\(2x+5x=26-5\)( chuyển vế)
\(7x=21\)
\(x=\frac{21}{7}=3\)
Vậy x=3
\(2x+5x=26-5\)( chuyển vế)
\(7x=21\)
\(x=\frac{21}{7}=3\)
Vậy x=3
Bài 1 : Tìm x
a) 2x + 1 phần 7 = 1 phần 3
b) 3(x - 1 phần 2) = 4 phần 9
c) ( x - 5)2 + 4 = 68
d) (|x|- 1 phần 2 ) (2x + 3 phần 2) = 0
e) 5x + 2 = 3x + 8
f) 26 - (5 - 2x) = 27
g) ( 4x - 8 ) - ( 2x - 6 ) = 4
h) (x + 3)3 ÷ 3 - 1 = - 10
1)5(5x-3)-3(2x-4)=11-5x
2)4(2-3x)-5(1-2x)=4-6x
1)6x-8=3x+1
2)12-10x=25-30x
3)3(2x+3)-2(4x-5)=10x+21
4)5(5x-3)-3(2x-4)11-5x
5)4(2-3x)-5(1-2x)=4-6x
6)8(4x-3)-3(2-3x)=13-40x
7)10x-5(1-4x)=5x-11
8)-3(3-4x)-5(4-3x)=12x-50
9)-2(20x-3)-3(4x-5)=9-2(2x-3)
10)-5(2-3x)+3(5-2x)=3x+3(3-5x)
8x + 2x = 25 . 22
5x + 2x = 62 - 50
5x + x = 150 : 2 + 3
giải ra luôn nha. thank you
1) 4x-(2x-5)=21
2) 14x+5=8x+10
3) 15+5x=3x+30
4) 2x-5=15-3x
5) 2(3x+5)+3(x+1)=6x+20
6) 4(x-3)+5(x-3)=18
(X-3)100-1=0
(9-5x)2019+1=0
(4x-3)5=(2-x)5
(2x-9)2=(5x-6)2
(11-4x)6-(2-5x)6
a,(x-4)(2x-3)>0
b,(x-1)(2x+5)<0
c,(2x-3)(4-5x)=0
Các bn giúp mk vs nha!!!
tìm x
x-1/3 +3x-5/2 +2x/9 + -5x +3 /9 =210/420
2x+(5x+39)=25
53x.57=52020-52018
Giúp mình voi