\(\left\{{}\begin{matrix}3x^2-8xy+5y^2=0\\2x+7y=5\end{matrix}\right.\)
Giải phương trình:
1. \(\left\{{}\begin{matrix}4x-2y=3\\6x-3y=5\end{matrix}\right.\)
2. \(\left\{{}\begin{matrix}2x-3y=5\\4x+6y=10\end{matrix}\right.\)
3. \(\left\{{}\begin{matrix}3x-4y+2=0\\5x+2y=14\end{matrix}\right.\)
4. \(\left\{{}\begin{matrix}2x+5y=3\\3x-2y=14\end{matrix}\right.\)
1) \(\left\{{}\begin{matrix}3x-2y=4\\4x+2y=10\end{matrix}\right.\)
<=> \(\left\{{}\begin{matrix}3x-2y=4\\7x=14\end{matrix}\right.< =>\left\{{}\begin{matrix}x=2\\y=1\end{matrix}\right.\)
2)\(\left\{{}\begin{matrix}2x+3y=5\\4x+6y=10\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}4x+6y=10\\4x=6y=10\end{matrix}\right.\)
=> Hệ có vô số nghiệm.
3)\(\left\{{}\begin{matrix}3x-4y=-2\\10x+4y=28\end{matrix}\right.\)
<=>\(\left\{{}\begin{matrix}3x-4y=-2\\13x=26\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=2\\y=2\end{matrix}\right.\)
4)\(\left\{{}\begin{matrix}6x+15y=9\\6x-4y=28\end{matrix}\right.\)
<=>\(\left\{{}\begin{matrix}6x+15y=9\\19y=19\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=4\\y=-1\end{matrix}\right.\)
Giải các hệ phương trình sau:
a) \(\left\{{}\begin{matrix}2x+5y=5\\3x-5y=-30\end{matrix}\right.\) b) \(\left\{{}\begin{matrix}4x-3y=-5\\3x+2y=-8\end{matrix}\right.\)
c) \(\left\{{}\begin{matrix}3x+3y=9\\4x-2y=-2\end{matrix}\right.\) d) \(\left\{{}\begin{matrix}5x-4y=32\\6x+2y=18\end{matrix}\right.\)
e) \(\left\{{}\begin{matrix}2x-3y+5=0\\3x+5y-21=0\end{matrix}\right.\) f) \(\left\{{}\begin{matrix}x-y\sqrt{2}=0\\2x\sqrt{2}+y=5\end{matrix}\right.\)
g) \(\left\{{}\begin{matrix}5x+4y=-3\\3x+2y=11\end{matrix}\right.\) h) \(\left\{{}\begin{matrix}2x-4y=12\\5x+3y=17\end{matrix}\right.\)
e.
\(\left\{{}\begin{matrix}2x-3y+5=0\\3x+5y-21=0\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}10x-15y=-25\\9x+15y=63\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}19x=38\\3x+5y=21\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=2\\y=\dfrac{21-3x}{5}\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=2\\y=3\end{matrix}\right.\)
f.
\(\left\{{}\begin{matrix}x-y\sqrt{2}=0\\2x\sqrt{2}+y=5\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x-y\sqrt{2}=0\\4x+y\sqrt{2}=5\sqrt{2}\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}5x=5\sqrt{2}\\2x\sqrt{2}+y=5\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=\sqrt{2}\\y=5-2x\sqrt{2}\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=\sqrt{2}\\y=1\end{matrix}\right.\)
a.
\(\Leftrightarrow\left\{{}\begin{matrix}5x=-25\\3x-5y=-30\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=-5\\y=\dfrac{3x+30}{5}\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=-5\\y=3\end{matrix}\right.\)
b.
\(\Leftrightarrow\left\{{}\begin{matrix}8x-6y=-10\\9x+6y=-24\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}17x=-34\\9x+6y=-24\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=-2\\y=\dfrac{-24-9x}{6}\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=-2\\y=-1\end{matrix}\right.\)
c.
\(\left\{{}\begin{matrix}3x+3y=9\\4x-2y=-2\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x+y=3\\2x-y=-1\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}3x=2\\2x-y=-1\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=\dfrac{2}{3}\\y=2x+1\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=\dfrac{2}{3}\\y=\dfrac{7}{3}\end{matrix}\right.\)
d.
\(\left\{{}\begin{matrix}5x-4y=32\\6x+2y=18\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}5x-4y=32\\12x+4y=36\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}5x-4y=32\\17x=68\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=4\\y=\dfrac{3x-32}{4}\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=4\\y=-3\end{matrix}\right.\)
Giai hệ phương trình:
\(\hept{\begin{cases}2x^3y+3x^2=5y\\1+6xy=7y^2\end{cases}}\)
\(\left\{{}\begin{matrix}2x^3y+3x^2=5y\\1+6xy=7y^2\end{matrix}\right.\)
giải hệ pt sau
a\(\left\{{}\begin{matrix}4x+y=2\\8x+3y=5\end{matrix}\right.\) b\(\left\{{}\begin{matrix}3x_{ }-2y=11\\4x-5y=3\end{matrix}\right.\) c\(\left\{{}\begin{matrix}4x+3y=13\\5x-3y=_{ }-31\end{matrix}\right.\) D\(\left\{{}\begin{matrix}7X+5Y=19\\3x+5y=31\end{matrix}\right.\)
e\(\left\{{}\begin{matrix}7x-5y=3\\3x+10y=62\end{matrix}\right.\) f\(\left\{{}\begin{matrix}2x+5y=11\\3x+2y=11\end{matrix}\right.\) g\(\left\{{}\begin{matrix}x+3y=4y-x+5\\2x-y=3x-2\left(y+1\right)\end{matrix}\right.\)
a)\(\left\{{}\begin{matrix}8x+2y=4\\8x+3y=5\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}y=1\\4x+1=2\end{matrix}\right.\Leftrightarrow}\left\{{}\begin{matrix}y=1\\x=\frac{1}{4}\end{matrix}\right.\)b)
\(\left\{{}\begin{matrix}12x-8y=44\\12x-15y=9\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}7y=35\\4x-5y=3\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}y=5\\4x-5.5=3\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}y=5\\x=7\end{matrix}\right.\)c)\(\left\{{}\begin{matrix}9x=-18\\4x+3y=13\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=-2\\4.\left(-2\right)+3y=13\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=-2\\y=7\end{matrix}\right.\)
\(\left\{{}\begin{matrix}x^2+2y^2-10xy+3x-5y+9=0\\x^2-2y^2-xy+x+7y-6=0\end{matrix}\right.\)
\(\left\{{}\begin{matrix}2x+5y=-2\\x-y=6\end{matrix}\right.\)
\(\left\{{}\begin{matrix}3x+y=-3\\2x+5y=-6\end{matrix}\right.\)
\(\left\{{}\begin{matrix}2x+5y=-2\\x-y=6\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}2x+5y=-2\\2x-2y=12\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}7y=-14\\x-y=6\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}y=-2\\x-\left(-2\right)=6\end{matrix}\right.\\ \)
\(\Leftrightarrow\left\{{}\begin{matrix}y=-2\\x=4\end{matrix}\right.\) là nghiệm duy nhất của hệ phương trình.
\(\left\{{}\begin{matrix}3x+y=-3\\2x+5y=-6\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}15x+5y=-15\\2x+5y=-6\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}13x=-9\\3x+y=-3\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}x=-\dfrac{9}{13}\\3\cdot\left(-\dfrac{9}{13}\right)+y=-3\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=-\dfrac{9}{13}\\y=-\dfrac{12}{13}\end{matrix}\right.\) là nghiệm duy nhất của hệ phương trình.
giai hpt
a.\(\left\{{}\begin{matrix}x=y+4\\2x+3=0\end{matrix}\right.\)
b.\(\left\{{}\begin{matrix}2x+y=7\\3y-x=7\end{matrix}\right.\)
c.\(\left\{{}\begin{matrix}5x+y=3\\-x-\dfrac{1}{5}y=\dfrac{-3}{5}\end{matrix}\right.\)
d.\(\left\{{}\begin{matrix}3x-5y=-18\\x-5=2y\end{matrix}\right.\)
\(a) \begin{cases}x=y+4\\2x+3=0\end{cases}\Leftrightarrow\begin{cases}x = y + 4\\2x = -3\end{cases}\Leftrightarrow\begin{cases}\dfrac{-3}{2} = y + 4\\x = \dfrac{-3}{2}\end{cases}\Leftrightarrow\begin{cases}y = \dfrac{-11}{2}\\x = \dfrac{-3}{2}\end{cases}\\b) \begin{cases}2x + y = 7\\3y - x = 7\end{cases}\Leftrightarrow\begin{cases}2x + y = 7\\6y - 2x = 14\end{cases}\Leftrightarrow\begin{cases}2x + y = 7\\7y = 21\end{cases}\Leftrightarrow\begin{cases}2x + 3 = 7\\y = 3\end{cases}\Leftrightarrow\begin{cases}x=2\\y=3\end{cases}\\ c) \begin{cases} 5x + y = 3 \\ -x - \dfrac{1}{5}y=\dfrac{-3}{5} \end{cases} \Leftrightarrow \begin{cases} 5x + y = 3 \\ 5x + y = 3 \end{cases} (luôn\ đúng) \Leftrightarrow Phương\ trình\ vô\ số\ nghiệm \\d) \begin{cases} 3x - 5y = -18 \\ x - 5 = 2y \end{cases} \Leftrightarrow \begin{cases} 3x - 5y = -18 \\ 3x - 6y = 15 \end{cases} \Leftrightarrow \begin{cases} x - 5 = 2.(-33)\\ y = -13 \end{cases} \Leftrightarrow \begin{cases}x = -61\\y=-33 \end{cases} \)
\(\left\{{}\begin{matrix}3x+y=3\\2x-y=7\end{matrix}\right.\)
..
\(\left\{{}\begin{matrix}2x+5y=8\\2x-3y=0\end{matrix}\right.\)
..
\(\left\{{}\begin{matrix}4x+3y=6\\2x+y=4\end{matrix}\right.\)
Câu 1:
Lấy PT(1) + PT(2) theo vế thu được:
$3x+y+(2x-y)=10$
$\Leftrightarrow 5x=10$
$\Leftrightarrow x=2$
$y=2x-7=2.2-7=-3$
Vậy hpt có nghiệm $(x,y)=(2,-3)$
Câu 2:
Lấy PT(1) - PT(2) theo vế thì:
$(2x+5y)-(2x-3y)=8$
$\Leftrightarrow 8y=8$
$\Leftrightarrow y=1$
Khi đó: $x=3y:2=\frac{3}{2}$
Vậy.............
Câu 3:
Lấy PT(1) - 2PT(2) thu được:
$(4x+3y)-2(2x+y)=6-2.4$
$\Leftrightarrow y=-2$
Khi đó:
$2x=4-y=6$
$\Leftrightarrow x=3$
Vậy..........
Giải các hệ phương trình sau bằng máy tính bỏ túi (làm tròn kết quả dến chữ số thập phân thứ hai)
a. \(\left\{{}\begin{matrix}3x-5y=6\\4x+7y=-8\end{matrix}\right.\)
b. \(\left\{{}\begin{matrix}-2x+3y=5\\5x+2y=4\end{matrix}\right.\)
c. \(\left\{{}\begin{matrix}2x-3y+4z=-5\\-4x+5y-z=6\\3x+4y-3z=7\end{matrix}\right.\)
d. \(\left\{{}\begin{matrix}-x+2y-3z=2\\2x+y+2z=-3\\-2x-3y+z=5\end{matrix}\right.\)
a. \(\left\{{}\begin{matrix}3x-5y=6\\4x+7y=-8\end{matrix}\right.\)
\(x=\dfrac{2}{41}\) ; \(y=\dfrac{-48}{41}\)
b. \(\left\{{}\begin{matrix}\text{−2x+3y=5}\\5x+2y=4\end{matrix}\right.\)
\(x=\dfrac{2}{19};y=\dfrac{33}{19}\)
c.\(\left\{{}\begin{matrix}\text{2x−3y+4z=−5}\\-4x+5y-z=6\\3x+4y-3z=7\end{matrix}\right.\)
\(x=\dfrac{22}{101};y=\dfrac{131}{101};z=\dfrac{-39}{101}\)
d. \(\left\{{}\begin{matrix}\text{− x + 2 y − 3 z = 2}\\2x+y+2z=-3\\-2x-3y+z=5\end{matrix}\right.\)
\(x=-4;y=\dfrac{11}{7};z=\dfrac{12}{7}\)
a)x=0,05 ; y=-1,17
b.x=0,11 ; y=1,74
c.x=0,22 ;y=1,29 z=-0.39
d.x=-4 y=1,57 z=1,71
a,\(\left\{{}\begin{matrix}3x-5y=6\\4x+7y=-8\end{matrix}\right.\)
x=\(\dfrac{2}{41}=0,05\) ; y=\(\dfrac{-48}{41}=-1,17\)
b,\(\left\{{}\begin{matrix}-2x+3y=5\\5x+2y=4\end{matrix}\right.\)
x=\(\dfrac{2}{19}=0,11\) ; y=\(\dfrac{33}{19}=1,74\)
c,\(\left\{{}\begin{matrix}2x-3y+4z=-5\\-4x+5y-z=6\\3x+4y-3z=2\end{matrix}\right.\)
x=\(\dfrac{22}{101}=0,22\) ;y=\(\dfrac{131}{101}=1,29\) ; z=\(\dfrac{-39}{101}=-0,39\)
d,\(\left\{{}\begin{matrix}-x+2y-3z=2\\2x+y+2z=-3\\-2x-3y+z=5\end{matrix}\right.\)
x=\(-4\) ; y=\(\dfrac{11}{7}=1,57\) ; z=\(\dfrac{12}{7}=1,71\)