5(x+7)-10=2³.5

5(x+7)-10=8.5

5(x+7)-10=45

5(x+7)=55

x+7=\(\dfrac{55}{5}\)=11  =>x=11-7=3

Ta có: \(5\left(x+7\right)-10=2^3\cdot5\)

\(\Leftrightarrow5\left(x+7\right)=50\)

\(\Leftrightarrow x+7=10\)

hay x=3

a) \(5\left(x+7\right)-10=2^3\cdot5\)

\(\Rightarrow5\left(x+7\right)-10=40\)

\(\Rightarrow5\left(x+7\right)=40+10\)

\(\Rightarrow x+7=\dfrac{50}{5}\)

\(\Rightarrow x+7=10\)

\(\Rightarrow x=10-7\)

\(\Rightarrow x=3\)

b) \(9x-2\cdot3^2=3^4\)

\(\Rightarrow9x-18=81\)

\(\Rightarrow9x=81+18\)

\(\Rightarrow9x=99\)

\(\Rightarrow x=\dfrac{99}{9}\)

\(\Rightarrow x=11\)

c) \(5^{25}\cdot5^{x-1}=5^{25}\)

\(\Rightarrow5^{x-1}=5^{25}:5^{25}\)

\(\Rightarrow5^{x-1}=1\)

\(\Rightarrow5^{x-1}=5^0\)

\(\Rightarrow x-1=0\)

\(\Rightarrow x=1\)

a) 5(�+7)−10=23⋅55(x+7)−10=23⋅5

$\Rightarrow 5\left(x+7\right)-10=40$

$\Rightarrow 5\left(x+7\right)=40+10$

⇒�+7=505⇒x+7=550​

$\Rightarrow x+7=10$

$\Rightarrow x=10-7$

$\Rightarrow x=3$

b) 9�−2⋅32=349x−2⋅32=34

$\Rightarrow 9x-18=81$

$\Rightarrow 9x=81+18$

$\Rightarrow 9x=99$

⇒�=999⇒x=999​

$\Rightarrow x=11$

c) 525⋅5�−1=525525⋅5x−1=525

⇒5�−1=525:525⇒5x−1=525:525

⇒5�−1=1⇒5x−1=1

$\Rightarrow$

4(x - 5) - 2³ = 2⁴ . 3

4(x - 5) - 8   = 48

4(x - 5)        = 48 + 8 

4(x - 5)         = 56

   x - 5          = 56 : 4

   x - 5          = 14

   x                = 14 + 5

   x                 = 19

Vậy x = 19

4( x - 5 ) - 2^3 = 2^4 . 3

4( x - 5 ) - 8 = 16 . 3

4( x - 5 ) - 8 = 48

4( x - 5 ) = 48 + 8

4( x - 5 ) = 56

x - 5 = 56 : 4

x - 5 = 14

x = 14 + 5

x = 19

Ta có: \(4\left(x-5\right)-2^3=2^4\cdot3\)

\(\Leftrightarrow4\left(x-5\right)=56\)

\(\Leftrightarrow x-5=14\)

hay x=19

`4(x-5)-2^3=2^{4}.3`

`=>4(x-5)-8=16.3=48`

`=>4(x-5)=48+8=56`

`=>x-5=56:4=14`

`=>x=19`

Vậy `x=19`

4.(x-5)-2³=2⁴.3

4.(x-5)-8=16.3

4.(x-5)-8=48

4.(x-5)=48+8

4.(x-5)=56

x-5=56:4

x-5=14

x=14+5

x=19

     4 (x - 5) - 2³ = 2⁴*3

=> 4 (x - 5) - 2³ = 16*3 = 48

=> 4 (x - 5) = 48 + 2³ = 48 + 8 = 56

=> x - 5 = 56/4 = 14

=> x = 14 + 5 = 19

 Vậy x = 19

a: x chia hết cho 4;5;10

nên \(x\in BC\left(4;5;10\right)\)

mà 10<=x<50

nên x=40

b: x=33

a: =>4/7<x<23/6

hay \(x\in\left\{1;2;3\right\}\)

b: =>19/10<x<27/5

hay \(x\in\left\{2;3;4;5\right\}\)

=>7/15<x<20/15=4/3

=>x=1

Ta có : 4/15 : 4/7< x > 2/5 x 10/3                                                                                           

Nên:  7/15   < x >     4/3                                                                                                       

Vậy số tự nhiên x là 1

\(\dfrac{4}{15}:\dfrac{4}{7}< x< \dfrac{2}{5}\times\dfrac{10}{3}\\ \dfrac{7}{15}< x< \dfrac{4}{3}\\ x=1\)

x=1. Trên violympic lớp 6 vòng 7. Chác chắn luôn đó. Nhớ tick mình nha

[(10 + x).2 + 5] : 3 - 2 = 7

[(10 + x).2 + 5] = 7 + 2 = 9

(10 + x).2+5 = 9.3 = 27

(10 + x).2 = 27 - 5 = 22

10 + x = 22 : 2 = 11

x = 11 - 10 = 1

a. 0; 1; 2; 3; 4.

b. 8; 9

c. 10

d. Không có số tự nhiên nào.