặc :

A= (3,1 - 2,5) - (- 2,5 + 3,1) = 3,1 - 2,5 + 2,5 - 3,1 = 0

B= (5,3 - 2,8) - (4 + 5,3) = 5,3 - 2,8 - 4 - 5,3 = - 6,8

C= - (251.3 + 281) + 3.251 - (1 - 281) = - 753 - 281 + 753 + 280 = - 1

D= - (35 + 34) − ( − 34 + 25) = - 35 - 34 + 34 - 25 = - 60

\(A=\left(3,1-2,5\right)-\left(-2,5+3,1\right)\)

\(A=3,1-2,5+2,5-3,1\)

\(A=\left(3,1-3,1\right)-\left(2,5-2,5\right)\)

\(A=0-0\)

\(A=0\)

\(B=\left(5,3-2,8\right)-\left(4+5,3\right)\)

\(B=5,3-2,8-4-5,3\)

\(B=\left(5,3-5,3\right)-\left(2,8+4\right)\\ B=0-6,8\\ B=-6,8\)

Tính giá trị:

\(A=\left(3,1-2,5\right)-\left(-2,5+3,1\right)\\ A=3,1-2,5+2,5-3,1\\ A=\left(3,1-3,1\right)-\left(2,5-2,5\right)\\ A=0\)

\(B=\left(5,3-2,8\right)-\left(4+5,3\right)\\ B=5,3-2,8-4-5,3\\ B=\left(5,3-5,3\right)-\left(2,8+4\right)\\ B=-6,8\)

\(C=-\left(251.3\right)+281+3.251-\left(1-281\right)\)

\(C=\left[-\left(251.3\right)+3.251\right]+\left[281-\left(1-281\right)\right]\\ C=0+560\\ C=560\)

\(D=-\left(\dfrac{3}{5}+\dfrac{3}{4}\right)-\left(-\dfrac{3}{4}+\dfrac{2}{5}\right)\\ D=-\dfrac{3}{5}-\dfrac{3}{4}+\dfrac{3}{4}-\dfrac{2}{5}\\ D=\left(-\dfrac{3}{5}-\dfrac{2}{5}\right)+\left(-\dfrac{3}{4}+\dfrac{3}{4}\right)\\ D=-1+0\\ D=-1\)

\(B=\left(5,3-2,8\right)-\left(4+5,3\right)\)

\(B=5,3-2,8-4-5,3\)

\(B=-6,8\)

= -251 . 3 - 281 + 3 . 251 - 1 + 281

ấn nhầm

A = \(\left(3,1-2,5\right)-\left(-2,5+3,1\right)\)

\(=3,1-2,5+2,5-3,1=6,2\)

B = \(\left(5,3-2,8\right)-\left(4+5,3\right)\)

\(=5,3-2,8-4-5,3=-6,8\)

C = \(-\left(251.3+281\right)+3.251-\left(1-281\right)\)

\(=-251.3-281+3.251-1+281=-1\)

D = \(-\left(\frac{3}{5}+\frac{3}{4}\right)-\left(-\frac{3}{4}+\frac{2}{5}\right)\)

\(=-\frac{3}{5}-\frac{3}{4}+\frac{3}{4}-\frac{2}{5}=-1\)

(Nhớ k cho mình với nhá!)

`@` `\text {Ans}`

`\downarrow`

`a,`

`A =(3,1 - 2,5) - (-2,5 + 3,1)`

`= 3,1 - 2,5 + 2,5 - 3,1`

`= (3,1 - 3,1) + (-2,5+2,5)`

`= 0`

Vậy, `A = 0`

`b,`

`B = (5,3 - 2,8) - (4+5,3)`

`= 5,3 - 2,8 - 4 - 5,3`

`= (5,3 - 5,3) + (-2,8-4)`

`= -6,8`

Vậy, `B = -6,8`

`c,`

`C = -(25 - 3 + 2,81) + 3,251 - (1 - 2,8)` `?`

`= -25 + 3 - 2,81 + 3,251 - 1 + 2,8`

`= (-25 + 3 - 1) + (-2,81 + 2,8) + 3,251`

`= -23 - 0,01 + 3,251`

`= -19,759`

a) \(A=\left(3,1-2,5\right)-\left(-2,5+3,1\right)\)

\(A=0,6-0,6\)

\(A=0\)

b) \(B=\left(5,3-2,8\right)-\left(4+5,3\right)\)

\(B=2,5-7,3\)

\(B=-6,8\)

c) \(C=-\left(25-3+2,81\right)+3,251-\left(1-2,8\right)\)

\(C=-24,81+3,251+1,8\)

\(C=-19,759\)

\(A=\left(3,1-2,5\right)-\left(-2,5+3,1\right)\)

\(=3,1-2,5+2,5-3,1=0\)

\(B=\left(5,3-2,8\right)-\left(4+5,3\right)\)

\(=5,3-2,8-4-5,3=-6,8\)

\(C=-\left(251.3+281\right)+3.215-\left(1-281\right)\)

\(=-753-281+645-1+281\)

\(=-753+654-1=-100\)

\(D=-\left(\dfrac{3}{5}+\dfrac{3}{4}\right)-\left(\dfrac{-3}{4}+\dfrac{2}{5}\right)\)

\(=-\dfrac{3}{5}-\dfrac{3}{4}+\dfrac{3}{4}-\dfrac{2}{5}=\dfrac{-3}{5}-\dfrac{2}{5}=-1\)

\(A=\left(3,1-2,5\right)-\left(-2,5+3,1\right)\)

\(=3,1-2,5+2,5-3,1\)

\(=\left(3,1-3,1\right)-\left(2,5-2,5\right)\)

\(=0\)

Vậy \(A=0.\)

\(B=\left(5,3-2,8\right)-\left(4+5,3\right)\)

\(=5,3-2,8-4-5,3\)

\(=\left(5,3-5,3\right)-\left(2,8+4\right)\)

\(=-\dfrac{34}{5}\)

Vậy \(B=\dfrac{-34}{5}.\)

\(C=-\left(251.3+281\right)+3.215-\left(1-281\right)\)

\(=-251.3-281+3.215-1+281\)

\(=-753-\left(281-281\right)+645\)

\(=-753+645=-108\)

Vậy \(C=-108.\)

\(D=-\left(\dfrac{3}{5}+\dfrac{3}{4}\right)-\left(-\dfrac{3}{4}+\dfrac{2}{5}\right)\)

\(=-\dfrac{3}{5}-\dfrac{3}{4}+\dfrac{3}{4}-\dfrac{2}{5}\)

\(=\left(\dfrac{-3}{5}-\dfrac{2}{5}\right)-\left(\dfrac{3}{4}-\dfrac{3}{4}\right)\)

\(=-1\)

Vậy D = -1.

A=(3,1-2,5)-(-2,5+3,1)
A=3,1-2,5=2,5-3,1

A=(3,1-3,1)+(2,5-2,50

A=0

B=(5,3-2,8)-(4+5,3)

B=5,3-2,8-4-5,3

B=(5,3-5,3)-(4+2,8)

B=0-6,8

B=-6,8

C=-(251.3+281)+3.215-(1-281)

C=-251.3-281+3.215-1+281

C=3(-251+215)-(281+281)-1

C=-108-1

C=-109
D=\(-\left(\dfrac{3}{5}+\dfrac{3}{4}\right)-\left(-\dfrac{3}{4}\right)+\dfrac{2}{5}\)
\(D=-\dfrac{3}{5}+-\dfrac{3}{4}+\dfrac{3}{4}+\dfrac{2}{5}\)

D=\(\left(-\dfrac{3}{5}+\dfrac{2}{5}\right)+\left(-\dfrac{3}{4}+\dfrac{3}{4}\right)\)

\(D=\dfrac{-1}{5}\)