a) ĐK: x ≥ 2

\(\sqrt{3x-6}=3\)

\(\Leftrightarrow3x-6=9\)

<=> 3x = 15

<=> x = 5

Vậy:....

b) ĐK: 5x - 16 ≥ 0

<=> 5x ≥ 16

<=> x ≥ 16/5

\(\sqrt{5x-16}=2\)

<=> 5x - 16 = 4

<=> 5x = 20

<=> x = 4

c) ĐK: \(x^2-4x+3\ne0\)

\(\Leftrightarrow\left(x-1\right)\left(x-3\right)\ne0\)

\(\Leftrightarrow\left\{{}\begin{matrix}x\ne1\\x\ne3\end{matrix}\right.\)

bình phương hai vế ta được:

a)điều kiện của x:x≥2

3x-6=9 <=> x=5(nhận)

b)ĐK: x≥16/5

5x-16=4 <=>x=4(nhận)

c) ta có: \(\dfrac{2x-3}{\left(x-2\right)^2-1}\)= \(\dfrac{2x-3}{\left(x-3\right)\left(x-1\right)}\)

ĐKXĐ: x≠3 ;x≠1

a,\(\sqrt{3x-6}=3\) (với x\(\ge\)2)

=>\(\left(\sqrt{3x-6}\right)^2=3^2\)

<=>\(3x-6=9\)<=>\(3x=9+6\)<=>x=\(\dfrac{15}{3}\)=5(thỏa mãn)

b,\(\sqrt{5x-16}=2\) (với x\(\ge\)16/5)

=>\(\left(\sqrt{5x-16}\right)^2=2^2\)<=>\(5x-16=4< =>5x=20< =>x=4\)(thỏa mãn)

c,B xác định khi \(x^2-4x+3\ne0< =>x^2-2.2.x+2^2-1\ne0\)

\(< =>\left(x-2\right)^2-1\ne0\)

\(< =>\left(x-2+1\right)\left(x-2-1\right)\ne\)0

\(< =>\left(x-1\right)\left(x-3\right)\ne0\)

\(< =>\left[{}\begin{matrix}x-1\ne0\\x-3\ne0\end{matrix}\right.< =>\left[{}\begin{matrix}x\ne1\\x\ne3\end{matrix}\right.\)

a: Ta có: \(3\left(2x-3\right)+2\left(2-x\right)=-3\)

\(\Leftrightarrow6x-9+4-2x=-3\)

\(\Leftrightarrow4x=2\)

hay \(x=\dfrac{1}{2}\)

\(3x+2\left(-2\right)^3=-\left(-2\right)^3\)

\(\Leftrightarrow3x+2\cdot\left(-8\right)=-8\)

\(\Leftrightarrow3x-16=-8\)

\(\Leftrightarrow3x=8\)

\(\Leftrightarrow x=\frac{8}{3}\)

4x-15=-75-x

\(\Leftrightarrow4x+x=-75+15\)

\(\Leftrightarrow5x=-60\)

\(\Leftrightarrow x=-12\)

3x + 2. (-2)³ = -(-2)³

3x + 2. (-8) = -(-8)

3x + (-16) = 8

3x = 8 + 16

3x = 24

x = 24 : 3

x = 8

Vậy x = 8

4x - 15 = -75 - x

4x + x = -75 + 15

5x = -60

x = (-60) : 5

x = -12

Vậy x = -12

Chúc bạn học tốt!!!

a) Ta có: \(36x^3-4x=0\)

\(\Leftrightarrow4x\left(9x^2-1\right)=0\)

\(\Leftrightarrow x\left(3x-1\right)\left(3x+1\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=\dfrac{1}{3}\\x=\dfrac{-1}{3}\end{matrix}\right.\)

b) Ta có: \(3x\left(x-2\right)+x-2=0\)

\(\Leftrightarrow\left(x-2\right)\left(3x+1\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=2\\x=\dfrac{-1}{3}\end{matrix}\right.\)

d) Ta có: \(x^2-6x-16=0\)

\(\Leftrightarrow\left(x-8\right)\left(x+2\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=8\\x=-2\end{matrix}\right.\)

e) Ta có: \(x^4-6x^2-7=0\)

\(\Leftrightarrow\left(x^2-7\right)\left(x^2+1\right)=0\)

\(\Leftrightarrow x\in\left\{\sqrt{7};-\sqrt{7}\right\}\)

\(a,\Rightarrow x^2+4x+25-x^2=3\\ \Rightarrow4x=-22\Rightarrow x=-\dfrac{11}{2}\\ b,\Rightarrow\left(2x-3-4x-3\right)\left(2x-3+4x+3\right)=0\\ \Rightarrow6x\left(-2x-6\right)=0\Rightarrow\left[{}\begin{matrix}x=-3\\x=0\end{matrix}\right.\)

a) 32 : (3.x - 2) = 8

3x - 2 = 32 : 8

3x - 2 = 4

3x = 4 + 2

3x = 6

x = 6 : 3

x = 2

b) 75 : (x - 18) = 25

x - 18 = 75 : 25

x - 18 = 3

x = 3 + 18

x = 21

c) (15 - 6.x) . 243 = 729

15 - 6x = 729 : 243

15 - 6x = 3

6x = 15 - 3

6x = 12

x = 12 : 6

x = 2

d) 4.(x - 12) + 9 = 17

4(x - 12) = 17 - 9

4(x - 12) = 8

x - 12 = 8 : 4

x - 12 = 2

x = 2 + 12

x = 14

e) 20 - 2.(x + 4) = 4

2(x + 4) = 20 - 4

2(x + 4) = 16

x + 4 = 16 : 2

x + 4 = 8

x = 8 : 2

x = 4

`32: ( 3xx x -2)=8`

`3xx x-2=32:8`

`3xx x-2=4`

`3 xx x=4+2`

`3xx x=6`

`x=6:3`

`x=2`

__

`75 : (x-18) =25`

`x-18=75:25`

`x-18= 3`

`x=3+18`

`x=21`

__

`(15-6 xx x ) xx 243 =729`

`15-6 xx x = 729 : 243`

`15-6 xx x = 3`

`6 xx x=15-3`

`6 xx x=12`

`x=12:6`

`x=2`

__

`4 xx (x-12)+9=17`

`4 xx (x-12)=17-9`

`4 xx (x-12)= 8`

`x-12=8:4`

`x-12=2`

`x=2+12`

`x=14`

__

`20-2xx(x+4)=4`

`2xx(x+4)=20-4`

`2xx(x+4)=16`

`x+4=16:2`

`x+4=8`

`x=8-4`

`x=4`

\(a,32:\left(3\times X-2\right)=8\\ 3\times X-2=32:8=4\\ 3\times X=4+2=6\\ X=\dfrac{6}{3}=2\\ Vậy:X=2\\ ---\\ b,75:\left(X-18\right)=25\\ X-18=75:25=3\\ X=3+18=21\\ Vậy:X=21\\ ---\\ c,\left(15-6\times X\right)\times243=729\\ 15-6\times X=729:243=3\\ 6\times X=15-3=12\\ X=\dfrac{12}{6}=2\\ Vậy:X=2\\ ---\\ d,4\times\left(X-12\right)+9=17\\ 4\times\left(X-12\right)=17-9=8\\ X-12=8:4=2\\ X=2+12=14\\ Vậy:X=14\\ ---\\ e,20-2\times\left(X+4+4\right)=4\\ 2\times\left(X+4\right)=20-4=16\\ X+4=16:2=8\\ X=8-4=4\\ Vậy:X=4\)