\(27^{13}=\left(3^3\right)^{13}=3^{39};243^8=\left(3^5\right)^8=3^{40};3^{39}< 3^{40}\Rightarrow27^{13}< 243^8\\ 125^{80}=\left(5^3\right)^{80}=5^{240};25^{118}=\left(5^2\right)^{118}=5^{236};5^{240}>5^{236}\Rightarrow125^{80}>25^{118}\)

\(27^{13}< 243^8;125^{80}>25^{118}\)

\(125^{80}=\left(5^3\right)^{80}=5^{240}\\ 25^{118}=\left(5^2\right)^{118}=5^{236}\)

Vì \(5^{240}>5^{236}\)nên \(125^{80}>25^{118}\)

Đáp án:

Đáp án:

2713 × 205 = 556165

Đáp án : C

Hợp chất giữa 2 nguyên tố là AlCl₃

=> M = 27 + 35.3 = 132

2713 x 205 = 556165

86472 : 24 = 3603

x : 24 = 35736

x = 35736 x 24

x = 857664

2713✖205=556165

86472:24=3603

x:24=35736

    x=35736✖24

     x=875664

24x35736=857664

vậy x=857664

a) Ta có \(\overline{2021ab}⋮31\Leftrightarrow202100+\overline{ab}⋮31\Leftrightarrow11+\overline{ab}⋮31\Leftrightarrow\overline{ab}\in\left\{20;51;82\right\}\).

Vậy..

a) Ta c󠯯¯¯¯¯¯¯¯¯¯¯¯¯¯¯2021ab⋮31⇔202100+¯¯¯¯¯ab⋮31⇔11+¯¯¯¯¯ab⋮31⇔¯¯¯¯¯ab∈{20;51;82}2021ab¯⋮31⇔202100+ab¯⋮31⇔11+ab¯⋮31⇔ab¯∈{20;51;82}.

Vậy.

372549   +   459521   =   832070

920460   -   510754   =   409706

2713   ×   205   =   556165

86472   ÷   24     =   3603