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Những câu hỏi liên quan
IOI
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Nguyễn Lê Phước Thịnh
27 tháng 5 2022 lúc 0:04

1: \(\left(x^2+1\right)^2-4x\left(1-x^2\right)\)

\(=x^4+2x^2+1-4x+4x^3\)

\(=x^4+4x^3+2x^2-4x+1\)

\(=\left(x^2+2x-1\right)^2\)

2: \(\left(x^2-8\right)^2+36\)

\(=x^4-16x^2+64+36\)

\(=x^4-16x^2+100\)

\(=x^4+20x^2+100-36x^2\)

\(=\left(x^2+10\right)^2-\left(6x\right)^2\)

\(=\left(x^2+6x+10\right)\left(x^2-6x+10\right)\)

3: \(x^4+4=x^4+4x^2+4-4x^2\)

\(=\left(x^2+2\right)^2-4x^2\)

\(=\left(x^2+2x+2\right)\left(x^2-2x+2\right)\)

4: \(x^4+64=x^4+16x^2+64-16x^2\)

\(=\left(x^2+8\right)^2-16x^2\)

\(=\left(x^2-4x+8\right)\left(x^2+4x+8\right)\)

5: \(64x^4+1=64x^4+16x^2+1-16x^2\)

\(=\left(8x^2+1\right)^2-16x^2\)

\(=\left(8x^2-4x+1\right)\left(8x^2+4x+1\right)\)

Đoàn Nguyễn Ánh
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Nguyễn Tấn Phát
29 tháng 6 2019 lúc 13:58

a) \(x^2+12x+35\)

\(=x^2+5x+7x+35\)

\(=\left(x^2+5x\right)+\left(7x+35\right)\)

\(=x\left(x+5\right)+7\left(x+5\right)\)

\(=\left(x+5\right)\left(x+7\right)\)

b)\(x^2-x-56\)

\(=x^2+7x-8x-56\)

\(=\left(x^2+7x\right)-\left(8x+56\right)\)

\(=x\left(x+7\right)-8\left(x+7\right)\)

\(=\left(x+7\right)\left(x-8\right)\)

c)\(5x^2-x-4\)

\(=5x^2-5x+4x-4\)

\(=\left(5x^2-5x\right)+\left(4x-4\right)\)

\(=5x\left(x-1\right)+4\left(x-1\right)\)

\(=\left(x-1\right)\left(5x+4\right)\)

Nguyễn Văn Tuấn Anh
29 tháng 6 2019 lúc 14:41

TL:

a)\(x^2+5x+7x+35\) 

 =\(x\left(x+5\right)+7\left(x+5\right)\) 

=\(\left(x+7\right)\left(x+5\right)\) 

b) \(x^2-x-56\)

  =\(x^2+7x-8x-56\) 

=\(x\left(x+7\right)-8\left(x+7\right)\) 

=\(\left(x-8\right)\left(x+7\right)\) 

d)\(4x^4+1=\left(2x^2\right)^2+4x^2+1-4x^2\) 

=\(\left(2x^2+1\right)^2-4x^2\) 

=\(\left(2x^2+1+4x\right)\left(2x^2+1-4x\right)\)

.......................(tự lm)

hc tốt

nguyễn tuấn thảo
29 tháng 6 2019 lúc 15:06

\(4\times^4+81\)

\(=\left(2\times^2\right)^2+36\times^2+9^2-36\times^2\)

\(=\left(2\times^2+9\right)^2-36\times^2\)

\(=\left(2\times^2+9+36\times\right)\left(2\times^2+9-36\times\right)\)

tràn thị trúc oanh
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Nguyệt Huỳnh Thúy Minh
24 tháng 7 2017 lúc 11:09

a) x2-7x+6= (x-6)(x-1)

câu c,e , g tương tự nha bạn

b) x4+64= x4+16x2+64-16x2=(x2+8)2-16x2=(x2+8-4x)(x2+8+4x)

các câu còn lại cũng tượng tự nha bạn

Phan Thị Hương Ly
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T.Thùy Ninh
25 tháng 7 2017 lúc 17:05

\(a,x^2-7x+6=x^2-6x-x+6\)

\(=x\left(x-6\right)-\left(x-6\right)=\left(x-1\right)\left(x-6\right)\)

\(b,x^4+64=\left(x^4+16x^2+64\right)-16x^2\)

\(=\left(x^2+8\right)^2-\left(4x\right)^2=\left(x^2-4x+8\right)\left(x^2+4x+8\right)\)

\(c,x^2+12x+35=x^2+5x+7x+35\)

\(=x\left(x+5\right)+7\left(x+5\right)=\left(x+7\right)\left(x+5\right)\)

\(d,4x^4+1=\left(4x^4+4x^2+1\right)-4x^2\)

\(=\left(2x^2+1\right)-\left(2x\right)^2=\left(2x^2+2x+1\right)\left(2x^2-2x+1\right)\)

\(e,x^2-x-56=x^2-8x+7x-56\)

\(=x\left(x-8\right)+7\left(x-8\right)=\left(x+7\right)\left(x-8\right)\)

\(f,4x^2+81=\left(4x^4+36x^2+81\right)-36x^2\)

\(=\left(2x^2+9\right)^2-\left(6x\right)^2=\left(2x^2+6x+9\right)\left(2x^2-6x+9\right)\)

\(g,5x^2-x-4=5x^2-5x+4x-4\)

\(=5x\left(x-1\right)+4\left(x-1\right)=\left(5x+4\right)\left(x-1\right)\)

\(h,64x^4+y^4=\left(64x^4+16x^2y^2+y^4\right)-16x^2y^2\)

\(=\left(8x^2+y^2\right)^2-\left(4xy\right)^2=\left(8x^2+y^2+4xy\right)\left(8x^2+y^2-4xy\right)\)

Huy Thắng Nguyễn
25 tháng 7 2017 lúc 17:11

a) \(x^2-7x+6=x^2-6x-x+6\)

\(=x\left(x-6\right)-\left(x-6\right)\)

\(=\left(x-6\right)\left(x-1\right)\)

b) \(x^4+64=x^4+64+16x^2-16x^2\)

\(=\left(x^2+8\right)^2-\left(4x\right)^2\)

\(=\left(x^2+8-4x\right)\left(x^2+8+4x\right)\)

c) \(x^2+12x+35=x^2+5x+7x+35\)

\(=x\left(x+5\right)+7\left(x+5\right)\)

\(=\left(x+5\right)\left(x+7\right)\)

d) \(4x^4+1=4x^4+1+4x^2-4x^2\)

\(=\left(2x^2+1\right)^2-\left(2x\right)^2\)

\(=\left(2x^2+1-2x\right)\left(2x^2+1+2x\right)\)

e) \(x^2-x-56=x^2+7x-8x-56\)

\(=x\left(x+7\right)-8\left(x+7\right)\)

\(=\left(x+7\right)\left(x-8\right)\)

f) \(4x^4+81=4x^4+81+36x^2-36x^2\)

\(=\left(2x^2+9\right)^2-\left(6x\right)^2\)

\(=\left(2x^2+9-6x\right)\left(2x^2+9+6x\right)\)

g) \(5x^2-x-4=5x^2+4x-5x-4\)

\(=x\left(5x+4\right)-\left(5x+4\right)\)

\(=\left(5x+4\right)\left(x-1\right)\)

h) \(64x^4+y^4=64x^4+y^4+16x^2y^2-16x^2y^2\)

\(=\left(8x^2+y^2\right)^2-\left(4xy\right)^2\)

\(=\left(8x^2+y^2-4xy\right)\left(8x^2+y^2+4xy\right)\)

Nguyễn Ngọc Thanh Thảo
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Mimi
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An Nguyễn Bá
27 tháng 9 2017 lúc 19:46

a) x² - x - 56

b) x^4 + 64

c) 4x^4 + 81

d) x².+ 12x + 35

e) 5x² - x - 4

g) 4x^4 + 1

h) 64x^4 + y^4

a)\(x^2-x-56\)

\(=x^2-8x+7x-56\)

\(=\left(x^2-8x\right)+\left(7x-56\right)\)

\(=x\left(x-8\right)+7\left(x-8\right)\)

\(=\left(x-8\right)\left(x+7\right)\)

b)\(x^4+64\)

\(=\left(x^2\right)^2+8^2\)

\(=\left(x^2\right)^2+16x^2+8^2-16x^2\)

\(=\left(x^2+8\right)^2-\left(4x\right)^2\)

\(=\left(x^2+8-4x\right)\left(x^2+8+4x\right)\)

c)\(4x^4+81\)

\(=\left(2x^2\right)^2+9^2\)

\(=\left(2x^2\right)^2+36x^2+9^2-36x^2\)

\(=\left(2x^2+9\right)^2-\left(6x\right)^2\)

\(=\left(2x^2+9-6x\right)\left(2x^2+9+6x\right)\)

d)\(x^2+12x+35\)

\(=x^2+5x+7x+35\)

\(=\left(x^2+5x\right)+\left(7x+35\right)\)

\(=x\left(x+5\right)+7\left(x+5\right)\)

\(=\left(x+5\right)\left(x+7\right)\)

e)\(5x^2-x-4\)

\(=5x^2-5x+4x-4\)

\(=\left(5x^2-5x\right)+\left(4x-4\right)\)

\(=5x\left(x-1\right)+4\left(x-1\right)\)

\(=\left(x-1\right)\left(5x+4\right)\)

g)\(4x^4+1\)

\(=\left(2x^2\right)^2+1^2\)

\(=\left(2x^2\right)^2+4x^2+1^2-4x^2\)

\(=\left(2x^2+1\right)^2-4x^2\)

\(=\left(2x^2+1-4x\right)\left(2x^2+1+4x\right)\)

h)\(64x^4+y^4\)

\(=\left(8x^2\right)^2+\left(y^2\right)^2\)

\(=\left(8x^2\right)^2+16x^2y^2+\left(y^2\right)^2-16x^2y^2\)

\(=\left(8x^2+y^2\right)^2-\left(4xy\right)^2\)

\(=\left(8x^2+y^2-4xy\right)\left(8x^2+y^2+4xy\right)\)

Tsukino Usagi
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Trần Việt Linh
24 tháng 10 2016 lúc 12:43

Mink nghĩ đề này là phân tích đa thức thành nhân tử chứ k phải tìm x^^

a) \(x^2-x-56=x^2-8x+7x-56=x\left(x-8\right)+7\left(x-8\right)=\left(x+7\right)\left(x-8\right)\)

b) \(4x^4+1=\left(4x^4+4x^2+1\right)-4x^2=\left(2x^2+1\right)^2-\left(2x\right)^2\)

\(\left(2x^2+1-2x\right)\left(2x^2+1+2x\right)\)

c) \(5x^2-x-4=5x^2-5x+4x-4=5x\left(x-1\right)+4\left(x-1\right)=\left(x-1\right)\left(5x+4\right)\)

d) \(4x^4+81=\left(4x^4+36x^2+81\right)-36x^2=\left(2x^2+9\right)^2-\left(6x\right)^2\)

\(=\left(2x^2+9+6x\right)\left(2x^2+9-6x\right)\)

e) \(64x^4+y^4=\left(64x^4+16x^2y^2+y^4\right)-\left(4xy\right)^2=\left(8x^2+y^2\right)^2-\left(4xy\right)^2\)

\(=\left(8x^2+y^2-4xy\right)\left(8x^2+y^2+4xy\right)\)

 

Lightning Farron
24 tháng 10 2016 lúc 12:59

a)\(x^2-x-56\)

\(=x^2+7x-8x-56\)

\(=x\left(x+7\right)-8\left(x+7\right)\)

\(=\left(x-8\right)\left(x+7\right)\)

b)\(4x^4+1\)

\(=\left(2x+1\right)^2-4x^2\)

\(=\left(2x^2-2x+1\right)\left(2x^2+2x+1\right)\)

c)\(5x^2-x-4\)

\(=5x^2+4x-5x-4\)

\(=x\left(5x+4\right)-\left(5x+4\right)\)

\(=\left(x-1\right)\left(5x+4\right)\)

d)\(4x^4+81\)

\(=\left(2x^2\right)^2+9^2+36x^2-36x^2\)

\(=\left(2x^2+9\right)^2-36x^2\)

\(=\left(2x^2-6x+9\right)\left(2x^2+6x+9\right)\)

e)\(64x^4+y^4\)

\(=\left(8x^2\right)^2+y^4+16x^2y^2-16x^2y^2\)

\(=\left(8x^2+y^2\right)^2-\left(4xy\right)^2\)

\(=\left(8x^2+y^2-4xy\right)\left(8x^2+y^2+4xy\right)\)

 

 

Tĩnh╰︵╯
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Lê Tự Nhân
26 tháng 12 2018 lúc 21:16

tự làm

Thái Thùy Linh
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Nguyễn Thị Yến Như
16 tháng 10 2016 lúc 15:24

hoa mắt chóng mặt