\(a, 4x^2-4y^2\)

\(= (4x-4y)(4x+4y)\)

\(b. x^2-xy+2x-2y\)

\(= (x^2-xy)+(2x-2y)\)

\(=x(x-y)+2(x-y)\)

\(=(x+2)(x-y)\)

\(c, 6x^2-7x+2\)

\(= 6x^2-4x-3x+2\)

\(=(6x^2-4x)-(3x-2)\)

\(= 2x(3x-2)-(3x-2)\)

\(=(3x-2)(2x-1)\)

1.

$4x^2y+5x^3-x^2y^2=x^2(4y+5x-y^2)$

2.

$5x(x-1)-3y(1-x)=5x(x-1)+3y(x-1)=(x-1)(5x+3y)$

3.

$4x^2-25=(2x)^2-5^2=(2x-5)(2x+5)$

4.

$6x-9-x^2=-(x^2-6x+9)=-(x-3)^2$

5.

$x^2+4y^2+4xy=x^2+2.x.2y+(2y)^2=(x+2y)^2$

6.

$\frac{1}{64}-27x^3=(\frac{1}{4})^3-(3x)^3$
$=(\frac{1}{4}-3x)(\frac{1}{16}+\frac{3x}{4}+9x^2)$
 

7.

$x^3-6x^2+12x-8=x^3-3.x^2.2+3.x.2^2-2^3$

$=(x-2)^3$
8.

$x^2-x-y^2-y=(x^2-y^2)-(x+y)=(x-y)(x+y)-(x+y)$

$=(x+y)(x-y-1)$

9.

$5x-5y+ax-ay=5(x-y)+a(x-y)$

$=(x-y)(5+a)$

a) Ta có: \(1+6x-6x^2-x^3\)

\(=\left(1-x\right)\left(x^2+x+1\right)+6x\left(1-x\right)\)

\(=\left(1-x\right)\left(x^2+7x+1\right)\)

b:Ta có: \(x^3-4x^2+8x-8\)

\(=\left(x-2\right)\left(x^2+2x+4\right)-4x\left(x-2\right)\)

\(=\left(x-2\right)\left(x^2-2x+4\right)\)

c: Ta có: \(x^3+2x^2+2x+1\)

\(=\left(x+1\right)\left(x^2-x+1\right)+2x\left(x+1\right)\)

\(=\left(x+1\right)\left(x^2+x+1\right)\)

d: Ta có: \(8x^3-12x^2+6x-1\)

\(=\left(2x\right)^3-3\cdot\left(2x\right)^2\cdot1+3\cdot2x\cdot1^2-1^3\)

\(=\left(2x-1\right)^3\)

\(6x^2-7x+2\)

\(=6x^2-3x-4x+2\)

\(=\left(6x^2-3x\right)-\left(4x-2\right)\)

\(=3x\left(2x-1\right)-2\left(2x-1\right)\)

\(=\left(2x-1\right)\left(3x-2\right)\)

\(=6x^2-3x-4x+2=\left(2x-1\right)\left(3x-2\right)\)

\(a,=\left(x-2\right)^2-y^2=\left(x-y-2\right)\left(x+y-2\right)\\ b,=4x^2\left(x^2+2x+1\right)=4x^2\left(x+1\right)^2\\ c,=xy^2\left(x^2-2xy+y^2\right)=xy^2\left(x-y\right)^2\\ d,=\left(x-y\right)\left(x+y\right)-7\left(x-y\right)=\left(x-y\right)\left(x+y-7\right)\\ e,=\left(5x-2y\right)\left(5x+2y\right)\\ f,=x^2+3x+4x+12=\left(x+3\right)\left(x+4\right)\\ i,=x^2+2x-7x-14=\left(x+2\right)\left(x-7\right)\)

a: =(x+6)(x-1)

n: \(=4x^4+36x^2+81-36x^2\)

\(=\left(2x^2+9-6x\right)\left(2x^2+9+6x\right)\)

a) $4x^2+4x+1$

$=(2x)^2+2\cdot2x\cdot1+1^2$

$=(2x+1)^2$

b) $x^2+6x-y^2+9$

$=(x^2+6x+9)-y^2$

$=(x^2+2\cdot x\cdot3+3^2)-y^2$

$=(x+3)^2-y^2$

$=(x+3-y)(x+3+y)$

$\text{#}Toru$

a: \(4x^2+4x+1\)

\(=\left(2x\right)^2+2\cdot2x\cdot1+1^2\)

\(=\left(2x+1\right)^2\)

b: \(x^2+6x-y^2+9\)

\(=\left(x^2+6x+9\right)-y^2\)

\(=\left(x+3\right)^2-y^2\)

\(=\left(x+3+y\right)\left(x+3-y\right)\)

a: \(7x-14y=7\left(x-2y\right)\)

b: \(4x^2-4x+1=\left(2x-1\right)^2\)

`@` `\text {Ans}`

`\downarrow`

`a)`

`6x^2 - 3xy`

`= 3x(2x - y)`

`b)`

Bạn ghi lại đầy đủ thông tin

`c)`

`x^2 - 5x + 6`

`= x^2 - 2x - 3x +6`

`= (x^2 - 2x) - (3x - 6)`

`= x(x - 2) - 3(x - 2)`

`= (x - 3)(x - 2)`

a: =3x*2x-3x*y

=3x(2x-y)

c: =x^2-2x-3x+6

=x(x-2)-3(x-2)

=(x-2)(x-3)

b: Bạn ghi đầy đủ đề nha bạn