a) \(\dfrac{2}{5}-\dfrac{3}{15}\)

\(=\dfrac{2}{5}-\dfrac{3:3}{15:3}\)

\(=\dfrac{2}{5}-\dfrac{1}{5}\)

\(=\dfrac{1}{5}\)

b) \(\dfrac{9}{27}-\dfrac{2}{9}\)

\(=\dfrac{9:3}{27:3}-\dfrac{2}{9}\)

\(=\dfrac{3}{9}-\dfrac{2}{9}\)

\(=\dfrac{1}{9}\)

c) \(\dfrac{18}{24}-\dfrac{4}{8}\)

\(=\dfrac{18:6}{24:6}-\dfrac{4:2}{8:2}\)

\(=\dfrac{3}{4}-\dfrac{2}{4}\)

\(=\dfrac{1}{4}\)

d) \(\dfrac{6}{16}-\dfrac{10}{64}\)

\(=\dfrac{6\times2}{16\times2}-\dfrac{10:2}{64:2}\)

\(=\dfrac{12}{32}-\dfrac{5}{32}\)

\(=\dfrac{7}{32}\)

a: =1/4+1/4=2/4=1/2

b: =3/5+3/5=6/5

c: =5/9+7/9=12/9=4/3

a, 1/4+1/4=2/4=1/4

b, 3/5+3/5=6/5

c, 5/9+7/9=12/9=4/3

a)1/4+1/4=2/4=1/4

b) 3/5+3/5=6/5

c) 5/9+7/9=12/9=4/3

Rút gọn rồi tính:                                                                                                                                               \(a.\frac{16}{24}-\frac{1}{3}=\frac{2}{3}-\frac{1}{3}=\frac{1}{3}\)

\(b.\frac{4}{5}-\frac{12}{60}=\frac{4}{5}-\frac{1}{5}=\frac{3}{5}\)

Tính rồi rút gọn:

\(a.\frac{17}{6}-\frac{2}{6}=\frac{15}{6}\)

\(b.\frac{16}{15}-\frac{11}{15}=\frac{5}{15}=\frac{1}{3}\)

\(c.\frac{19}{12}-\frac{13}{12}=\frac{6}{12}=\frac{1}{2}\)

1a2/3-1/3=1/3            c4/5-1/5=3/5             tinh roi rut gon 17/6-2/6=15/6=5/2             16/15-11/15=5/15=1/3           19/12-13/12=6/12=1/2

chuc bn hoc tot

lớp 1 à cu

a: \(\dfrac{3}{9}\times\dfrac{5}{4}=\dfrac{5}{4}\times\dfrac{1}{3}=\dfrac{5\times1}{4\times3}=\dfrac{5}{12}\)

b: \(\dfrac{10}{15}\times\dfrac{3}{5}=\dfrac{3}{5}\times\dfrac{2}{3}=\dfrac{3\times2}{5\times3}=\dfrac{2}{5}\)

c: \(\dfrac{5}{8}\times\dfrac{4}{12}=\dfrac{5}{8}\times\dfrac{1}{3}=\dfrac{5}{3\times8}=\dfrac{5}{24}\)

d: \(\dfrac{9}{27}\times\dfrac{3}{21}=\dfrac{1}{7}\times\dfrac{1}{3}=\dfrac{1\times1}{7\times3}=\dfrac{1}{21}\)

a: \(\dfrac{8}{18}+\dfrac{5}{3}=\dfrac{4}{9}+\dfrac{5}{3}=\dfrac{4}{9}+\dfrac{15}{9}=\dfrac{4+15}{9}=\dfrac{19}{9}\)

b: \(\dfrac{8}{24}+\dfrac{4}{48}=\dfrac{1}{3}+\dfrac{1}{12}=\dfrac{4}{12}+\dfrac{1}{12}=\dfrac{4+1}{12}=\dfrac{5}{12}\)

c: \(\dfrac{20}{15}-\dfrac{4}{45}=\dfrac{4}{3}-\dfrac{4}{45}=\dfrac{60}{45}-\dfrac{4}{45}=\dfrac{60-4}{45}=\dfrac{56}{45}\)

d: \(\dfrac{40}{32}-\dfrac{1}{2}=\dfrac{5}{4}-\dfrac{1}{2}=\dfrac{5-2}{4}=\dfrac{3}{4}\)

TL

4/16+1/4=1/4+14=2/4=1/2

b) 15/25+6/10=3/5+3/5=6/5

c)5/9+21/27=5/9+7/9=4/3

HT

\(a)\) \(\dfrac{4}{16} + \dfrac{1}{4} = \dfrac{1}{4}+ \dfrac{1}{4} = \dfrac{2}{4} = \dfrac{1}{2} \)

\(b) \dfrac{15}{25} + + \dfrac{6}{10} = \dfrac{3}{5} + \dfrac{3}{5} =\dfrac{6}{5} \)

\(c) \dfrac{5}{9} + \dfrac{21}{27} = \dfrac{5}{9} + \dfrac{7}{9} = \dfrac{12}{9} = \dfrac{4}{3}\)

a) 1/4 + 1/4 = 2/4 = 1/2

b) 3/5 + 3/5 = 6/5

c) 5/9 + 7/9 = 12/9 = 4/3

\(5\sqrt{\left(-2\right)^4}=5\sqrt{4^2}=5.4=20\)

\(-4\sqrt{\left(-3\right)^6}=-4\sqrt{27^2}=-4.27=-108\)

\(\sqrt{\sqrt{\left(-5\right)^8}}=\sqrt{\sqrt{\left(5^4\right)^2}}=\sqrt{5^4}=\sqrt{25^2}=25\)

Rút gọn rồi tính:

a) $\frac{16}{24}–\frac{1}{3}=\frac{2}{3}–\frac{1}{3}=\frac{2–1}{3}=\frac{1}{3}$     

b) $\frac{4}{5}–\frac{12}{60}=\frac{4}{5}–\frac{1}{5}=\frac{3}{5}$

Tính rồi rút gọn:

a) $\frac{17}{6}–\frac{2}{6}=\frac{17–2}{6}=\frac{15}{6}=\frac{5}{2}$             

b) $\frac{16}{15}–\frac{11}{15}=\frac{16–11}{15}=\frac{5}{15}=\frac{1}{3}$

c)