c) ( 2x - 1)6 = 642
2x.2x+3=642:25
\(2^x.2^{x+3}=64^2:2^5\)
\(2^x.2^x.2^3=2^{12}:2^5\)
\(2^x.\left(1+8\right)=2^7\)
\(2^x.9=2^7\)
\(\Rightarrow x=\varnothing\)
\(2^{2x+3}=64^2:2^5\)
\(\Leftrightarrow2^{2x+3}=2^7\)
hay x=2
\(2^x.2^{x+3}=64^2:2^5\)
\(\Leftrightarrow\)\(2^x.2^{x+3}=128\)
\(\Leftrightarrow\)\(2^x.2^{x+3}=2^7\)
\(\Leftrightarrow\)\(x+x+3=7\)
\(\Leftrightarrow\)\(x=2\)
Tính: 2 . 2^2x + 4^3 . 2^2x = 642
Tính: 642 x (30 -6)
642 x (30 -6)
= 642 x 30 - 642 x 6
= 19260 - 3852 = 15408
x:6+12 948=15 642
X : 6 + 12 948 = 15 642
X : 6 = 15 642 - 12 948
X : 6 = 2694
X = 2694 x 6
X = 16164
giúp mình giải mấy phương trình này với
x2-4y2=1
x4-2x2-100x-642=0
x2 - 4y2 =1
<=>x-2y=1
hoặcx+2y=1
<=>x=1+2y
hoăcx=1-2y=>1+2y=1-2y
<=>4y = 0 <=> y=0=>x=1
1. Phân tích các đa thức sau thành phân tử
8xy2+24x2y-32x3y2
x2-16x-y2+64
2. Tìm x biết
(x-4)22-(12x+x2)=6
Bài 1:
a) \(8xy^2+24x^2y-32x^3y^2=8xy\left(y+3x-4x^2y\right)\)
b) \(x^2-16x-y^2+64=\left(x-8\right)^2-y^2=\left(x-8-y\right)\left(x-8+y\right)\)
Bài 2:
\(\left(x-4\right)^2-\left(12x+x^2\right)=6\)
\(\Rightarrow x^2-8x+16-12x-x^2=6\)
\(\Rightarrow20x=10\Rightarrow x=\dfrac{1}{2}\)
\(1,\\ =8xy\left(y+3x-4x^2y\right)\\ =\left(x-8\right)^2-y^2=\left(x-y-8\right)\left(x+y-8\right)\)
\(2,\Leftrightarrow x^2-8x+16-12x-x^2=6\\ \Leftrightarrow-20x=-10\\ \Leftrightarrow x=2\)
Tính:
a)
6 × 2 12 : 6 12 : 2 | 6 × 7 42 : 6 42 : 7 | 6 × 9 54 : 6 54 : 9 |
b)
24 g : 6
60 cm : 6
36 : 6
a)
6 × 2 = 12 12 : 6 = 2 12 : 2 = 6 | 6 × 7 = 42 42 : 6 = 7 42 : 7 = 6 | 6 × 9 = 54 54 : 6 = 9 54 : 9 = 6 |
b)
24 g : 6 = 4 g
60 cm : 6 = 10 cm
36 l : 6 = 6 l
135 × (20 + 3) 642 × (30 − 6)
427 × (10 + 8) 287 × (40 − 8)
135 x (20 + 3)
= 135 x 20 + 135 x 3
= 2700 + 405
= 3105.
427 x (10 + 8)
= 427 x 10 + 427 x 8
= 4270 + 3416
= 7686.
642 x (30 - 6)
= 642 x 30 - 642 x 6
= 19260 - 1452
= 18808.
287 x (40 - 8)
= 287 x 40 - 287 x 8
= 11480 - 2296
= 9184.
135x(20+3) 642 x (30-6)
= 135 x 20 + 135 x 3 = 642 x 30 - 642 x 6
= 2700+405 = 19 260 - 3852
= 3105 =15 408
427 x ( 10+8) 287 x (40 - 8)
= 427 x 10 + 427 x 8 = 287 x 40 - 287 x 8
= 4270 + 3416 =11 480 - 2296
=7686 = 9184
Two iPhone 6 Plus mobiles cost $642. How much do five iPhone 6 Plus mobiles cost?
five iphone 6 plus cost is : 642 x 5 = 3210 ( $ )
answer : 3210$
k for me
Bài giải
one iphones 6 plus run out of $ are :
642 / 2 = 321($)
five iphones 6plus out of the $ are:
321 x 5 = 1605($)
Answer: 1605$
One iPhone 6 Plus cost: 642 : 2 = 321 ($)
Five iPhone 6 Plus cost: 321 x 5 = 1605 ($)
Answer: $1605
tim x biet
a)190+x=2009
b)(x-2)*7=642
c)x:7=642
a) 190 + x = 2009
x = 2009 - 190
x = 1819
b) (x - 2) x 7 = 642
x- 2 = 642 : 7
x - 2 = \(\frac{642}{7}\)
x = \(\frac{642}{7}\) +2
x = \(\frac{656}{7}\)
c) x : 7 = 642
x = 642 x 7
x = 4494
a)190+x=2009
x=2009-190
x=1819. Vậy x=1819
b)(x-2)*7=642
x-2=642/7
x-2=91,7 .......
nói chung đề câu này sai
c)x:7=642
x=642*7
x=4494
a.190+x=2009
=>x=2009-190
=>x=1819
b.(x-2).7=642
=>x-2=642:7
=>x=642/7+2
=>x=656/7
c.x:7=642
=>x=642.7
=>x=4494