đề có lộn ko banj

\(\dfrac{2727}{3131}=\dfrac{27.101}{31.101}=\dfrac{27}{31}\)

⇒\(\dfrac{27}{31}=\dfrac{2727}{3131}\)

\(\dfrac{27}{31}=\dfrac{27\times101}{31\times101}=\dfrac{2727}{3131}\)

a) Có 143/363 = 13/33
=> 13/33 = 143/363
b)Có 12/27 = 4/9
         1212/2727 = 4/9
=> 12/27 = 1212/2727 

a) Ta có:   \(\dfrac{13}{33}=\dfrac{143}{363}\) 

     Mà \(\dfrac{143}{363}=\dfrac{143}{363}\)

     Vậy \(\dfrac{13}{33}=\dfrac{143}{363}\)

b) Ta có: \(\dfrac{12}{27}=\dfrac{1212}{2727}\)

     Mà \(\dfrac{1212}{2727}=\dfrac{1212}{2727}\)

     Vậy \(\dfrac{12}{27}=\dfrac{1212}{2727}\)

a) Ta có : 

\(\dfrac{13}{33}=\dfrac{13.11}{33.11}=\dfrac{143}{363}\) 

\(\Rightarrow\dfrac{13}{33}=\dfrac{143}{363}\) ( điều phải chứng minh ) 

Vậy ...... 

b) Ta có : 

\(\dfrac{1212}{2727}=\dfrac{1212:101}{2727:101}=\dfrac{12}{27}\) 

\(\Rightarrow\dfrac{1212}{2727}=\dfrac{12}{27}\) ( điều phải chứng minh ) 

Vậy ...... 

Chúc bạn học tốt 

 \(\dfrac{143}{363}\) = \(\dfrac{143:11}{363:11}\) = \(\dfrac{13}{33}\) (đpcm)

\(\dfrac{1212}{2727}\) = \(\dfrac{1212:101}{2727:101}\) = \(\dfrac{12}{27}\) (đpcm)

\(\dfrac{13}{33}\)  và \(\dfrac{143}{363}\)

\(\dfrac{13}{33}=\dfrac{13\times11}{33\times11}=\dfrac{143}{363}\)

\(\dfrac{143}{363}=\dfrac{143\times1}{363\times1}=\dfrac{143}{363}\)

\(\dfrac{1212}{2727}\)  và \(\dfrac{12}{27}\)

\(\dfrac{12}{27}=\dfrac{12\times101}{27\times101}=\dfrac{1212}{2727}\)

\(\dfrac{1212}{2727}=\dfrac{1212\times1}{2727\times1}=\dfrac{1212}{2727}\)

đó là toán mà

\(\frac{27}{31}=\frac{2727}{3131}=\frac{272727}{313131}\)

\(\frac{27}{31}=\frac{27.101}{31.101}=\frac{27.10101}{31.10101}\)

\(\frac{27}{31}=\frac{27}{31}=\frac{27}{31}\)

\(\Rightarrow\frac{27}{31}=\frac{2727}{3131}=\frac{272727}{313131}\)

\(\frac{27}{31}=\frac{2727}{3131}=\frac{272727}{313131}\)

\(\frac{27}{31}=\frac{27\cdot101}{31\cdot101}=\frac{27\cdot10101}{31\cdot10101}\)

\(\Rightarrow\frac{27}{31}=\frac{2727}{3131}=\frac{272727}{313131}\)

`#3107.101107`

`a)`

Ta có:

\(\dfrac{2727}{3131}=\dfrac{2727\div27}{3131\div31}=\dfrac{27}{31}\)

Vì \(\dfrac{27}{31}=\dfrac{27}{31}\)

\(\Rightarrow\dfrac{27}{31}=\dfrac{2727}{3131}\)

`b)`

Ta có:

\(\dfrac{11}{31}=1-\dfrac{20}{31}=1-\dfrac{200}{310}\)

\(\dfrac{111}{311}=1-\dfrac{200}{311}\)

Vì \(\dfrac{200}{310}>\dfrac{200}{311}\)

\(\Rightarrow1-\dfrac{200}{310}< 1-\dfrac{200}{311}\)

\(\Rightarrow\dfrac{11}{31}< \dfrac{111}{311}.\)

27/31 = 2727/3131

11/31 bé hơn 111/311

a   x=5-3

x=2

b   15x+11=101

    15x=101-11

    15x=90

       x = 90:15

      x  = 6

c    x+2=0

    x=0-2

  x=-2

a ) 3+x=5

=> x = 5 - 3

=> x = 2

Vậy x = 2

b ) 5x + 1 = 2727 : 27

=> 5x + 1 = 101

=> 5x = 101 - 1

=> 5x = 100

=> x = 100 : 5

= > x = 20

Vậy x = 20

c ) /x+2/ = 0

=> x+2 = 0

=> x = 0 - 2

=> x = -2

Vậy x = -2

tìm x:

a) 3 + x =5

x = 5 - 3

x = 2

b) 5x+ 1 = 2727 : 27

5x + 1 = 101

5x = 101 - 1

5x = 100

x = 100 : 5

x = 20

27/31<2727/3131

11/31<111/311