a) -2x+17=15

-2x=-2

x=1

b)2x-5=-5x-26

2x+5x=5-26

7x=-21

x=-3

a, -2x+17=15

    15x=15 suy ra x= tự làm

b, 2x+5x=-26+5

    7x=-21 suy ra x= tự làm

a) \(\Rightarrow x\left(x+3\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}x=0\\x=-3\end{matrix}\right.\)

b) \(\Rightarrow x\left(x^2-4\right)=0\Rightarrow x\left(x-2\right)\left(x+2\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}x=0\\x=2\\x=-2\end{matrix}\right.\)

c) \(\Rightarrow\left(x-1\right)\left(5x-1\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}x=1\\x=\dfrac{1}{5}\end{matrix}\right.\)

d) \(\Rightarrow2\left(x+5\right)-x\left(x+5\right)=0\Rightarrow\left(x+5\right)\left(2-x\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}x=-5\\x=2\end{matrix}\right.\)

e) \(\Rightarrow2x^2-10x-3x-2x^2=26\)

\(\Rightarrow-13x=26\Rightarrow x=-2\)

f) \(\Rightarrow\left(x-2012\right)\left(5x-1\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}x=2012\\x=\dfrac{1}{5}\end{matrix}\right.\)

vậy giỏi zữ vậy

Bài 2: 

a: \(\Leftrightarrow2x^2-10x-3x-2x^2=26\)

=>-13x=26

hay x=-2

b: \(\Leftrightarrow\left(x-1\right)\left(5x-1\right)=0\)

hay \(x\in\left\{1;\dfrac{1}{5}\right\}\)

c: \(\Leftrightarrow\left(x+5\right)\left(2-x\right)=0\)

hay \(x\in\left\{-5;2\right\}\)

ủng hộ mình lên 330 điểm nha các bạn

a) 2x(x - 5)- x(3 + 2x ) = 26

2x² - 10x - 3x - 2x² = 26

-13x = 26

x = -2

b) 5x³ - 45 = 0

5x³ = 45

x³ = 9

=> x ko thỏa mãn

a)\(5\left(2x-1\right)-4\left(8-3x\right)=7\)

\(\Leftrightarrow10x-5+12x-32=7\)

\(\Leftrightarrow22x-37=7\)

\(\Leftrightarrow22x=44\Rightarrow x=2\)

b)\(5x\left(x-5\right)-x\left(2x+3\right)=26\)

\(\Leftrightarrow5x^2-25x-2x^2-3x=26\)

\(\Leftrightarrow3x^2-28x-26=0\)

\(\Leftrightarrow3\left(x-\dfrac{14}{3}\right)^2-\dfrac{274}{3}=0\)

\(\Rightarrow x=\dfrac{14}{3}\pm\dfrac{\sqrt{274}}{3}\)

Rối mắt , loạn thần kinh toàn là x không

Nhiều quá bạn ơi 

a) 2x(x - 5) - x(3 + 2x) = 26

    2x² - 10x - 3x - 2x² = 26

    -10x - 3x = 26

    -13x = 26 => x = -2

b) 5x(x - 1) = x - 1

    5x(x - 1) - (x - 1) = 0

    (x - 1)(5x - 1) = 0

    x - 1 = 0 => x = 1

    5x - 1 = 0 => x = \(\frac{1}{5}\)

Vậy x = 0; x = \(\frac{1}{5}\)