a: \(A=x^2-4=\left(x-2\right)\left(x+2\right)\)

Khi x=102 thì \(A=\left(102-2\right)\left(102+2\right)=104\cdot100=10400\)

b: \(B=x^2+6x+9=x^2+2\cdot x\cdot3+3^2=\left(x+3\right)^2\)

Khi x=997 thì \(B=\left(997+3\right)^2=1000^2=1000000\)

c: \(C=4x^2-4xy+y^2=\left(2x\right)^2-2\cdot2x\cdot y+y^2=\left(2x-y\right)^2\)

Khi x=39 và y=-2 thì \(C=\left(2\cdot39+2\right)^2=80^2=6400\)

a) \(x+546=46\\ x=46-546\\ x=-500\)

b) \(2x-19\times3=27\\ 2x-57=27\\ 2x=27+57\\ 2x=84\\ x=84:2\\ x=42\)

c) \(x+12=23+3\times3^4\\ x+12=23+3\times81\\ x=23+243-12\\ x=254\)

d) \(x-12=3-3\times2^4\\ x-12=3-3\times16\\ x=3-48+12\\ x=-33\)

e) \(\left(27-x\right)\left(x+9\right)=0\\ \Rightarrow\left[{}\begin{matrix}27-x=0\\x+9=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=27\\x=-9\end{matrix}\right.\)

f) \(\left(-x\right)\left(x-43\right)=0\\ \Rightarrow\left[{}\begin{matrix}-x=0\\x-43=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=0\\x=43\end{matrix}\right.\)

a) x + 546 = 46

x = 46 - 546

x = -500

b) 2x - 19 x 3 = 27

2x - 57 = 27

2x = 27 + 57

2x = 84

x = 84 : 2

x = 42

c) x + 12 = 23 + 3 x 3⁴

x + 12 = 23 + 3 x 81

x + 12 = 23 + 243

x + 12 = 266

x = 266 - 12

x = 254

d) x - 12 = 3 - 3 x 2⁴

x - 12 = 3 - 3 x 16

x - 12 = 3 - 48

x - 12 = -45

x = -45 + 12

x = -33

e) (27 - x) x (x + 9) = 0

TH1: 27 - x = 0

x = 27 - 0

x = 27

TH2: x + 9 = 0

x = 0 + 9

x = 9

⇒ x = 27 hoặc x = 9

f) (-x) x (x - 43) = 0

TH1: -x = 0

⇒ x = 0

TH2: x - 43 = 0

x = 0 + 43

x = 43

⇒ x = 0 hoặc x = 43.

Giá trị x trong phép tính 10 - 2x = 4 là :

A.5      B.2     C.3    D.7

Kết quả sắp xếp các số -2 ; -3 ; -102 ; -99 theo thứ tự tăng dần là :

A -2 ; -3 ; -99 ; -102

B -102 ; -99 ; -3 ; -2

C -99 ; -102 ; -3 ; -2

D -102 ; -99 ; -2 ; -3 

c b

C

B

Đề câu b sai hả bạn

Tại so lại là (6x-12).(x=7)=0

x - 7 hay là x + 7 v bạn 

a, 5-(10-x)=7

10-x=7+5

10-x=12

x=12-10

x=2 

Vậy x=2

c,(2x)-19=-10-19

2x-19=-29

2x=-29+19

2x=-10

x=-10:2

x=-5

Vậy x=-5

d,3.|x-1|-27=0

3.|x-1|=0+27

3.|x+1|=27

|x+1|=27:3

|x+1|=9

suy ra x+1=9 hoặc x+1=-9

TH1: x+1=9

x=9-1

x=8

TH2: x+1=-9

x=-9-1

x=-9+(-1)

x=-10

Vậy x=8 hoặc x=-10

CÂU c, BẠN VIẾT LẠI NHA

NHỚ TÍCH MK ĐÓ!

có \(\frac{27-2x}{12-x}=\frac{\left(24-2x\right)+4}{12-x}=\frac{2\left(12-x\right)}{12-x}+\frac{4}{12-x}\) 

\(=2+\frac{4}{12-x}\)

Để \(\frac{27-2x}{12-x}\)có GTLN => \(2+\frac{4}{12-x}\)có GTLN

=>12-x đạt gia trị dương nhỏ nhất

=>12-x=1

=>x=13

Khi đó, \(\frac{27-2x}{12-x}\)sẽ có giá trị lớn nhát là \(2+\frac{4}{1}\)=2+4=5

Vậy GTLN của \(\frac{27-2x}{12-x}\)là 5 khi x=5

b)\(\frac{5x-19}{x-4}=\frac{\left(5x-20\right)+1}{x-4}=\frac{5\left(x-4\right)}{x-4}+\frac{1}{x-4}=5+\frac{1}{x-4}\)

Để \(\frac{5x-19}{x-4}\)Đạt GTNN thì \(5+\frac{1}{x-4}\)Đạt GTNN

=>\(\frac{1}{x-4}\)Đạt GTNN

ĐÊN ĐÂY MÌNH MỜI BIẾT ĐỀ PHÂN B SAI RỒI BẠN ƠI

BẠN SỬA ĐỂ ĐÚNG RỒI LAM THEO CÂU A LÀ ĐƯỢC

CHÚC BẠN MAY MẮN

a. x=5/6

\(a,\Rightarrow\left(x-\dfrac{1}{2}\right)^3=\dfrac{1}{27}=\left(\dfrac{1}{3}\right)^3\\ \Rightarrow x-\dfrac{1}{2}=\dfrac{1}{3}\Rightarrow x=\dfrac{5}{6}\\ b,\Rightarrow\left(\dfrac{3}{2}\right)^{2x-1}:\left(\dfrac{3}{2}\right)^9=\left(\dfrac{3}{2}\right)^4\\ \Rightarrow2x-1-9=4\\ \Rightarrow2x=14\Rightarrow x=7\\ c,\Rightarrow2^{x-1}+2^{x+2}=9\cdot2^5\\ \Rightarrow2^{x-1}\left(1+2^3\right)=9\cdot2^5\\ \Rightarrow2^{x-1}\cdot9=9\cdot2^5\\ \Rightarrow2^{x-1}=2^5\Rightarrow x-1=5\Rightarrow x=6\\ d,\Rightarrow\left(2x+1\right)^2=12+69=81\\ \Rightarrow\left[{}\begin{matrix}2x+1=9\\2x+1=-9\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=4\\x=-5\end{matrix}\right.\)

\(a,\dfrac{2}{3}+\left(x-\dfrac{1}{2}\right)^3=\dfrac{19}{27}\)

\(\left(x-\dfrac{1}{2}\right)^3=\dfrac{19}{27}-\dfrac{2}{3}\)

\(\left(x-\dfrac{1}{2}\right)^3=\dfrac{1}{27}\)

\(\Rightarrow\left(x-\dfrac{1}{2}\right)^3=\left(\dfrac{1}{3}\right)^3\)

\(\Rightarrow x-\dfrac{1}{2}=\dfrac{1}{3}\)

\(x=\dfrac{1}{2}+\dfrac{1}{3}\)

\(x=\dfrac{1}{5}\)

a) 42 - x = 5

x = 42 - 5

x = 37

b) 15.(x + 4) = 75

x + 4 = 75 : 15

x + 4 = 5

x = 5 - 4

x = 1

d) x + 18 = 12

x = 12 - 18

x = -6

e) 2x - 15 = -19

2x = (-19) + 15

2x = -4

x = -4 : 2

x = -2

f) 36 : (x^3 - 12) = -3

x^3 - 12 = 36 : (-3)

x^3 - 12 = -12

x^3 = 0

=> x = 0

g)x + 15 = 35

x = 35 - 15

x = 20

h) 2x - 13 = 3^2

2x - 13 = 9

2x = 9 + 13

2x = 22

x = 22 : 2

x = 11

a) 42-x=5

         x=42-5

         x= 37

b)15*(x+4)=75

        x+4=75:15

        x+4=5

        x    =5-4

       x     = 1

a) 42 - x = 5

x = 42 - 5

x = 37

b) 15.(x + 4) = 75

x + 4 = 75 : 15

x + 4 = 5

x = 5 - 4

x = 1

d) x + 18 = 12

x = 12 - 18

x = -6

e) 2x - 15 = -19

2x = (-19) + 15

2x = -4

x = -4 : 2

x = -2

f) 36 : (x^3 - 12) = -3

x^3 - 12 = 36 : (-3)

x^3 - 12 = -12

x^3 = 0

=> x = 0

g)x + 15 = 35

x = 35 - 15

x = 20

h) 2x - 13 = 3^2

2x - 13 = 9

2x = 9 + 13

2x = 22

x = 22 : 2

x = 11

`@` `\text {Ans}`

`\downarrow`

`c)`

`( 34 - 2x ) . ( 2x - 6 ) = 0`

`=>`\(\left[{}\begin{matrix}34-2x=0\\2x-6=0\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}2x=34\\2x=6\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=34\div2\\x=6\div2\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=17\\x=3\end{matrix}\right.\)

Vậy, `x \in {17; 3}`

`d)`

`( 2019 - x ) . ( 3x - 12 ) =0` `?`

`=>`\(\left[{}\begin{matrix}2019-x=0\\3x-12=0\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=2019-0\\3x=12\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=2019\\x=12\div3\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=2019\\x=4\end{matrix}\right.\)

Vậy, `x \in {2019; 4}`

`e) `

`57 . ( 9x - 27 ) = 0`

`=>`\(9x-27=0\div57\)

`=> 9x - 27 = 0`

`=> 9x = 27`

`=> x = 27 \div 9`

`=> x = 3`

Vậy, `x = 3`

`f)`

`25 + ( 15 - x ) = 30`

`=> 15 - x = 30 - 25`

`=> 15 - x = 5`

`=> x = 15 -5 `

`=> x = 10`

Vậy, `x = 10`

`g) `

`43 - ( 24 - x ) = 20`

`=> 24 - x = 43 - 20`

`=> 24 - x = 23`

`=> x = 24 - 23`

`=> x = 1`

Vậy, `x = 1`

`h) `

`2 . ( x - 5 ) - 17 = 25`

`=> 2 ( x - 5) = 25+17`

`=> 2 ( x - 5) = 42`

`=> x - 5 = 42 \div 2`

`=> x - 5 = 21`

`=> x = 21 + 5`

`=> x = 26`

Vậy, `x = 26`

`i)`

`3 . ( x + 7 ) - 15 = 27`

`=> 3(x + 7) = 27 + 15`

`=> 3(x + 7) = 42`

`=> x +7 = 42 \div 3`

`=> x + 7 = 14`

`=> x = 14 - 7`

`=> x = 7`

Vậy, `x = 7`

`j)`

`15 + 4 . ( x - 2 ) = 95`

`=> 4(x - 2) = 95 - 15`

`=> 4(x - 2) = 80`

`=> x - 2 = 80 \div 4`

`=> x - 2 = 20`

`=> x = 20 + 2`

`=> x = 22`

Vậy, `x = 22`

`k)`

`20 - ( x + 14 ) = 5`

`=> x + 14 = 20 - 5`

`=> x + 14 = 15`

`=> x = 15 - 14`

`=> x = 1`

Vậy, `x = 1`

`l) `

`14 + 3 . ( 5 - x ) = 27`

`=> 3(5 - x) = 27 - 14`

`=> 3(5 - x) = 13`

`=> 5 - x = 13 \div 3`

`=> 5 - x = 13/3`

`=> x = 5- 13/3`

`=> x = 2/3`

Vậy, `x = 2/3.`

`@` `\text {Kaizuu lv uuu}`

nhanh mik tick cho nha

Đáp án C.

Ta có  y = 2 3 x - 9 , x ≠ ± 3 - 1 9 , x = ± 3 ⇒  Hàm số không liên tục tại điểm x = 3.