\(\left(2x-1\right)^6=64^2\)
\(\Leftrightarrow\left(2x-1\right)^6=4^6\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}2x-1=4\\2x-1=-4\end{array}\right.\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}x=\frac{5}{2}\\x=-\frac{3}{2}\end{array}\right.\)
\(\left(2x-1\right)^6=64^2\)
\(\Rightarrow\left(2x-1\right)^6=4^6\)
\(\Rightarrow2x-1=\pm4\)
+) \(2x-1=4\Rightarrow x=\frac{5}{2}\)
+) \(2x-1=-4\Rightarrow x=\frac{-3}{2}\)
Vậy \(x=\frac{5}{2}\) hoặc \(x=\frac{-3}{2}\)
(2x-1)6 = 642
<=> (2x-1)6 = 46
<=> 2x -1 = 4
<=> 2x = 5
<=> x = \(\frac{5}{2}\)