Tính
a)\(\left(x^4+2x^3+10x-25\right):\left(x^2+5\right)\)
b) \(\left(3x^4-8x^3-10x^2+8x-5\right):\left(3x^2-2x+1\right)\)
Thực hiện phép tính
a, \(\left(3x^4-8x^3-10x^2+8x-5\right):\left(3x^2-2x+1\right)\)
b,\(\left(2x^3-9x^2+19x-15\right):\left(x^2-3x+5\right)\)
c,\(\left(8x^3-y^3\right)\left(4x^2-y^2\right):\left(2x+y\right)\left(4x^2-4xy+y^2\right)\)
\(\frac{3x^4-8x^3-10x^2+8x-5}{3x^2-2x+1}\)
\(=\frac{x^2\left(3x^2-2x+1\right)-2x\left(3x^2-2x+1\right)-5\left(3x^2-2x+1\right)}{3x^2-2x+1}\)
\(=\frac{\left(3x^2-2x+1\right)\cdot\left(x^2-2x-5\right)}{3x^2-2x+1}\)
\(=x^2-2x-5\)
\(\frac{2x^3-9x^2+19x-15}{x^2-3x+5}\)
\(=\frac{2x\left(x^2-3x+5\right)-3\left(x^2-3x+5\right)}{x^2-3x+5}\)
\(=\frac{\left(x^2-3x+5\right)\left(2x-3\right)}{x^2-3x+5}\)
\(=2x-3\)
\(\frac{\left(8x^3-y^3\right)\left(4x^2-y^2\right)}{\left(2x+y\right)\left(4x^2-4xy+y^2\right)}\)
\(=\frac{\left(2x-y\right)\left(4x^2+2xy+y^2\right)\left(2x-y\right)\left(2x+y\right)}{\left(2x+y\right)\left(2x-y\right)^2}\)
\(=4x^2+2xy+y^2\)
tính
\(\left(x^2-3x+2\right)\left(-2x-5\right)\)
\(\left(3x^4-8x^3-10x^2+8x-5\right):\left(3x^2-2x+1\right)\)
a)\(\left(x^2-3x+2\right)\left(-2x-5\right)=-2x^3-5x^2+6x^2+15x-4x-10=-2x^3+x^2+11x-10\)
b) \(\left(3x^4-8x^3-10x^2+8x-5\right):\left(3x^2-2x+1\right)=x^2-2x-5\)
Thực hiện phép tính
a,\(\left(3x^4-8x^3-10x^2+8x-5\right):\left(3x^2-2x+1\right)\)
b,\(\left(2x^3-9x^2+19x-15\right):\left(x^2-3x+5\right)\)
c,\(\left(8x^3-y^3\right)\left(4x^2-y^2\right):\left(2x+y\right)\left(4x^2-4xy+y^2\right)\)
\(\left(3x^4-8x^3-5+8x-10x^2\right):\left(-2x^2+1+3x\right)\)
\(\left(3x^4-8x^3-5+8x-10x^2\right):\left(-2x^2+1+3x\right)\)
\(\left(1\right)\sqrt{x^2-9}-2\sqrt{x-3}=0\)
\(\left(2\right)\sqrt{4x+1}-\sqrt{3x-4}=1\)
\(\left(3\right)\sqrt{x^2-10x+25}=5-x\)
\(\left(4\right)\sqrt{x^2-8x+16}=x+2\)
1:
\(\Leftrightarrow\sqrt{x-3}\left(\sqrt{x+3}-2\right)=0\)
=>x-3=0 hoặc \(\sqrt{x+3}=2\)
=>x=3 hoặc x+3=4
=>x=1(loại) hoặc x=3(nhận)
2:
\(\Leftrightarrow\left(\sqrt{4x+1}-\sqrt{3x-4}\right)^2=1\)
=>\(4x-1+3x-4-2\sqrt{\left(4x+1\right)\left(3x-4\right)}=1\)
=>\(\sqrt{4\left(4x+1\right)\left(3x-4\right)}=7x-6\)
=>4(12x^2-16x+3x-4)=(7x-6)^2
=>49x^2-84x+36=48x^2-52x-16
=>-84x+36=-52x-16
=>-32x=-52
=>x=13/8
3: =>\(\sqrt{\left(x-5\right)^2}=5-x\)
=>|x-5|=5-x
=>x-5<=0
=>x<=5
4: \(\Leftrightarrow\left|x-4\right|=x+2\)
=>\(\left\{{}\begin{matrix}x>=-2\\\left(x-4\right)^2=\left(x+2\right)^2\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x>=-2\\x^2-8x+16=x^2+4x+4\end{matrix}\right.\)
=>x>=-2 và -8x+16=4x+4
=>x=1
Giải các bpt sau
a, \(\left(2x-3\right)\left(3x-4\right)\left(5x+2\right)>0\)
b, \(25-16x^2>8x^2-10x\)
c, \(\frac{4x\left(3x+2\right)}{2x+5}>0\)
d, \(\frac{2x-5}{3x+2}\le\frac{3x+2}{2x-5}\)
a/ \(\left(2x-3\right)\left(3x-4\right)\left(5x+2\right)>0\)
\(\Rightarrow\left[{}\begin{matrix}-\frac{2}{3}< x< \frac{4}{3}\\x>\frac{3}{2}\end{matrix}\right.\)
b/ \(\Leftrightarrow24x^2-10x-25< 0\)
\(\Rightarrow-\frac{5}{6}< x< \frac{5}{4}\)
c/ \(\frac{4x\left(3x+2\right)}{2x+5}>0\Rightarrow\left[{}\begin{matrix}-\frac{5}{2}< x< -\frac{2}{3}\\x>0\end{matrix}\right.\)
d/ \(\Leftrightarrow\frac{3x+2}{2x-5}-\frac{2x-5}{3x+2}\ge0\)
\(\Leftrightarrow\frac{\left(3x+2\right)^2-\left(2x-5\right)^2}{\left(2x-5\right)\left(3x+2\right)}\ge0\)
\(\Leftrightarrow\frac{\left(5x-2\right)\left(x+7\right)}{\left(2x-5\right)\left(3x+2\right)}\ge0\Rightarrow\left[{}\begin{matrix}x\le-7\\-\frac{2}{3}< x\le\frac{2}{5}\\x>\frac{5}{2}\end{matrix}\right.\)
Tìm x, biết :
a, \(\left(3x+2\right).\left(6x-2\right)-\left(9x-2\right).\left(2x+1\right)=24\)
b, \(\left(4x+3\right)\left(3x-2\right)-\left(6x-1\right)\left(2x+3\right)=16\)
c, \(\left(5x-2\right)\left(4x+5\right)+\left(10x-7\right)\left(5-2x\right)=12\)
d, \(6x\left(3-4x\right)+8x\left(3x-2\right)=16\)
Cho 2 đa thức:
\(A\left(x\right)=-5x^3+3x^4+\frac{5}{7}-8x^2-10x\)
\(B\left(x\right)=-2x^4-\frac{2}{7}+7x^2+8x^3+6x\)
1) Hãy sắp xếp các hạng tử của mỗi đa thức trên theo lũy thừa giảm dần của biến
2) Tính \(A\left(x\right)+B\left(x\right)\)và \(A\left(x\right)-B\left(x\right)\)
1) \(A\left(x\right)=-5x^3+3x^4+\frac{5}{7}-8x^2-10x\)
\(A\left(x\right)=3x^4-5x^3-8x^2-10x+\frac{5}{7}\)
\(B\left(x\right)=-2x^4-\frac{2}{7}+7x^2+8x^3+6x\)
\(B\left(x\right)=-2x^4+8x^3+7x^2+6x-\frac{2}{7}\)
2) \(A\left(x\right)=3x^4-5x^3-8x^2-10x+\frac{5}{7}\)
+
\(B\left(x\right)=-2x^4+8x^3+7x^2+6x-\frac{2}{7}\)
\(A\left(x\right)+B\left(x\right)=x^4+3x^3-x^2-4x+\frac{3}{7}\)
\(A\left(x\right)=3x^4-5x^3-8x^2-10x+\frac{5}{7}\)
-
\(B\left(x\right)=-2x^4+8x^3+7x^2+6x-\frac{2}{7}\)
\(A\left(x\right)-B\left(x\right)=5x^4-13x^3-15x^2-16x+1\)